I am formatting the current date in an AIR Mobile project in the following way:
var dateFormatter:DateTimeFormatter = new DateTimeFormatter( Capabilities.language );
dateFormatter.setDateTimePattern("EEEE d");
trace(dateFormatter.format(date));
This works perfect, but since I have a width restriction (only 12 characters can be displayed) the problem is that in certain languages like Portuguese, the EEEE format returns Segunda-feria meaning that the number of characters would be 16 (including day number).
Is there a way to put conditional formatting meaning that EEEE cannot exceed more than 10 characters? (i.e: use EEEE always but if it exceeds more than 12 characters display EEE)
Try something like this:
var str_tmp: String ="";
var dateFormatter :DateTimeFormatter = new DateTimeFormatter( Capabilities.language );
dateFormatter.setDateTimePattern("EEEE d");
//# check for larger than 12 chars
str_tmp = dateFormatter.format(date);
if ( str_tmp.length > 12 ) { dateFormatter.setDateTimePattern("EEE d"); }
trace(dateFormatter.format(date));
Related
I have gotten amazing help here today!
I'm trying to do something else. I have a numbered list of questions in a Google Doc, and I'd like to replace the numbers with something else.
For example, I'd like to replace the numbers in a list such as:
The Earth is closest to the Sun in which month of the year?
~July
~June
=January
~March
~September
In Australia (in the Southern Hemisphere), when are the days the shortest and the nights the longest?
~in late December
~in late March
=in late June
~in late April
~days and nights are pretty much the same length throughout the year in Australia
With:
::Q09:: The Earth is closest to the Sun in which month of the year?
~July
~June
=January
~March
~September
::Q11:: In Australia (in the Southern Hemisphere), when are the days the shortest and the nights the longest?
~in late December
~in late March
=in late June
~in late April
~days and nights are pretty much the same length throughout the year in Australia
I've tried using suggestions from previous posts but have come up only with things such as the following, which doesn't seem to work.
Thank you for being here!!!
function questionName2(){
var body = DocumentApp.getActiveDocument().getBody();
var text = body.editAsText();
var pattern = "^[1-9]";
var found = body.findText(pattern);
var matchPosition = found.getStartOffset();
while(found){
text.insertText(matchPosition,'::Q0');
found = body.findText(pattern, found);
}
}
Regular expressions
Text.findText(searchPattern) uses a string that will be parsed as a regular expression using Google's RE2 library for the searchPattern. Using a string in this way requires we add an extra backslash whenever we are removing special meaning from a character, such as matching the period after the question number, or using a character matching set like \d for digits.
^\\s*\\d+?\\. will match a set of digits, of any non-zero length, that begin a line, with any length (including zero) of leading white space. \d is for digits, + is one or more, and the combination +? makes the match lazy. The lazy part is not required here, but it's my habit to default to lazy to avoid bugs. An alternative would be \d{1,2} to specifically match 1 to 2 digits.
To extract just the digits from the matched text, we can use a JavaScript RegExp object. Unlike the Doc regular expression, this regular expression will not require extra backslashes and will allow us to use capture groups using parentheses.
^\s*(\d+?)\. is almost the same as above, except no extraneous slashes and we will now "save" the digits so we can use them in our replacement string. We mark what we want to save using parentheses. Because this will be a normal JavaScript regular expression literal, we will wrap the whole thing in slashes: /^\s*(\d+?)\./, but the starting and ending / are just to indicate this is a RegExp literal.
text elements and text strings
Text.findText can return more than just the exact match we asked for: it returns the entire element that contains the text plus indices for what the regular expression matched. In order to perform search and replace with capture groups, we have to use the indices to delete the old text and then insert the new text.
The following assignments get us all the data we need to do the search and replace: first the element, then the start & stop indices, and finally extracting the matched text string using slice (note that slice uses an exclusive end, whereas the Doc API uses an inclusive end, hence the +1).
var found = DocumentApp.getActiveDocument().getBody().findText(pattern);
var matchStart = found.getStartOffset();
var matchEnd = found.getEndOffsetInclusive();
var matchElement = found.getElement().asText();
var matchText = matchElement.getText().slice(matchStart, matchEnd + 1);
Caveats
As Tanaike pointed out in the comments, this assumes the numbering is not List Items, which automatically generates numbers, but numbers you typed in manually. If you are using an automatically generated list of numbers, the API does not allow you to edit the format of the numbering.
This answer also assumes that in the example, when you mapped "9." to "::Q09::" and "10." to "::Q11::", that the mapping of 10 to 11 was a typo. If this was intended, please update the question to clarify the rules for why the numbering might change.
Also assumed is that the numbers are supposed to be less than 100, given the example zero padding of "Q09". The example should be flexible enough to allow you to update this to a different padding scheme if needed.
Full example
Since the question did not use any V8 features, this assumes the older Rhino environment.
/**
* Replaces "1." with "::Q01::"
*/
function updateQuestionNumbering(){
var text = DocumentApp.getActiveDocument().getBody();
var pattern = "^\\s*\\d+?\\.";
var found = text.findText(pattern);
while(found){
var matchStart = found.getStartOffset();
var matchEnd = found.getEndOffsetInclusive();
var matchElement = found.getElement().asText();
var matchText = matchElement.getText().slice(matchStart, matchEnd + 1);
matchElement.deleteText(matchStart, matchEnd);
matchElement.insertText(matchStart, matchText.replace(/^\s*(\d+?)\./, replacer));
found = text.findText(pattern, found);
}
/**
* #param {string} _ - full match (ignored)
* #param {string} number - the sequence of digits matched
*/
function replacer(_, number) {
return "::Q" + padStart(number, 2, "0") + "::";
}
// use String.prototype.padStart() in V8 environment
// above usage would become `number.padStart(2, "0")`
function padStart(string, targetLength, padString) {
while (string.length < targetLength) string = padString + string;
return string;
}
}
I'm trying to create a spline chart using this CSV:
slave_id,date,time,rtc_temp,temp1,temp2,temp3
1,2017/12/26,16:42:59,21,11.50,13.13,5.88
2,2017/12/26,16:43:29,21,14.13,20.63,99.99
1,2017/12/26,16:44:00,21,11.50,13.13,5.88
2,2017/12/26,16:44:30,21,14.13,20.63,99.99
1,2017/12/26,16:45:01,21,11.50,13.13,5.88
2,2017/12/26,16:45:31,21,14.13,20.63,99.99
1,2017/12/26,16:46:02,21,11.50,13.13,5.88
2,2017/12/26,16:46:32,21,14.13,20.63,99.99
As you can see here [IMAGE], the graph is showing the date and time, but the x Axis is not accepting the date / time.
Ive tried using date.UTC, but that did not work either. Can someone point me in the right direction?
https://jsfiddle.net/asvoy6b9/ [not working due to CSV missing]
Full code [Hastebin]
I see that date variable in your code is a string:
// all data lines start with a double quote
line = line.split(',');
date = line[1] + " " + line[2];
(...)
RTC.push([
date,
parseInt(line[3], 10)
]);
If you choose to construct the point's options as an array of two values and the first value is a string then it's treated as its name property (not x).
Explanation: https://www.highcharts.com/docs/chart-concepts/series
In that case Highcharts assigns subsequent integers as x values for all points (that's why there're values like 00:00:00.000 (1 Jan 1970), 00:00:00.001 etc.).
You need to parse your date to timestamp. You can use Date.UTC() (https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Date/UTC) or some other function for this.
I've managed to get it working with Date.UTC using the following code:
var yyyymmdd = line[2].split("-"); //Split the date: 2017 12 16
var hhmmss = line[3].split(":"); //Split the time: 16 11 14
var date = Date.UTC(yyyymmdd[0], yyyymmdd[1] - 1, yyyymmdd[2], hhmmss[0], hhmmss[1], hhmmss[2]); //Stitch 'em together using Date.UTC
I have two columns in my Google Sheets: one column for base 10 and one column for base 36. I have filled out my Base 10 column to go from 1 to 5,000. I would like to create a function in my script that will allow me to take in the value of the Base 10 number and return a value of base 36. (0123456789abcdefghijklmnopqrstuvwxyz) I want to keep the letter lower case so that I won't confuse the number 0 with the letter O.
This is what I have tried so far in my script:
function toBase36(decNumb) {
var base36 = parseInt(decNumb, 36);
return parseInt(base36);
}
The code above produces the following result:
How can I edit my code that that I will add the lower case letters?
It would be much simpler to use the toString() method.
Instead of var base36 = parseInt(decNumb, 36);
use var base36 = decNumb.toString(36);
Hi there seems to be plenty out there to convert a US formatted date (MM/DD/YYYY) to a UK date (DD/MM/YYYY), but I'm trying to do the opposite: i receive a load of UK dates (DD-MM-YYYY) from the server which I'm trying to format as DD-MMM-YYYY (eg: 11 Jan 2013 ), but Flex thinks it's trying to convert American days and so when it gets 17-02-2013, it returns an empty string because there is no month 17.
How do i tell it I'm giving it UK dates and not US dates?
Thanks in advance.
Short answer, you can't.
Longer answer, there's not enough information to determine the date format. As you saw, in some cases you CAN determine that the date is not valid for the expected format (17-02-2013 - since 17 isn't a valid month, it must be DD-MM-YYYY rather than MM-DD-YYYY), but for just under half of the dates you just can't tell (is 01-02-2013 supposed to be Jan 2 or Feb 1?)
If you DO know that the dates are supposed to be in a particular format, you can use DateField.stringToDate to parse the string:
var value:Date = DateField.stringToDate(dateString, 'DD-MM-YYYY');
OK, got round it in the end with this ugly hack: ended up converting the string into an array and re-organising it so that it would fit the american format before using the DateFormatter.format on the result. There must be a more elegant way...
<Script>
public convertDateStringToUS( date : String ) : String
{
var dateArray : Array = date.split( "-" );
var day = dateArray[0];
var month = dateArray[1];
var year = dateArray[2];
date = month + "-" + day + "-" + year;
return date
}
</Script>
<declarations>
<mx:DateFormatter id="dateFormatter"
formatString="DD-MMM-YYYY" />
</declarations>
<s:Label id="myDateLabel"
text =" { dateFormatter.format( convertDateStringToUS( date ) ) } "/>
I have a function that gets a numeric value (as Object) and returns a well formatted representation of that number. Because we can get very small numbers, in the process we use the Number object of flex. this is part of the code:
var numericValue:Number = Number(value.toString());
var fixed:String = numericValue.toFixed(precision);
This is the problem: there are situations that the numeric value is in the form of
5.684341886080802e-14
because we want to represent these numbers as 0 we use the above code. In this specific case, where precision is 0 we get an odd result
Initial Values:
value = 5.684341886080802e-14
percision = 0
Operation on values:
var numericValue:Number = Number(value.toString());
var fixed:String = numericValue.toFixed(precision);
Result:
fix = "1."
Why is this?
(BTW - on other numbers in the representataion of X.XXXXXXe-YY with percision bigger than 0 we get the correct result of 0)
This is a bug in Flash Player (FP-5141). It has been around for quite a while. The bug report says it is fixed, but it is not as of Flash Player 11.5.