I want replace random word in WordPress post. I have a code for MySQL.
This code working well:
update wp_posts set post_content =
replace(post_content,'oldword','newword');
But when I want replace random in database like
replace(post_content,'oldword',rand('newword','google','stackoverflow','stackover'));
This code not working.
I don't know how use this code for random replace word.
I want each occurrence of oldword to be replaced by a different word
Error
SQL query:
UPDATE wp_posts SET post_content =
REPLACE_RANDOM(post_content, 'oldword')
MySQL said: Documentation
#1366 - Incorrect string value: '\xD8\xA7\xDB\x8C\xD9\x86...' for column 'String' at row 1
Where is the problem?
DELIMITER $$
DROP FUNCTION IF EXISTS Replace_Random$$
CREATE FUNCTION Replace_Random(String TEXT, Word TEXT)
RETURNS TEXT
BEGIN
DECLARE New TEXT DEFAULT '';
DECLARE Loc INT DEFAULT INSTR(String, Word);
DECLARE WLen INT DEFAULT Length(Word);
WHILE Loc DO
SET New = CONCAT(New, SUBSTR(String, 1, Loc-1), ELT(FLOOR(RAND()*5)+1, 'biterrr', 'stackoverflow', 'serress', 'ms-ms-ms', 'Nick'));
SET String = SUBSTR(String, Loc + WLen);
SET Loc = INSTR(String, Word);
END WHILE;
SET NEW = CONCAT(New, String);
RETURN New;
END$$
DELIMITER ;
UPDATE wp_posts SET post_content =
REPLACE_RANDOM(post_content, 'oldword');`
You could use ELT to pick a random value from a list of strings:
UPDATE wp_posts SET post_content =
REPLACE(post_content, 'oldword', ELT(FLOOR(RAND()*5)+1, 'hello', 'world', 'friend', 'tuesday', 'sunny'))
If you have a different number of strings in the list, just change the multiplier of RAND() from 5 to the number of strings.
Update
If you need to replace multiple occurrences of the string in a phrase with different words, you will need a stored function. This one will do the job:
DELIMITER \\
DROP FUNCTION IF EXISTS Replace_Random\\
CREATE FUNCTION Replace_Random(String TEXT CHARACTER SET utf8, Word TEXT CHARACTER SET utf8)
RETURNS TEXT CHARACTER SET utf8
BEGIN
DECLARE New TEXT CHARACTER SET utf8 DEFAULT '';
DECLARE Loc INT DEFAULT INSTR(String, Word);
DECLARE WLen INT DEFAULT Length(Word);
WHILE Loc DO
SET New = CONCAT(New, SUBSTR(String, 1, Loc-1), ELT(FLOOR(RAND()*5)+1, 'hello', 'world', 'friend', 'tuesday', 'sunny'));
SET String = SUBSTR(String, Loc + WLen);
SET Loc = INSTR(String, Word);
END WHILE;
SET NEW = CONCAT(New, String);
RETURN New;
END\\
DELIMITER ;
SELECT REPLACE_RANDOM('a string with oldword in it twice - oldword!', 'oldword');
Output (varies):
a string with sunny in it twice - tuesday!
a string with hello in it twice - friend!
Related
I would like to have a multiple values Paramter with text1, text2, text3
SSRS should only show me the rows that contain one or all of this Parameter values in a column.
I notice you can set a filter in a Dataset or the tablix. The problem is I do not have something a function that do both LIKE and IN
Do you someone have an idea?
I tried already the LIKE function and the VALUE =”*”+”Parameters!PAR.Value”+”*”.
It did work, but not on a multiple values parameter.
I don't think you will be able to do this using dataset filters using a multi-value parameter.
However, you should be able to change your dataset query to handle this.
CREATE PROC myProc (#myParameter varchar(1000))
AS
SELECT * FROM myTable t
JOIN string_split(#myParameter, ',') p on t.myColumn like '%' + p.value + '%'
When you pass the parameter to the stored proc you can use the following expression
=JOIN(Parameters!myParameter.Value, ",")
This will simply join each of your parameter values into a single comma separated string string ready to pass to the procedure.
If you do not have a version of SQL Server that support string_split
Hers's the code to create one. There are smaller versions around on the internet but this one was designed to handle special cases as well as the typical single character delimiters.
SET ANSI_NULLS ON
GO
SET QUOTED_IDENTIFIER ON
GO
CREATE FUNCTION [Split](#sText varchar(8000), #sDelim varchar(20) = ' ')
RETURNS #retArray TABLE (idx smallint Primary Key, value varchar(8000))
AS
BEGIN
DECLARE #idx smallint,
#value varchar(8000),
#bcontinue bit,
#iStrike smallint,
#iDelimlength tinyint
IF #sDelim = 'Space'
BEGIN
SET #sDelim = ' '
END
SET #idx = 0
SET #sText = LTrim(RTrim(#sText))
SET #iDelimlength = DATALENGTH(#sDelim)
SET #bcontinue = 1
IF NOT ((#iDelimlength = 0) or (#sDelim = 'Empty'))
BEGIN
WHILE #bcontinue = 1
BEGIN
--If you can find the delimiter in the text, retrieve the first element and
--insert it with its index into the return table.
IF CHARINDEX(#sDelim, #sText)>0
BEGIN
SET #value = SUBSTRING(#sText,1, CHARINDEX(#sDelim,#sText)-1)
BEGIN
INSERT #retArray (idx, value)
VALUES (#idx, #value)
END
--Trim the element and its delimiter from the front of the string.
--Increment the index and loop.
SET #iStrike = DATALENGTH(#value) + #iDelimlength
SET #idx = #idx + 1
SET #sText = LTrim(Right(#sText,DATALENGTH(#sText) - #iStrike))
END
ELSE
BEGIN
--If you can't find the delimiter in the text, #sText is the last value in
--#retArray.
SET #value = #sText
BEGIN
INSERT #retArray (idx, value)
VALUES (#idx, #value)
END
--Exit the WHILE loop.
SET #bcontinue = 0
END
END
END
ELSE
BEGIN
WHILE #bcontinue=1
BEGIN
--If the delimiter is an empty string, check for remaining text
--instead of a delimiter. Insert the first character into the
--retArray table. Trim the character from the front of the string.
--Increment the index and loop.
IF DATALENGTH(#sText)>1
BEGIN
SET #value = SUBSTRING(#sText,1,1)
BEGIN
INSERT #retArray (idx, value)
VALUES (#idx, #value)
END
SET #idx = #idx+1
SET #sText = SUBSTRING(#sText,2,DATALENGTH(#sText)-1)
END
ELSE
BEGIN
--One character remains.
--Insert the character, and exit the WHILE loop.
INSERT #retArray (idx, value)
VALUES (#idx, #sText)
SET #bcontinue = 0
END
END
END
RETURN
END
GO
To test this try something like
select * from Split('abc,def,ghi', ',')
which will return
MySQL version = 5.7.29
I want to do a MySQL search on a column which has delimited data. For example:
'field_black:1, field_white:2, field1_black:5, field_green:3'
I want a function which takes input the color and returns only the delimited values which do not have the input color.
func(input, color, delimiter)
func('field_black:1, field_white:2, field1_black:5, field1_green:3', 'black', ',') = 'field_white:2, field1_green:3'
This is pretty easy to implement in python using string split on delimiter and returning result set where the color is not in the given input.
def func(inp, col, delim):
inp = inp.split(delim)
res = []
for data in inp:
if col not in data:
res.append(data)
return (','.join(res))
Can anyone help me with an equivalent implementation in MySQL.
Thank you for the help!
CREATE FUNCTION func (input TEXT, color TEXT, delimiter CHAR(1))
RETURNS TEXT
DETERMINISTIC
BEGIN
DECLARE piece TEXT;
DECLARE result TEXT DEFAULT '';
/* SET color = CONCAT('field_', color); */ /* uncomment if needed */
REPEAT
SET piece = SUBSTRING_INDEX(input, delimiter, 1);
SET input = SUBSTRING(input FROM 2 + LENGTH(piece) FOR LENGTH(input));
IF NOT LOCATE(color, piece) THEN
SET result = CONCAT(result, delimiter, TRIM(piece));
END IF;
UNTIL input = ''
END REPEAT;
RETURN TRIM(BOTH delimiter FROM result);
END
fiddle
PS. Of course you may use multi-char delimiter if needed - alter input parameter type simply.
Just cracked this after a few iterations due to unfamiliarity with MySQL syntax. This is unnecessarily complicated though.
Answer by Akina is more simple and elegant: mysql delimit and search column data
CREATE FUNCTION `new_function`(input longtext, col TEXT, delim CHAR(1)) RETURNS longtext CHARSET utf8
DETERMINISTIC
BEGIN
declare result longtext default '';
declare piece longtext default '';
declare inptext longtext default '';
set inptext = input;
while (substring_index(inptext,delim,1) = '') = 0 DO
set piece = substring_index(inptext,delim,1);
IF NOT LOCATE(col, piece) THEN
set result = concat(result, piece, delim);
END IF;
set inptext = substr(inptext, length(SUBSTRING_INDEX(inptext, '|', 1) ) + 2);
END WHILE;
set result = left(result, length(result) -1);
RETURN result;
END
I am trying to run a query that can find all the records from a field contains the letters.
For example suppose a state field contains a record value "New York" and another record conatains NY. Now i am searching for NY or New york will return these 2 records. What will be the query.
Currently i am using
like %New York%" or "%NY%"
Any suggestion
No your query is not correct as it searches for anything containing New York or NY.
So if there is PENNY that will be matched although it shouldn't be....
Your query must be something like this.
SELECT * from TABLE where field in ('NEW YORK','NY')
Now to fetch acronym,you can use
delimiter $$
drop function if exists `initials`$$
CREATE FUNCTION `initials`(str text, expr text) RETURNS text CHARSET utf8
begin
declare result text default '';
declare buffer text default '';
declare i int default 1;
if(str is null) then
return null;
end if;
set buffer = trim(str);
while i <= length(buffer) do
if substr(buffer, i, 1) regexp expr then
set result = concat( result, substr( buffer, i, 1 ));
set i = i + 1;
while i <= length( buffer ) and substr(buffer, i, 1) regexp expr do
set i = i + 1;
end while;
while i <= length( buffer ) and substr(buffer, i, 1) not regexp expr do
set i = i + 1;
end while;
else
set i = i + 1;
end if;
end while;
return result;
end$$
drop function if exists `acronym`$$
CREATE FUNCTION `acronym`(str text) RETURNS text CHARSET utf8
begin
declare result text default '';
set result = initials( str, '[[:alnum:]]' );
return result;
end$$
delimiter ;
So,your final query will be something like this.
SELECT * from TABLE where field in ('NEW YORK',select acronym('Come Again? That Cant Help!'))
Source:- Mysql extract first letter of each word in a specific column
Presumably, the logic that you want is:
col like '%New York%' or col like '%NY%'
or, if you want to use regular expressions:
col regexp 'New York|NY'
Select * from table where col like '%N' or col like '%n'
I have developed a function for split string in tsql but mysql don't have some built in functions. I needed to function in MYSQL as i am new in mysql. Function should accept 2 parameters
1. String to be split
2. separator (',' or whatever)
Kindly reply me.
i had found solution on the internet you can into that.
DELIMITER //
DROP FUNCTION IF EXISTS `splitAndTranslate` //
CREATE FUNCTION splitAndTranslate(str TEXT, delim VARCHAR(124))
RETURNS TEXT
DETERMINISTIC
BEGIN
DECLARE i INT DEFAULT 0; -- total number of delimiters
DECLARE ctr INT DEFAULT 0; -- counter for the loop
DECLARE str_len INT; -- string length,self explanatory
DECLARE out_str text DEFAULT ''; -- return string holder
DECLARE temp_str text DEFAULT ''; -- temporary string holder
DECLARE temp_val VARCHAR(255) DEFAULT ''; -- temporary string holder for query
-- get length
SET str_len=LENGTH(str);
SET i = (LENGTH(str)-LENGTH(REPLACE(str, delim, '')))/LENGTH(delim) + 1;
-- get total number delimeters and add 1
-- add 1 since total separated values are 1 more than the number of delimiters
-- start of while loop
WHILE(ctr<i) DO
-- add 1 to the counter, which will also be used to get the value of the string
SET ctr=ctr+1;
-- get value separated by delimiter using ctr as the index
SET temp_str = REPLACE(SUBSTRING(SUBSTRING_INDEX(str, delim, ctr), LENGTH(SUBSTRING_INDEX(str, delim,ctr - 1)) + 1), delim, '');
-- query real value and insert into temporary value holder, temp_str contains the exploded ID
SELECT <real_value_column> INTO temp_val FROM <my_table> WHERE <table_id>=temp_str;
-- concat real value into output string separated by delimiter
SET out_str=CONCAT(out_str, temp_val, ',');
END WHILE;
-- end of while loop
-- trim delimiter from end of string
SET out_str=TRIM(TRAILING delim FROM out_str);
RETURN(out_str); -- return
END//
reference http://www.slickdev.com/2008/09/15/mysql-query-real-values-from-delimiter-separated-string-ids/
In mysql they they dont support some functionality like sqlserver. so spliting will be difficult in mysql
SELECT e.`studentId`, SPLIT(",", c.`courseNames`)[e.`courseId`]
FROM ..
SELECT TRIM(SUBSTRING_INDEX(yourcolumn,',',1)), TRIM(SUBSTRING_INDEX(yourcolumn,',',-1)) FROM yourtable
CREATE FUNCTION [dbo].[SplitString]
(
#RowData nvarchar(2000),
#SplitOn nvarchar(5)
)
RETURNS #RtnValue table
(
--Id int identity(1,1),
Data nvarchar(100)
)
AS
BEGIN
Declare #Cnt int
Set #Cnt = 1
While (Charindex(#SplitOn,#RowData)>0)
Begin
Insert Into #RtnValue (data)
Select
Data = ltrim(rtrim(Substring(#RowData,1,Charindex(#SplitOn,#RowData)-1)))
Set #RowData = Substring(#RowData,Charindex(#SplitOn,#RowData)+1,len(#RowData))
Set #Cnt = #Cnt + 1
End
Insert Into #RtnValue (data)
Select Data = ltrim(rtrim(#RowData))
Return
END
MySQL runs pretty much all string comparisons under the default collation... except the REPLACE command. I have a case-insensitive collation and need to run a case-insensitive REPLACE. Is there any way to force REPLACE to use the current collation rather than always doing case-sensitive comparisons? I'm willing to upgrade my MySQL (currently running 5.1) to get added functionality...
mysql> charset utf8 collation utf8_unicode_ci;
Charset changed
mysql> select 'abc' like '%B%';
+------------------+
| 'abc' like '%B%' |
+------------------+
| 1 |
+------------------+
mysql> select replace('aAbBcC', 'a', 'f');
+-----------------------------+
| replace('aAbBcC', 'a', 'f') |
+-----------------------------+
| fAbBcC | <--- *NOT* 'ffbBcC'
+-----------------------------+
If replace(lower()) doesn't work, you'll need to create another function.
My 2 cents.
Since many people have migrated from MySQL to MariaDB, those people will have available a new function called REGEXP_REPLACE. Use it as you would a normal replace, but the pattern is a regular expression.
This is a working example:
UPDATE `myTable`
SET `myField` = REGEXP_REPLACE(`myField`, '(?i)my insensitive string', 'new string')
WHERE `myField` REGEXP '(?i)my insensitive string'
The option (?i) makes all the subsequent matches case insensitive (if put at the beginning of the pattern like I have then it all is insensitive).
See here for more information: https://mariadb.com/kb/en/mariadb/pcre/
Edit: as of MySQL 8.0 you can now use the regexp_replace function too, see documentation: https://dev.mysql.com/doc/refman/8.0/en/regexp.html
Alternative function for one spoken by fvox.
DELIMITER |
CREATE FUNCTION case_insensitive_replace ( REPLACE_WHERE text, REPLACE_THIS text, REPLACE_WITH text )
RETURNS text
DETERMINISTIC
BEGIN
DECLARE last_occurency int DEFAULT '1';
IF LCASE(REPLACE_THIS) = LCASE(REPLACE_WITH) OR LENGTH(REPLACE_THIS) < 1 THEN
RETURN REPLACE_WHERE;
END IF;
WHILE Locate( LCASE(REPLACE_THIS), LCASE(REPLACE_WHERE), last_occurency ) > 0 DO
BEGIN
SET last_occurency = Locate(LCASE(REPLACE_THIS), LCASE(REPLACE_WHERE));
SET REPLACE_WHERE = Insert( REPLACE_WHERE, last_occurency, LENGTH(REPLACE_THIS), REPLACE_WITH);
SET last_occurency = last_occurency + LENGTH(REPLACE_WITH);
END;
END WHILE;
RETURN REPLACE_WHERE;
END;
|
DELIMITER ;
Small test:
SET #str = BINARY 'New York';
SELECT case_insensitive_replace(#str, 'y', 'K');
Answers: New Kork
This modification of Luist's answer allows one to replace the needle with a differently cased version of the needle (two lines change).
DELIMITER |
CREATE FUNCTION case_insensitive_replace ( REPLACE_WHERE text, REPLACE_THIS text, REPLACE_WITH text )
RETURNS text
DETERMINISTIC
BEGIN
DECLARE last_occurency int DEFAULT '1';
IF LENGTH(REPLACE_THIS) < 1 THEN
RETURN REPLACE_WHERE;
END IF;
WHILE Locate( LCASE(REPLACE_THIS), LCASE(REPLACE_WHERE), last_occurency ) > 0 DO
BEGIN
SET last_occurency = Locate(LCASE(REPLACE_THIS), LCASE(REPLACE_WHERE), last_occurency);
SET REPLACE_WHERE = Insert( REPLACE_WHERE, last_occurency, LENGTH(REPLACE_THIS), REPLACE_WITH);
SET last_occurency = last_occurency + LENGTH(REPLACE_WITH);
END;
END WHILE;
RETURN REPLACE_WHERE;
END;
|
DELIMITER ;
I went with http://pento.net/2009/02/15/case-insensitive-replace-for-mysql/ (in fvox's answer) which performs the case insensitive search with case sensitive replacement and without changing the case of what should be unaffected characters elsewhere in the searched string.
N.B. the comment further down that same page stating that CHAR(255) should be changed to VARCHAR(255) - this seemed to be required for me as well.
In the previous answers, and the pento.net link, the arguments to LOCATE() are lower-cased.
This is a waste of resources, as LOCATE is case-insensitive by default:
mysql> select locate('el', 'HELLo');
+-----------------------+
| locate('el', 'HELLo') |
+-----------------------+
| 2 |
+-----------------------+
You can replace
WHILE Locate( LCASE(REPLACE_THIS), LCASE(REPLACE_WHERE), last_occurency ) > 0 DO
with
WHILE Locate(REPLACE_THIS, REPLACE_WHERE, last_occurency ) > 0 DO
etc.
In case of 'special' characters there is unexpected behaviour:
SELECT case_insensitive_replace('A', 'Ã', 'a')
Gives
a
Which is unexpected... since we only want to replace the à not A
What is even more weird:
SELECT LOCATE('Ã', 'A');
gives
0
Which is the correct result... seems to have to do with encoding of the parameters of the stored procedure...
I like to use a search and replace function I created when I need to replace without worrying about the case of the original or search strings. This routine bails out quickly if you pass in an empty/null search string or a null replace string without altering the incoming string. I also added a safe count down just in case somehow the search keep looping. This way we don't get stuck in a loop forever. Alter the starting number if you think it is too low.
delimiter //
DROP FUNCTION IF EXISTS `replace_nocase`//
CREATE FUNCTION `replace_nocase`(raw text, find_str varchar(1000), replace_str varchar(1000)) RETURNS text
CHARACTER SET utf8
DETERMINISTIC
BEGIN
declare ret text;
declare len int;
declare hit int;
declare safe int;
if find_str is null or find_str='' or replace_str is null then
return raw;
end if;
set safe=10000;
set ret=raw;
set len=length(find_str);
set hit=LOCATE(find_str,ret);
while hit>0 and safe>0 do
set ret=concat(substring(ret,1,hit-1),replace_str,substring(ret,hit+len));
set hit=LOCATE(find_str,ret,hit+1);
set safe=safe-1;
end while;
return ret;
END//
This question is a bit old but I ran into the same problem and the answers given didn't allow me to solve it entirely.
I wanted the result to retain the case of the original string.
So I made a small modification to the replace_ci function proposed by fvox :
DELIMITER $$
DROP FUNCTION IF EXISTS `replace_ci`$$
CREATE FUNCTION `replace_ci` (str TEXT, needle CHAR(255), str_rep CHAR(255))
RETURNS TEXT
DETERMINISTIC
BEGIN
DECLARE return_str TEXT DEFAULT '';
DECLARE lower_str TEXT;
DECLARE lower_needle TEXT;
DECLARE tmp_needle TEXT;
DECLARE str_origin_char CHAR(1);
DECLARE str_rep_char CHAR(1);
DECLARE final_str_rep TEXT DEFAULT '';
DECLARE pos INT DEFAULT 1;
DECLARE old_pos INT DEFAULT 1;
DECLARE needle_pos INT DEFAULT 1;
IF needle = '' THEN
RETURN str;
END IF;
SELECT LOWER(str) INTO lower_str;
SELECT LOWER(needle) INTO lower_needle;
SELECT LOCATE(lower_needle, lower_str, pos) INTO pos;
WHILE pos > 0 DO
SELECT substr(str, pos, char_length(needle)) INTO tmp_needle;
SELECT '' INTO final_str_rep;
SELECT 1 INTO needle_pos;
WHILE needle_pos <= char_length(tmp_needle) DO
SELECT substr(tmp_needle, needle_pos, 1) INTO str_origin_char;
SELECT SUBSTR(str_rep, needle_pos, 1) INTO str_rep_char;
SELECT CONCAT(final_str_rep, IF(BINARY str_origin_char = LOWER(str_origin_char), LOWER(str_rep_char), IF(BINARY str_origin_char = UPPER(str_origin_char), UPPER(str_rep_char), str_rep_char))) INTO final_str_rep;
SELECT (needle_pos + 1) INTO needle_pos;
END WHILE;
SELECT CONCAT(return_str, SUBSTR(str, old_pos, pos - old_pos), final_str_rep) INTO return_str;
SELECT pos + CHAR_LENGTH(needle) INTO pos;
SELECT pos INTO old_pos;
SELECT LOCATE(lower_needle, lower_str, pos) INTO pos;
END WHILE;
SELECT CONCAT(return_str, SUBSTR(str, old_pos, CHAR_LENGTH(str))) INTO return_str;
RETURN return_str;
END$$
DELIMITER ;
Example of use :
SELECT replace_ci( 'MySQL', 'm', 'e' ) as replaced;
Will return :
| replaced |
| --- |
| EySQL |