Ordering issue when using SQL variable - mysql

I run this query:
SELECT stockcarddetail.id, stockcarddetail.date, stockcarddetail.quantity, stockcarddetail.pricePerItem
FROM Stockcard
LEFT JOIN staff
ON staff.branchId = stockcard.branchId
LEFT JOIN stockcarddetail
ON stockcarddetail.stockcardId = stockcard.id
WHERE staff.username = 'jemmy.h'
AND stockcarddetail.quantity > 0
AND stockcard.productId = '98924a5f-6afb-11e7-8dd4-2c56dcbcb038'
ORDER BY date ASC
and get the result below:
id | date | quantity| pricePerItem
50 | 2017-10-15 | 10.00 | 10000.00
1 | 2017-10-18 | 20.00 | 10000.00
Then, I need to calculate the cumulative of quantity based on the order above, so I run this query:
SELECT a.*, #tot:=#tot + a.quantity FROM
(SELECT #tot:= 0)b
JOIN
(SELECT stockcarddetail.id, stockcarddetail.date, stockcarddetail.quantity, stockcarddetail.pricePerItem
FROM Stockcard
LEFT JOIN staff
ON staff.branchId = stockcard.branchId
LEFT JOIN stockcarddetail
ON stockcarddetail.stockcardId = stockcard.id
WHERE staff.username = 'jemmy.h'
AND stockcarddetail.quantity > 0
AND stockcard.productId = '98924a5f-6afb-11e7-8dd4-2c56dcbcb038'
ORDER BY date ASC) a
Then I got this result:
id | date | quantity| pricePerItem | #tot
1 | 2017-10-18 | 20.00 | 10000.00 | 20
50 | 2017-10-15 | 10.00 | 10000.00 | 30
However, the result that I want is like this:
id | date | quantity| pricePerItem | #tot
50 | 2017-10-15 | 10.00 | 10000.00 | 10
1 | 2017-10-18 | 20.00 | 10000.00 | 30
How can I get the expected result?
EDIT
Simplified version of the problem can be found here: http://sqlfiddle.com/#!9/f6ad91/3

From what I understand from you, you want the cumulative total for each entry.
I suggest ditching the variable and relying on a subquery instead:
SELECT
scd.id,
scd.date,
scd.quantity,
scd.pricePerItem,
(SELECT SUM(scd1.quantity) FROM StockcardDetail AS scd1 WHERE scd1.stockcardId = scd.stockcardId AND scd1.date <= scd.date) AS total
FROM Stockcard
LEFT JOIN staff ON staff.branchId = stockcard.branchId
LEFT JOIN stockcarddetail AS scd ON scd.stockcardId = stockcard.id
WHERE staff.username = 'jemmy.h'
AND scd.quantity > 0
AND stockcard.productId = '98924a5f-6afb-11e7-8dd4-2c56dcbcb038'
ORDER BY scd.date ASC
The idea behind this is to make it select the sum of all entries prior (including the current one) for each entry.

As per my understanding, you should get the expected output from your query. But, you aren't getting your expected output, then other possible solution is (WITHOUT JOIN)
SET #tot:= 0;
SELECT
stockcarddetail.id,
stockcarddetail.date,
stockcarddetail.quantity,
stockcarddetail.pricePerItem,
#tot:=#tot + stockcarddetail.quantity as Total
FROM Stockcard
LEFT JOIN staff ON staff.branchId = stockcard.branchId
LEFT JOIN stockcarddetail ON stockcarddetail.stockcardId = stockcard.id
WHERE staff.username = 'jemmy.h' AND stockcarddetail.quantity > 0 AND stockcard.productId = '98924a5f-6afb-11e7-8dd4-2c56dcbcb038'
ORDER BY date ASC

Related

How to calculate a level with an unlimited number of levels?

Now I have that structure (very simplify):
promotion:
id | name | level1 | points1| level2 | points2 | client_id
1 | A | 10 | 12 | 20 | 15 | 1
client:
id | name | value
1 | john | 15
And that's how I calculate the level:
SELECT
name,
CASE
WHEN client.value >= promotion.level2 THEN promotion.points2
WHEN client.value >= promotion.level1 THEN promotion.points1
ELSE "None"
END as points
FROM promotion
JOIN client ON client.id = promotion.client_id
This is working well, but I would like to have such structure:
promotion:
id | name | client_id
1 | A | 1
level:
id | name | level | points | promotion_id
1 | level1 | 10 | 12 | 1
2 | level2 | 10 | 15 | 1
client:
id | name | value
1 | john | 15
But I don't have any idea how to use it in my query to get points...
SELECT
name,
CASE
???
END as points
FROM promotion
JOIN client ON client.id = promotion.client_id
LEFT JOIN level ON promotion.id= level.promotion_id
This query will give you the desired results. It uses a LEFT JOIN to find any rows in the level table which are lower than the client value, and then takes the MAX of those values, using COALESCE to set the value to None if there are no levels below the client's value:
SELECT p.name AS promotion,
c.name AS client,
COALESCE(MAX(l.points), 'None') AS points
FROM promotion p
JOIN client c ON c.id = p.client_id
LEFT JOIN level l ON l.promotion_id = p.id AND l.level < c.value
GROUP BY p.name, c.name
Output for your sample data:
promotion client points
A john 12
Demo on dbfiddle
I would use a correlated subquery:
select p.name,
(select l.points
from level l
where l.promotion_id = p.points and
l.level <= c.value
order by l.level desc
limit 1
) as points
from promotion p join
client c
on c.id = p.client_id;
The point of using a correlated subquery is to avoid an aggregation on the full data. With an index on level(promotion_id, level, points), this should have better performance.

Mysql join select max for all record

I am unable to map the record as my expectation.
Doc Table
-------+-------------------
doc_id | doc_title
-------+-------------------
1 | My book
-------+-------------------
2 | My sec Book
--------------------------
Doc details Table
-----------+--------------+-----------------------
fk_doc_id | doc_version | submit_date
-----------+--------------+-----------------------
1 | 1 | 2015-10-25 14:32:01
-----------+--------------+-----------------------
1 | 2 | 2015-10-26 13:00:01
-----------+--------------+-----------------------
1 | 3 | 2015-10-27 09:00:00
--------------------------+-----------------------
2 | 1 | 2015-10-25 11:15:01
-----------+--------------+-----------------------
2 | 2 | 2015-10-26 10:00:00
--------------------------+-----------------------
Question: How do I join this two tables to get each documents with the latest version doc info? even though I get the latest version but the row info which is not correct.
So far I have tried this query
SELECT *, max(doc_version) AS latest_version
FROM d_doc
JOIN d_doc_dtl ON d_doc.doc_id = d_doc_dtl.fk_doc_id
GROUP BY d_doc.doc_id;
My expected result is
--------+--------------+----------------+--------------------
doc_id | doc_title | latest_version | submit_date
--------+--------------+----------------+--------------------
1 | My book | 3 | 2015-10-27 09:00:00
--------+--------------+----------------+--------------------
2 | My sec book | 2 | 2015-10-26 10:00:00
----------------------------------------+--------------------
but my result is
--------+--------------+----------------+--------------------
doc_id | doc_title | latest_version | submit_date
--------+--------------+----------------+--------------------
1 | My book | 3 | 2015-10-25 14:32:01
--------+--------------+----------------+--------------------
2 | My sec book | 2 | 2015-10-25 11:15:01
----------------------------------------+--------------------
NOTE: the submit_date which is no correct.
SELECT d_doc.doc_id, d_doc.doc_title, max_table.latest_version
FROM d_doc JOIN (
select fk_doc_id, max(doc_version) as latest_version from d_doc_dtl group by fk_doc_id
) as max_table ON d_doc.doc_id = max_table.fk_doc_id
This query should work as you expect. It selects latest document versions in inner subquery and than joins it with documents.
SELECT d.doc_id,
d.doc_title,
dtl.doc_version latest_version,
dtl.submit_date
FROM d_doc d
INNER JOIN (SELECT dt.*
FROM d_doc_dtl dt
INNER JOIN (SELECT fk_doc_id, MAX(doc_version) doc_version
FROM d_doc_dtl
GROUP BY fk_doc_id) dm
ON dt.fk_doc_id = dm.fk_doc_id
AND dt.doc_version = dm.doc_version) dtl
ON d.doc_id = dtl.fk_doc_id
You get wrong results because you selected only max(version), but date as it is not in group by clause can contain any value. First you need to get records containing latest version as shown above.
Easy, instead of
SELECT *, max(doc_version) AS latest_version
Use this
SELECT d_doc.*, max(doc_version) AS latest_version
What you were doing by selecting * is getting all the results after the table is joined and you only wanted the original table results.
select * from doc_table , doc_version where exists( select
max(version_id)
from
doc_version vert
where
(doc_table .DOC_ID = vert.VERSION_DOC_ID) ) group by doc_id;
You can try something like this.

Get total count of records with a mysql join and 2 tables

I have 2 tables that I am trying to join but I am not sure how to make it the most time efficient.
Tasks Table:
nid | created_by | claimed_by | urgent
1 | 11 | 22 | 1
2 | 22 | 33 | 1
3 | 33 | 11 | 1
1 | 11 | 43 | 0
1 | 11 | 44 | 1
Employee Table:
userid | name
11 | EmployeeA
22 | EmployeeB
33 | EmployeeC
Result I am trying to get:
userid | created_count | claimed_count | urgent_count
11 | 3 | 1 | 3
22 | 1 | 1 | 2
33 | 1 | 1 | 2
created_account column will show total # of tasks created by that user.
claimed_count column will show total # of tasks claimed by that user.
urgent_count column will show total # of urgent tasks (created or claimed) by that user.
Thanks in advance!
I would start by breaking this up into pieces and then putting them back together. You can get the created_count and claimed_count using simple aggregation like this:
SELECT created_by, COUNT(*) AS created_count
FROM myTable
GROUP BY created_by;
SELECT claimed_by, COUNT(*) AS claimed_count
FROM myTable
GROUP BY claimed_by;
To get the urgent count for each employee, I would join the two tables on the condition that the employee is either the created_by or claimed_by column, and group by employee. Instead of counting, however, I would use SUM(). I am doing this because it appears each row will be either 0 or 1, so SUM() will effectively count all non-zero rows:
SELECT e.userid, SUM(t.urgent)
FROM employee e
JOIN task t ON e.userid IN (t.created_by, t.claimed_by)
GROUP BY e.userid;
Now that you have all the bits of data you need, you can use an outer join to join all of those subqueries to the employees table to get their counts. You can use the COALESCE() function to replace any null counts with 0:
SELECT e.userid, COALESCE(u.urgent_count, 0) AS urgent_count, COALESCE(crt.created_count, 0) AS created_count, COALESCE(clm.claimed_count, 0) AS claimed_count
FROM employee e
LEFT JOIN(
SELECT e.userid, SUM(t.urgent) AS urgent_count
FROM employee e
JOIN task t ON e.userid IN (t.created_by, t.claimed_by)
GROUP BY e.userid) u ON u.userid = e.userid
LEFT JOIN(
SELECT claimed_by, COUNT(*) AS claimed_count
FROM task
GROUP BY claimed_by) clm ON clm.claimed_by = e.userid
LEFT JOIN(
SELECT created_by, COUNT(*) AS created_count
FROM task
GROUP BY created_by) crt ON crt.created_by = e.userid;
Here is an SQL Fiddle example.

Filter query with order by and limit when using left join

How to filter query with order by and limit when using left join
store_profile
id + store_name
1 | Accessorize.me
2 | Active IT
3 | Edushop
4 | Gift2Kids
5 | Heavyarm
6 | Bamboo
store_fee
id + store_id + date_end
1 | 1 | 27-6-2013
2 | 2 | 29-8-2013
3 | 3 | 02-6-2013
4 | 4 | 20-4-2013
5 | 4 | 01-7-2013
6 | 4 | 28-9-2013
7 | 5 | 03-9-2013
8 | 6 | 01-9-2013
my previous query
$order_by_for_sort_column = "order by $column" //sorting column
$query = "SELECT * FROM store_profile sp LEFT JOIN store_fee sf ON (sf.store_id = sp.id) $order_by_for_sort_column";
what i want is order by id desc and limit 1 for table store_fee not for for entire query. So i can grab the latest date in date_end for each store.
As you can see for store_id 4(store_fee) i have 3 different date and i just want grab the latest date.
and the result should be something like this
1 | Accessorize.me 27-6-2013
2 | Active IT 29-8-2013
3 | Edushop 02-6-2013
4 | Gift2Kids 28-9-2013
5 | Heavyarm 03-9-2013
6 | Bamboo 01-9-2013
SELECT a.id, a.store_name, MAX(b.date_End) date_end
FROM store_profile a
LEFT JOIN store_fee b
ON a.ID = b.store_ID
GROUP BY a.id, a.store_name
SQLFiddle Demo
but if the datatype date_End column is varchar, the above query won't work because it sorts the value by character and that it can mistakenly gives undesired result. 18-1-2013 is greater than 01-6-2013.
To further gain more knowledge about joins, kindly visit the link below:
Visual Representation of SQL Joins
SELECT *
FROM store_profile AS sp
LEFT JOIN (
SELECT store_id, MAX(date_end)
FROM store_fee
GROUP BY store_id
) AS sf
ON sp.id=sf.store_id;

nested query & transaction

Update #1: query gives me syntax error on Left Join line (running the query within the left join independently works perfectly though)
SELECT b1.company_id, ((sum(b1.credit)-sum(b1.debit)) as 'Balance'
FROM MyTable b1
JOIN CustomerInfoTable c on c.id = b1.company_id
#Filter for Clients of particular brand, package and active status
where c.brand_id = 2 and c.status = 2 and c.package_id = 3
LEFT JOIN
(
SELECT b2.company_id, sum(b2.debit) as 'Current_Usage'
FROM MyTable b2
WHERE year(b2.timestamp) = '2012' and month(b2.timestamp) = '06'
GROUP BY b2.company_id
)
b3 on b3.company_id = b1.company_id
group by b1.company_id;
Original Post:
I keep track of debits and credits in the same table. The table has the following schema:
| company_id | timestamp | credit | debit |
| 10 | MAY-25 | 100 | 000 |
| 11 | MAY-25 | 000 | 054 |
| 10 | MAY-28 | 000 | 040 |
| 12 | JUN-01 | 100 | 000 |
| 10 | JUN-25 | 150 | 000 |
| 10 | JUN-25 | 000 | 025 |
As my result, I want to to see:
| Grouped by: company_id | Balance* | Current_Usage (in June) |
| 10 | 185 | 25 |
| 12 | 100 | 0 |
| 11 | -54 | 0 |
Balance: Calculated by (sum(credit) - sum(debits))* - timestamp does not matter
Current_Usage: Calculated by sum(debits) - but only for debits in JUN.
The problem: If I filter by JUN timestamp right away, it does not calculate the balance of all time but only the balance of any transactions in June.
How can I calculate the current usage by month but the balance on all transactions in the table. I have everything working, except that it filters only the JUN results into the current usage calculation in my code:
SELECT b.company_id, ((sum(b.credit)-sum(b.debit))/1024/1024/1024/1024) as 'BW_remaining', sum(b.debit/1024/1024/1024/1024/28*30) as 'Usage_per_month'
FROM mytable b
#How to filter this only for the current_usage calculation?
WHERE month(a.timestamp) = 'JUN' and a.credit = 0
#Group by company in order to sum all entries for balance
group by b.company_id
order by b.balance desc;
what you will need here is a join with sub query which will filter based on month.
SELECT T1.company_id,
((sum(T1.credit)-sum(T1.debit))/1024/1024/1024/1024) as 'BW_remaining',
MAX(T3.DEBIT_PER_MONTH)
FROM MYTABLE T1
LEFT JOIN
(
SELECT T2.company_id, SUM(T2.debit) T3.DEBIT_PER_MONTH
FROM MYTABLE T2
WHERE month(T2.timestamp) = 'JUN'
GROUP BY T2.company_id
)
T3 ON T1.company_id-T3.company_id
GROUP BY T1.company_id
I havn't tested the query. The point here i am trying to make is how you can join your existing query to get usage per month.
alright, thanks to #Kshitij I got it working. In case somebody else is running into the same issue, this is how I solved it:
SELECT b1.company_id, ((sum(b1.credit)-sum(b1.debit)) as 'Balance',
(
SELECT sum(b2.debit)
FROM MYTABLE b2
WHERE b2.company_id = b1.company_id and year(b2.timestamp) = '2012' and month(b2.timestamp) = '06'
GROUP BY b2.company_id
) AS 'Usage_June'
FROM MYTABLE b1
#Group by company in order to add sum of all zones the company is using
group by b1.company_id
order by Usage_June desc;