$productLists = DB::table('A')
->leftJoin('B', function($join) {
$join->where('B.qty','=', 1);
$join->on("B.id", "=", "A.id");
})
->select('A.*','B.*')
->get();
What's wrong with the query?
The field I get from B table all returned null .
Am I doing it in wrong way?
Try this:
$productLists = DB::table('A')
->leftJoin('B', function($join) {
$join->where('B.qty','=', 1)
->on("B.id", "=", "A.id");
})
->select('A.*','B.*')
->get();
$productLists = DB::table('A') ->select('A.*','B.*')->join('B','B.id','=','A.id')->where('B.qty', 1) ->get();
this is one way to write joins in laravel..
try this:
$productLists = DB::table('A')
->join('B', 'B.id', '=', 'A.id')
->select('A.*','B.*')
->where('B.qty','=', 1)
->get();
Related
I have the following raw SQL query:
select a.id user_id, a.email_address, a.name_first, a.name_last, count(b.id) number_of_videos, sum(b.vimeo_duration) total_duration, sum(b.count_watched) total_playbacks
from users a,
videos b
where a.id = b.tutor_id
and a.email_address in ('candace_rennie#yahoo.com', 'tjm#hiltoncollege.com', 'matthewjameshenshall#gmail.com', 'nkululeko#syafunda.co.za', 'khulile#syafunda.co.za', 'nzakheni#syafunda.co.za')
group by a.id;
This correctly gets 6 rows from the database. I'm trying to convert this to a Laravel database query like so:
$totals = DB::table('users')
->select(DB::Raw('users.id as user_id'), 'users.email_address', 'users.name_first', 'users.name_last', DB::Raw('count(videos.id) as number_of_videos'), DB::Raw('sum(videos.vimeo_duration) as total_duration'), DB::Raw('sum(videos.count_watched) as total_playbacks'))
->join('videos', 'users.id', '=', 'videos.tutor_id')
->where('users.id', 'videos.tutor_id')
->whereIn('users.email_address', array('candace_rennie#yahoo.com', 'tjm#hiltoncollege.com', 'matthewjameshenshall#gmail.com', 'nkululeko#syafunda.co.za', 'khulile#syafunda.co.za', 'nzakheni#syafunda.co.za'))
->groupBy('users.id')
->get();
This however return 0 rows. Is there anything I'm missing?
It should be smth like below even tho groupBy user id does not help much as id is unique.
$aggregates = [
DB::raw('count(b.id) as number_of_videos'),
DB::raw('sum(b.vimeo_duration) as total_duration'),
DB::raw('sum(b.count_watched) as total_playbacks'),
];
$simpleSelects = ['users.email_address', users.id, 'users.name_first', 'users.name_last'];
$emails = ['candace_rennie#yahoo.com', 'tjm#hiltoncollege.com'....]
$users = Users::select(array_merge($simpleSelects, $aggregates))
->leftJoin('videos as b', function ($join) use ($emails) {
$join->on('b.tutor_id', 'a.id')
->whereIn('users.email_address', $emails);
})
->groupBy('users.id')
->get();
Try to remove this line:
->where('users.id', 'videos.tutor_id')
List item
after sql code convert into laravel
DB::select('posts.id','posts.title','posts.body')
->from('posts')
->where('posts.author_id', '=', 1)
->orderBy('posts.published_at', 'DESC')
->limit(10)
->get();
I have a 3 table questions,registrations,ssi_tracks i need to get details from the registraions table by corresponding to other two tables
i need to get details from registrations based on
questions.question_schedul=0 ,ssi_tracks.track_first_status
i have wrote query but it says the column is not found here is my query
$register = DB::table('registrations')
->join('questions', 'registrations.registration_id', '=', 'questions.question_id')
->join('ssi_tracks','registrations.registration_id','=','ssi_tracks.registration_id')
->select('address', 'model', 'chassis', 'delivery_date','ssi_tracks.track_first_status')
->where([["questions.question_schedul", "=", $dropselected] and ['ssi_tracks.track_first_status',0]])
->get();
Try this:
$register = DB::table('registrations as R')
->select('R.address', 'R.model', 'R.chassis', 'R.delivery_date','S.track_first_status')
->join('questions as Q', 'R.registration_id', '=', 'Q.question_id')
->join('ssi_tracks as S','R.registration_id','=','S.registration_id')
->where('Q.question_schedul', '=', $dropselected)
->where('S.track_first_status', '=', 0)
->get();
Make sure you have used the right column here from question table for matching registration id:
->join('questions as Q', 'R.registration_id', '=', 'Q.question_id')
try this query :
$register = DB::table('registrations')
->leftJoin('questions', 'registrations.registration_id', '=', 'questions.question_id')
->leftJoin('ssi_tracks','registrations.registration_id','=','ssi_tracks.registration_id')
->select('registrations.address', 'registrations.model', 'registrations.chassis', 'registrations.delivery_date','ssi_tracks.track_first_status')
->where(['questions.question_schedul'=>$dropselected,'ssi_tracks.track_first_status'=>0])
->get();
I have 2 tables 'users' and 'instantUsers'. I want to join them on users.id = instantUsers.user_id and want to add 2 where clauses on the resulting. I'm not getting how to do both. The query I'm using is -
DB::table('users')
->join('instantUsers', function($join) use ($userId) {
$join->on('users.id', '=', 'instantUsers.user_id');
})
->where('instantUsers.instantMode', '=', '1')
->where (function($query) use ($userId) {
$query->where('instantUsers.user_id', '!=', $userId);
})
->get();
You can try this one maybe this will help you:
DB::table('users as table1')->join('instantUsers as table2','table1.id','=','table2.fkId') ->where('table2.instantMode','=','1')->where('table2.user_id','!=',$userId)->get();
Your 'instantUsers.instantMode','=','1' expression can be done in a join, resulting in a better performance.
I would write it like this
DB::table('users')
->join('instantUsers', function($join) use ($userId) {
$join
->on('users.id', '=', 'instantUsers.user_id')
->on('instantUsers.instantMode', '=', 1);
})
->where('users.id', '!=', $userId)
->get();
What i'm trying to achieve is the following:
I want to check if there is a record with the same client_code but with a lower/different campaign id. I'm using a sub-query for now and i tried to do it with a join as well but I couldn't get the logic working
This is what i got now:
$oDB = DB::table('campaigns AS c')
->select(
'c.id AS campaign_id',
'cc.id AS campaign_customer_id'
)
->join('campaign_customers AS cc', 'cc.campaign_id', '=', 'c.id')
->where('c.status', '=', ModelCampaign::STATUS_PLANNED)
->where('c.scheduled', '=', 1)
->whereRaw('c.scheduled_at <= NOW()')
->where('cc.status', '=', ModelCampaignCustomer::STATUS_INVITE_EMAIL_SCHEDULED)
->whereNotIn('cc.client_code', '=', function ($query){
$query ->select(DB::raw(1))
->from('campaign_customers')
->whereRaw('campaign_id', '!=', 'c.id');
})
->where('cc.active', '=', 1)
;
any tips on how to work the logic would be great
You can use the ->toSql(); method to see the SQL so you can refactorize your query.
The whereNotIn probably shouldn't have an = in it
->whereNotIn('cc.client_code', function ($query){
....
edit
Try:
->whereNotIn('cc.client_code', function ($query){
$query->select(DB::raw('client_code'))
->from('campaign_customers')
->whereRaw('campaign_id != c.id');
})
I think the whereRaw should be a single text string or maybe you can use where here (looking at this for reference https://laravel.com/docs/5.2/queries#advanced-where-clauses). Also DB::raw(1) is going to return a 1 for each subquery result but you want an id for the whereNotIn.
i have the sql below:
$result = DB::table('tblA')
->join('tblB','tblB.id', '=', 'tblA.photoid')
->join('tblB','tblB.id', '=', 'tblA.linkedphotoid')
...
I have tblA with photoid and linkedphotoid and both link to one same table(tblB) and same column.
How to write it in laravel sql?
You can add OR condition in your join
$result = DB::table('tblA')
->join('tblB', function($join) {
$join->on('tblB.id', '=', 'tblA.photoid')->orOn('tblB.id', '=', 'tblA.linkedphotoid');
})
->get();