I have a column which has positive & negative numbers. Is it possible to have sum of all the positive numbers in Col1, negative numbers in Col2 and (Col1 - Col2) in Col3. Then sort by the last Col.
Current table New Table
ID Score ID Pos Neg Diff
1 3 3 5 0 5
1 1 1 4 1 3
1 -1 2 2 1 1
2 1
2 -1
2 1
3 3
3 1
3 1
This gives me the total but i would like to list the Pos and Neg numbers as well.
SELECT ID, SUM(Score) as total FROM results
GROUP BY ID ORDER BY total DESC
Just use a standard pivot query with separate conditional aggregations for the positive and negative numbers.
SELECT
ID,
SUM(CASE WHEN Score >= 0 THEN Score ELSE 0 END) AS Pos,
SUM(CASE WHEN Score < 0 THEN -1*Score ELSE 0 END) AS Neg,
SUM(Score) AS Diff
FROM results
GROUP BY ID
ORDER BY ID
Demo
Related
From this table
groupId
flag
flagValue
1
0
500
2
0
100
1
1
10
2
1
50
3
0
100
1
1
200
3
1
1000
2
1
50
I need this result
groupId
flag1
flag0
valFlag1
valFlag0
totalFlags
1
2
1
210
500
3
2
2
1
100
100
3
3
1
1
1000
100
2
where
flag1 is number of times flag is 1 for a particular group
flag0 is number of times flag is 0 for a particular group
valFlag1 is sum of flagVal when flag is 1
valFlag0 is sum of flagVal when flag is 0
totalFlags is sum of total flags associated with a group
I am stuck as to how to actually count values based on an IF condition.
Anyhelp is appreciated. Thanks.
I have used a table named group_table with your values
Try using this:
SELECT
g.`groupId`,
SUM(g.`flag`=1 ) AS flag1,
SUM(g.`flag`=0) AS flag0,
SUM(CASE WHEN g.`flag`=1 THEN g.`flagValue` ELSE 0 END) AS valFalg1,
SUM(CASE WHEN g.`flag`=0 THEN g.`flagValue` ELSE 0 END) AS valFalg0,
COUNT(*) AS totalFlags
FROM
`group_table` g
GROUP BY g.`groupId`
If you have to use the IF,
SELECT
g.`groupId`,
IF(g.`flag`=1,1,0 ) AS flag1,
IF(g.`flag`=0,1,0) AS flag0,
SUM(IF(g.`flag`=1,g.`flagValue`,0 )) AS valFalg1,
SUM(IF(g.`flag`=0,g.`flagValue`,0 )) AS valFalg0,
COUNT(*) AS totalFlags
FROM
`group_table` g
GROUP BY g.`groupId`, flag1, flag0
They'll produce the same result
In the Data shown,we need to do a continuous pattern check of Leaves,
for eg:
CASE
WHEN count("Leaves") BETWEEN 1 AND 2 THEN '1-2'
WHEN count("Leaves") BETWEEN 3 AND 5 THEN '3-5'
WHEN count("Leaves") >5 THEN '>5'
ELSE 'Above 5' END AS "Leave Occurence",
On Jan 1st and 2nd employee has taken 2 leaves togather which belongs to
'1-2'Bucket,
similarly 8,9,10,11th JAN it is contineous for 4 Days hence in '3-4'Bucket
and contineously more than 5 Leaves belongs to [<5]Bucket
Now we need the count of each Bucket for Month wise.
Here 1-2Bucket is 2
3-4Bucket is 1
<5 Bucket is also 1
We used this code ,but it gives the SUM,But not checking the contineous pattern
Year Month Leaves
2011 1-Jan 1
2-Jan 1
3-Jan 0
4-Jan 0
5-Jan 0
6-Jan 0
7-Jan 0
8-Jan 1
9-Jan 1
10-Jan 1
11-Jan 1
12-Jan 0
13-Jan 0
14-Jan 0
15-Jan 1
16-Jan 1
17-Jan 1
18-Jan 1
19-Jan 1
20-Jan 1
21-Jan 0
22-Jan 0
23-Jan 1
24-Jan 1
You can identify each group of leaves by counting the number of non-leaves before it. Then you have aggregation:
select min(date), max(date), count(*) as numdays
from (select t.*,
(select count(*)
from t t2
where t2.date <= t.date and t2.leave = 0
) as grp
from t
where t.leave = 1
) t
group by grp;
You can then format the results however you like. This gives you one row per continuous "leave" period.
I have a table X like this,
student ans_status question_id
1 1 10
2 -1 10
3 1 10
4 0 10
1 -1 11
2 1 11
3 -1 11
4 -2 11
expected o/p is
10 2/3
11 1/3
etc..
Now, i want the data fro each question 10 like,
number of 1's/(total of 1's and -1's for each question)
I have tried this,
select (select count(student_id) from X
where question_id=10 and ans_status=1) / count(student_id)
from X
where question_id=10
group by ans_status
having ans_status in(1,-1).
i can do it in a nested query, by again selecting and grouping according to the status condition, but is there any way better to do this?
please note i want this for all questions in the table
You can just do:
select question_id,
avg(ans_status = 1)
from X
where ans_status in (1, -1)
group by question_id;
This uses the MySQL feature that a boolean expression is treated as an integer in a numeric context. "True" is 1 and "false" is 0, so the average turns out to be the percentage that are true.
If you want the values independently:
select question_id,
sum(ans_status = 1), count(*)
from X
where ans_status in (1, -1)
group by question_id;
Use GROUP BY for taking count of each question_id for getting count of answer_id is 1 or -1.
Query
select t.`question_id`,
t.`count_1` / t.`total_count` as `new_col` from(
select `question_id`,
sum(case `ans_status` when 1 then 1 when -1 then 1 else 0 end) as `count_1`,
count(*) as `total_count`
from `your_table_name`
group by `question_id`
)t;
Find a demo here
Already checked solutions related to my question but didn't get what I want to achieve
Here is my table structure (for ex. where table name is tbl_rank)
name rank
apple 10
banana 2
grapes 5
orange 1
chiku 0
pineapple 0
Now What I want as result is that the elements with 0 rank should be given the max rank and all the elements should appear in descending order of their rank (actually creating a new column as new_rank),
This is the desired result
name rank new_rank
apple 10 10
chiku 0 10
pineapple 0 10
grapes 5 5
banana 2 2
orange 1 1
To get the above result I am using this query
SELECT *, (CASE WHEN rank=0 THEN MAX(rank) ELSE rank END) as new_rank
FROM `tbl_rank` ORDER BY new_rank DESC
but all I am getting is only one row as result of the above query
No idea where I am doing wrong or why its returning only one row
Try this:
SELECT A.*, (CASE WHEN A.rank = 0 THEN B.rank ELSE A.rank END) AS new_rank
FROM tbl_rank A, (SELECT MAX(rank) AS rank FROM tbl_rank) AS B
ORDER BY new_rank DESC;
I'm trying to put together a MYSQL query that will count the number of Non-Null (or better yet, non-zero) values in select fields in a single row and then sort from lowest to highest (based on the count). For example, I have a table with 5 fields... ID, Name, Score_1, Score_2, Score_3. I want to count how many times the value "0" exists in Score_1, Score_2 and Score_3 for each record, then sort from most non zero values to least.
ID Name Score_1 Score_2 Score_3
1 Dan 8 7 0
2 Joe 0 0 3
3 Chris 0 0 0
4 Mike 4 5 5
I assume the query has to look something like this...
Select ID, Name, Score_1, Score_2, Score_3 where (???) ORDER BY (???)
Output should look like this (ID 4 is displayed first since it has the least amount of non-zero entries)...
ID Name Score_1 Score_2 Score_3
4 Mike 4 5 5
1 Dan 8 7 0
2 Joe 0 0 3
3 Chris 0 0 0
I'm somewhat new to mysql query's, so any help would be greatly appreciated. I thought the COUNT function would help, but that function appears to count columns from all rows. Perhaps there is a way to use the COUNT function and limit it to a singel row so it can be sorted by that row count?
This should do what you want:
SELECT ID, Name, Score_1, Score_2, Score_3
FROM Table1
ORDER BY (Score_1 = 0) + (Score_2 = 0) + (Score_3 = 0)
Result:
ID Name Score_1 Score_2 Score_3
4 Mike 4 5 5
1 Dan 8 7 0
2 Joe 0 0 3
3 Chris 0 0 0
try This:
Select id, Count1, Count2, Count3, Count4
From
(Select
Sum(Case When IsNull(Score_1,0) = 0 Then 1 Else 0 End) Count1,
Sum(Case When IsNull(Score_2,0) = 0 Then 1 Else 0 End) Count2,
Sum(Case When IsNull(Score_3,0) = 0 Then 1 Else 0 End) Count3,
Sum(Case When IsNull(Score_4,0) = 0 Then 1 Else 0 End) Count4
From Table
Group By Id) Z -- This column (Id) better not be the PK for this table!!!
Order By Count1 + Count2 + Count3 + Count4