This pulls back two int values of yesterday and today. I'd like to subtract the two results from within the statement in a third column called difference:
SELECT (
SELECT COUNT(*)
FROM collectors_users
WHERE DATE(dateadded) = CURDATE() - INTERVAL 1 DAY
) AS yesterday, COUNT(*) AS today
FROM collectors_users
WHERE DATE(dateadded) = CURDATE()
You need to repeat the expressions. SQL (in general) does not allow you to re-use column aliases in the same SELECT. You can simplify the logic to:
SELECT SUM(DATE(dateadded) = CURDATE() - INTERVAL 1 DAY) AS yesterday,
SUM(DATE(dateadded) = CURDATE()) as today,
(SUM(DATE(dateadded) = CURDATE()) -
SUM(DATE(dateadded) = CURDATE() - INTERVAL 1 DAY)
) as diff
FROM collectors_users
WHERE dateadded >= CURDATE() - INTERVAL 1 DAY AND
dateadded < CURDATE() + INTERVAL 1 DAY;
Note that the logic for the WHERE clause covers two days. Also, it does not use DATE(). This would allow the query to use an index, if available.
Related
I'm trying to turn two count queries with date conditions (the ones below) into one query.
SELECT COUNT(*) as yesterday FROM orders WHERE DATE(timedate) = DATE(NOW() - INTERVAL 1 DAY)
SELECT COUNT(*) as yesterday FROM orders WHERE DATE(timedate) = DATE(NOW() - INTERVAL 2 DAY)
Following the advice of another answer I created the following, but that doesn't seem to work syntax-wise, and I'm not quite sure why. Is there another way to do this? I can't find a similar question on this
SELECT
SUM(IF(DATE(timedate) = DATE(NOW() - INTERVAL 1 DAY))) AS testcount1,
SUM(IF(DATE(timedate) = DATE(NOW() - INTERVAL 2 DAY))) AS testcount2
FROM
orders
You're missing the output values for the IF expression. Also you should use CURRENT_DATE() so you don't need to convert to a DATE:
SELECT
SUM(IF(DATE(timedate) = CURRENT_DATE() - INTERVAL 1 DAY, 1, 0)) AS testcount1,
SUM(IF(DATE(timedate) = CURRENT_DATE() - INTERVAL 2 DAY, 1, 0)) AS testcount2
FROM
orders
Note that MySQL treats boolean expressions as 1 (true) or 0 (false) in a numeric context, so you can actually SUM the expression without needing the IF:
SELECT
SUM(DATE(timedate) = CURRENT_DATE() - INTERVAL 1 DAY) AS testcount1,
SUM(DATE(timedate) = CURRENT_DATE() - INTERVAL 2 DAY) AS testcount2
FROM
orders
You want conditional aggregation. I would phrase the query as follows:
SELECT
SUM(
timedate >= CURRENT_DATE - INTERVAL 1 DAY
and timedate < CURRENT_DATE
) AS testcount1,
SUM(
timedate >= CURRENT_DATE - INTERVAL 2 DAY
and timedate < CURRENT_DATE- INTERVAL 1 DAT
) AS testcount2
FROM orders
Details:
this uses a nice feature of MySQL, that evaluates false/true conditions as 0/1 in numeric context
no date functions are applied on the timedate column : instead, we do litteral date comparisons. This is much more efficient, since the database can possibly take advantage of an index on the datetime column
You might also want to add a WHERE clause to the query:
WHERE
timedate >= CURRENT_DATE - INTERVAL 2 day
AND timedate< CURRENT_DATE
i got a MySQL tbl, with some colums, where every 5 min. a new row is inserted with 3 values
1. Auto inc. curent Date Unix timestamp --> date
2. power consumption absolut --> wert01
3. Power Generation absolut --> wert02
To Show this Information in a Graph, for Exampl for weekly power consumption, i need to select the First and the last, which allready Works, but then have to Substract the last from the First and Show only tue result & the day of the werk.
SELECT
(SELECT wert01
FROM sml_splitt
WHERE date >= curdate() - INTERVAL DAYOFWEEK(curdate())+6 DAY
AND date < curdate() - INTERVAL DAYOFWEEK(curdate()) DAY
ORDER BY date DESC LIMIT 1) AS 'last',
(SELECT wert01
FROM sml_splitt
WHERE date >= curdate() - INTERVAL DAYOFWEEK(curdate())+6 DAY
AND date < curdate() - INTERVAL DAYOFWEEK(curdate()) DAY
ORDER BY date LIMIT 1) AS 'lirst
I am searching for some days to find a solution, but with no success.
Hopfuly, you could help me.
If you're happy with your query, then you can do the math by nesting it one more time like this: http://sqlfiddle.com/#!9/515ef/1
select t1.last, t1.first, t1.last - t1.first as result
from (
select (
select wert01
from sml_splitt
where dt >= curdate() - interval dayofweek(curdate()) + 6 day
and dt < curdate() - interval dayofweek(curdate()) day
order by dt desc limit 1
) as 'last',
(
select wert01
from sml_splitt
where dt >= curdate() - interval dayofweek(curdate()) + 6 day
and dt < curdate() - interval dayofweek(curdate()) day
order by dt limit 1
) as 'first'
) t1
;
If you really want to work with this data by week for reporting purposes, let me suggest a couple of views. The first will give you all of your distinct beginning of week dates:
create view v1 as
select date(dt) as week_begins
from sml_splitt
where dayofweek(dt) = 1
group by week_begins
The second view joins the first view with itself to give you a week beginning and week ending range:
create view v2 as
select t1.week_begins, coalesce(t2.week_begins,now()) as week_ends
from v1 t1
left join v1 t2
on t2.week_begins = t1.week_begins + interval 7 day
You can see the results here: http://sqlfiddle.com/#!9/a4d1b3/2. Notice that I'm using now() to get the current date and time if the week hasn't ended yet.
From there you can join your view with your original table and use min() and max() function with grouping to get the starting and ending 'wert' values and do any calculations on them that you like.
Here's an example: http://sqlfiddle.com/#!9/a4d1b3/6
select week_begins, week_ends,
min(wert01) as start_wert01,
max(wert01) as end_wert01,
max(wert01) - min(wert01) as power_consumed,
min(wert02) as start_wert02,
max(wert02) as end_wert02,
max(wert02) - min(wert02) as power_generated,
(max(wert02) - min(wert02)) - (max(wert01) - min(wert01)) as net_generated
from v2
inner join sml_splitt
on sml_splitt.dt >= v2.week_begins
and sml_splitt.dt < v2.week_ends
group by week_begins
I hope that helps.
I have this SQL statement. It works, and I need to add another one condition.
I need to sort it by date. occurence - is my date row.
SELECT dd.caption, COUNT(t.occurence)
FROM transaction t
INNER JOIN dict_departments dd
ON dd.id = t.terminal_id
GROUP BY dd.caption
How to add this condition:
WHERE t.occurence BETWEEN (CURRENT_DATE() - INTERVAL 1 MONTH)
to my query.
Try this:
WHERE t.occurrece BETWEEN current_date() AND dateadd(month,1,current_date())
The function dateadd is a SQL SERVER function, but the rest of the clause is standard SQL.
BETWEEN requires two arguments, a start point and an end point. If your end point is the current time, you have two options:
Using BETWEEN:
WHERE t.occurence BETWEEN (CURRENT_DATE() - INTERVAL 1 MONTH) AND NOW()
Using simple comparison operator:
WHERE t.occurence >= (CURRENT_DATE() - INTERVAL 1 MONTH)
If you want to filter dates from 1 month ago till now:
WHERE (t.occurrece BETWEEN DATE_ADD(CURDATE(), INTERVAL -1 MONTH) AND CURDATE()) = 1
or
WHERE (t.occurrece BETWEEN ADDATE(CURDATE(), INTERVAL -1 MONTH) AND CURDATE()) = 1
I'm trying to select all the data from the previous month to all the months in the future .. for example , I'd like to select everything from January till any date available in the future on the database, that goes for any month .. select the previous month till the future months of this year
This is my QUERY, It only starts with February , how can I make it start with the previous month .. current month - 1 is not working
SELECT *
FROM events
WHERE YEAR(event_start_date) = YEAR(CURDATE())
AND MONTH(event_start_date) = MONTH(CURDATE())
use DATE_SUB() to select previous month and >= to select all data in the future:
SELECT *
FROM events
WHERE YEAR(event_start_date) = YEAR(CURDATE())
AND MONTH(event_start_date) >= MONTH(DATE_SUB( CURDATE(), INTERVAL 1 MONTH))
Try:
AND MONTH(event_start_date) = MONTH(DATE_SUB(CURDATE(), INTERVAL 1 MONTHS))
The portion DATE_SUB(CURDATE(), INTERVAL 1 MONTH) will subtract a month from the current date. If you want last month and everything in the future, use:
AND MONTH(event_start_date) >= MONTH(DATE_SUB(CURDATE(), INTERVAL 1 MONTHS))
Notice '>='. Although there is an edge case at january that you'll have to get around. The best way might be like this:
WHERE event_start_date >= DATE_SUB(DATE_SUB(CURDATE(), INTERVAL 1 MONTHS), (DAYOFMONTH(CURDATE)) DAYS)
Which will get you everything from the 1st of last month. No edge cases.
Try this
SELECT *
FROM events
WHERE YEAR(event_start_date) = YEAR(CURDATE())
AND MONTH(event_start_date) >= MONTH(CURDATE() - INTERVAL 1 MONTH);
SELECT *
FROM events
WHERE event_start_date >= '1/'+MONTH(DATE_SUB( CURDATE(), INTERVAL 1 MONTH))+'/'+YEAR(DATE_SUB( CURDATE(), INTERVAL 1 MONTH))
For performance, you'd likely want an index range scan operation on the event_start_date column. That means (obviously), you'd want an index with event_start_date as a leading column.
To get an index range scan, the predicate needs to be on the bare event_start_date column, and NOT a function.
WHERE event_start_date >= some_value
For "some_value" in this case, one possible expression you can use would be:
CAST(DATE_FORMAT(NOW()+INTERVAL -1 MONTH ,'%Y-%m-01') AS DATE)
That takes the current date and time, subtracts one month, and then sets the day and time component to midnight of the first of the month.
I have a table containing data about events and festivals with following columns recording their start and end dates.
Start_Date
End_Date
date format is in YYYY-MM-DD. I need to fetch event details with the following condition.
Need to fetch all events which start with a current month and there end dates can be anything say currentDate+next30days.
I am clear about end date concept. but not sure how I can fetch data whose start dates are in a current month.
For this, I need to compare current year and current month against the Start_Date column in my database.
Can anyone help me to point out as how I can do that?
select * from your_table
where year(Start_Date) = year(curdate())
and month(Start_Date) = month(curdate())
and end_date <= curdate() + interval 30 day
I don't like either of the other two answers, because they do not let the optimizer use an index on start_date. For that, the functions need to be on the current date side.
So, I would go for:
where start_date >= date_add(curdate(), interval 1 - day(curdate()) day) and
start_date < date_add(date_add(curdate(), interval 1 - day(curdate()) day), interval 1 month)
All the date functions are on curdate(), which does not affect the ability of MySQL to use an index in this case.
You can also include the condition on end_date:
where (start_date >= date_add(curdate(), interval 1 - day(curdate()) day) and
start_date < date_add(date_add(curdate(), interval 1 - day(curdate()) day), interval 1 month)
) and
end_date <= date_add(curdate(), interval 30 day)
This can still take advantage of an index.
DateTime functions are your friends:
SELECT
*
FROM
`event`
WHERE
(MONTH(NOW()) = MONTH(`Start_Date`))
AND
(`End_Date` <= (NOW() + INTERVAL 30 DAY))
AND
(YEAR(NOW()) = YEAR(`Start_Date`))
Comparing the year and month separately feels messy. I like to contain it in one line. I doubt it will make a noticeable difference in performance, so its purely personal preference.
select * from your_table
where LAST_DAY(Start_Date) = LAST_DAY(curdate())
and end_date <= curdate() + interval 30 day
So all I'm doing is using the last_day function to check the last day of the month of each date and then comparing this common denominator. You could also use
where DATE_FORMAT(Start_Date ,'%Y-%m-01') = DATE_FORMAT(curdate(),'%Y-%m-01')