How to use validation when i use duplicate key update - mysql

When I Use duplicate key update
INSERT INTO test_table (name, age, date)
VALUES (Kevin, 20, now)
ON DUPLICATE KEY UPDATE name = VALUES(name),
age = VALUES(age),
date = VALUES(date)
I want to compare with existing value for validation
How can I do?
I have tried some method
where date < VALUES(date)
But all of method are syntax error
Thanks for reading

Try using CASE EXPRESSION :
INSERT INTO test_table (name, age, date)
VALUES (Kevin, 20, now)
ON DUPLICATE KEY
UPDATE name = CASE WHEN `date`< values(`date`) THEN VALUES(name) ELSE name end,
age= CASE WHEN `date`< values(`date`) THEN VALUES(age) ELSE age end,
`date`= CASE WHEN `date`< values(`date`) THEN VALUES(date) ELSE `date` end

INSERT INTO test_table (name, age, date)
VALUES (Kevin, 20, now)
ON DUPLICATE KEY UPDATE age = IF(`date` < values(`date`), values(age), age),
name = IF(`date` < values(`date`), values(name), name),
date = IF(`date` < values(`date`), values(date), date)

Related

Week date range

There is a table objects, which stores data on real estate objects. Me need to use a query to calculate a new field that will display the date range from Monday to Sunday, which includes the date the object was created (for example, “2020-11-16 - 2020-11-22”)
create table objects(
object_id int NOT NULL PRIMARY KEY ,
city_id int not null ,
price int ,
area_total int ,
status varchar(50) ,
class varchar(50) ,
action varchar(50) ,
date_create timestamp,
FOREIGN KEY(city_id) references avg_price_square_city(city_id)
);
Data in the table:
INSERT INTO objects (object_id, city_id, price, area_total, status, class, action, date_create)
VALUES (1, 1, 4600000, 72, 'active', 'Secondary', 'Sale', '2022-05-12 21:49:34');
INSERT INTO objects (object_id, city_id, price, area_total, status, class, action, date_create)
VALUES (2, 2, 5400000, 84, 'active', 'Secondary', 'Sale', '2022-05-19 21:49:35');
The query should display two fields: the object number and a range that includes the date it was created. How can this be done ?
P.S
I wrote this query,but he swears at the "-" sign:
SET #WeekRangeStart ='2022/05/10';
SET #WeekRangeEnd = '2022/05/17';
select object_id,#range := #WeekRangeStart '-' #WeekRangeEnd
FROM objects where #range = #WeekRangeStart and date_create between #WeekRangeStart and #WeekRangeEnd
UNION
select object_id,#range from objects where #`range` = #WeekRangeEnd;
Error:[42000][1064] You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '#WeekRangeEnd FROM objects where #range = #WeekRangeStart and date_create betwee' at line 1
I want to receive in query:
object_id #range
1 2022/05/10 - 2022/05/17
The column #range must contain the date from the "date_create"
SET #WeekRangeStart = CAST('2022/05/10' as DATE);
SET #WeekRangeEnd = CAST('2022/05/17' as DATE);
SET #range = CONCAT(#WeekRangeStart,' - ',#WeekRangeEnd) ;
-- select #range;
select
object_id,
#range
FROM objects
where DATE(date_create) between #WeekRangeStart and #WeekRangeEnd
UNION
select object_id,#range from objects
;
Gives next result:
object_id
#range
1
2022-05-10 - 2022-05-17
2
2022-05-10 - 2022-05-17
This result is the output of the SQL part that is put after the UNION. Because date_create is not between your WeekRangeStart and WeekRangeEnd.
You should take some time, and read the UNION documentation.
The variable #range is calculated before the SQL statement, because the value is a constant.
see: DBFIDDLE
NOTE: You should try to use the same dateformat everywhere, and not mix date like '2022-05-19 21:49:35' and 2022/05/10. Use - OR use /, but do not mix them...
EDIT: After the calirification "Me need to use a query to calculate a new field that will display the date range from Monday to Sunday,...":
You probably wanted to do:
SET #WeekDate = CAST('2022/05/10' as DATETIME);
SELECT
ADDDATE(#WeekDate, -(DAYOFWEEK(#WeekDate)-1) +1) as Monday,
DATE_ADD(ADDDATE(#WeekDate, -(DAYOFWEEK(#WeekDate)-1) +9), INTERVAL -1 SECOND) as Sunday;
output:
Monday
Sunday
2022-05-09 00:00:00
2022-05-16 23:59:59

SQL IF exist date by day do increment update else insert data

How can I express the below statement as a SQL query ?
IF EXISTS (SELECT * FROM expense_history
WHERE user_id = 40
AND DATE_FORMAT(expense_history.created_date , '%Y-%m-%d') = '2018-06-02'
AND camp_id='80')
UPDATE expense_history
SET clicks = clicks + 1,
amount = amount + 1
WHERE user_id = 40
AND DATE_FORMAT(expense_history.created_date, '%Y-%m-%d') = '2018-06-02'
AND camp_id = '80'
ELSE
INSERT INTO expense_history (camp_id, created_date, amount, user_id)
VALUES ('80', '2018-06-02 12:12:12', '1', '40')
END IF;
I just want to do increment clicks and amount if is set by day, else I want to add new row.
This is very tricky in MySQL. You are storing a datetime but you want the date part to be unique.
Starting in MySQL 5.7.?, you can use computed columns for the unique constraint. Here is an example:
create table expense_history (
user_id int,
camp_id int,
amount int default 0,
clicks int default 1,
. . .
created_datetime datetime, -- note I changed the name
created_date date generated always as (date(created_datetime)),
unique (user_id, camp_id, created_datetime)
);
You can then do the work as:
INSERT INTO expense_history (camp_id, created_datetime, amount, user_id)
VALUES (80, '2018-06-02 12:12:12', 1, 40)
ON DUPLICATE KEY UPDATE
amount = COALESCE(amount + 1, 1),
clicks = COALESCE(clicks + 1, 1);
Earlier versions of MySQL don't support generated columns. Nor do they support functions on unique. But you can use a trick on a prefix index on a varchar to do what you want:
create table expense_history (
user_id int,
camp_id int,
amount int default 0,
clicks int default 1,
. . .
created_datetime varchar(19),
unique (created_datetime(10))
);
This has the same effect.
Another alternative is to store the date and the time in separate columns.
I presumed your database is mysql, because of DATE_FORMAT() function(and edited your question as to be).
So, by using such a mechanism below, you can do what you want,
provided that a COMPOSITE PRIMARY KEY for camp_id, amount, user_id columns :
SET #camp_id = 80,
#amount = 1,
#user_id = 40,
#created_date = sysdate();
INSERT INTO expense_history(camp_id,created_date,amount,user_id,clicks)
VALUES(#camp_id,#created_date,#amount,#user_id,ifnull(clicks,1))
ON DUPLICATE KEY UPDATE
amount = #amount + 1,
clicks = ifnull(clicks,0)+1;
SQL Fiddle Demo

MysQL Update if a count condition is met

I have a table which consists of 5000 rows. I need SQL command that could update each row by removing all values in "(...)" if only one couple of () is found.
Basically, if I have a name in a row:
Name surname (extra info)
I need to remove "(extra info)" and leave only Name surname
But if there is no additional couple of ()
If there is a row
Name Surname(data) (extra info)
The script should not amend this name
In simple words, I need to update a name where is only one ( or ) symbol
Many thanks
can you try to find first '(' and substring to it ?
don't forget to use case for none ( in string
update userlogin
set fullname = case position('(' in FullName)
when 0
then fullname
else substring(Fullname,1,position('(' in FullName) - 1)
end
This is an implementation of my question. I used select to let me check the result before applying it to update request. The script shows a table of
3 columns: Id, Name, UpdatedName, where Name is what we have and UpdatedName what we will obtain
SELECT `Id`,`Name`,
(case when ((LENGTH(`Name`)-LENGTH(REPLACE(`Name`, '(', ''))) = 1)
THEN
SUBSTRING_INDEX(`Name`, '(', 1)
ELSE
'-'
END)
as updated_name,
FROM table
WHERE (LENGTH(`Name`)-LENGTH(REPLACE(`Name`, '(', ''))) = 1
LIMIT 0,1500
P.S. I used Id to allow me to amend values
SELECT CASE
WHEN fname = 'correct' THEN 'your condition'
WHEN sname = 'correct' THEN 'your second condition'
ELSE 'baz'
END AS fullname
FROM `databasetable`
or you can do as like also
CASE
WHEN action = 'update' THEN
UPDATE sometable SET column = value WHERE condition;
WHEN action = 'create' THEN
INSERT INTO sometable (column) VALUES (value);
END CASE

Insert multiple rows from select result

For a database fix I have to perform I need to do an insert for every ID this query results;
SELECT Id FROM role WHERE id != 99 AND Id NOT IN (SELECT RoleId FROM permissionaction WHERE PermissionId = 19);
So it results some ID's which have to be added with this query.
INSERT INTO permissionaction (AccessLevel, PermissionId, ControllerActionId, Active, CreatedOn, ModifiedOn, CreatedById, ModifiedById, RoleId) VALUES (1, 19, 1, 1, Now(), Now(), 1, 1, *******ID HERE******);
I know it can be done with using mysql cursors but it's not a possibility here. Is there a way to add all of the resulting ID's in one query?
Thanks
Use INSERT...SELECT:
INSERT INTO permissionaction (AccessLevel, PermissionId, ControllerActionId, Active, CreatedOn, ModifiedOn, CreatedById, ModifiedById, RoleId)
SELECT 1, 19, 1, 1, Now(), Now(), 1, 1, Id
FROM role
WHERE id != 99
AND Id NOT IN (SELECT RoleId FROM permissionaction WHERE PermissionId = 19);
With INSERT...SELECT you can add values to the table permissionaction for each returned row of the SELECT query.

INSERT SELECT MAX connected with text

I want to insert to type field max id from other table but I need to connect it with text information as "Created new user with id = "MAX(my_employee.id). Code that work but insert only id:
INSERT INTO my_logs (user_id, type, date)
SELECT '1', MAX(my_employee.id), '2013-05-28 23:52:07' FROM my_employee
I tried:
INSERT INTO my_logs (user_id, type, date)
SELECT '1',"Created new user with id =" MAX(my_employee.id),
'2013-05-28 23:52:07' FROM my_employee
and similar but nothing seems to work
Are you trying to do this?
INSERT INTO my_logs (user_id, type, date)
SELECT '1', concat('Created new user with id =', MAX(my_employee.id)),
'2013-05-28 23:52:07'
FROM my_employee;
This should work for you:
insert into my_logs
select 1, concat('Created new user with id = ', MAX(id)), '2013-05-28 23:52:07'
from my_employee
SQL Fiddle Demo