I have this query for calculating sums of values per every year based on a date.
It works, but it is heavy, takes a minute to 2 minutes running on about 10k records
Is there a way to optimize this, or write it in a more efficient way?
"select departments sum(case when year(employment_date) = '1990' then 1 else 0 end) as '1990',"
+ "sum(case when year(employment_date) = '2010' then 1 else 0 end) as '2010',"
+ "sum(case when year(employment_date) = '2011' then 1 else 0 end) as '2011',"
+ "sum(case when year(employment_date) = '2012' then 1 else 0 end) as '2012',"
+ "sum(case when year(employment_date) = '2013' then 1 else 0 end) as '2013',"
+ "sum(case when year(employment_date) = '2014' then 1 else 0 end) as '2014',"
+ "sum(case when year(employment_date) = '2015' then 1 else 0 end) as '2015',"
+ "sum(case when year(employment_date) = '2016' then 1 else 0 end) as '2016',"
+ " count(departments.dept_id) as Total "
+ "from employees inner join departments on employees.employee_id=departments.employee_id AND departments.dept_id = ?";
sample resuts
|departments | Total | 2010 | 2011 | 2012 | 2013 | 2014 | 2015 | 2016 |
|Data systems | 100 | 30 | 10 | 5 | 15 | 20 | 12 | 8 |
|Social ssmp | 70 | 10 | 10 | 15 | 15 | 4 | 6 | 10 |
In mysql, the one of best way to improve the query performance is indexing.The whole point of having an index is to speed up search queries by essentially cutting down the number of records/rows in a table that need to be examined.
CREATE INDEX Emp_index ON Employee (Employment_Date, Employee_Id);
CREATE INDEX Dept_index ON Departments(Departments , Dept_Id );
Please refer link for more info.
Just a quick suggestion.. As indexing costs you additional writes and storage space, so if your application requires more insert/update operation, you might want to use tables without indexes, but if it requires more data retrieval operations, you should go for indexed table.
give this a shot and see if it's any faster.
select sum(case when employment_year = '1990' then employee_count else 0 end) as '1990',
sum(case when employment_year = '2010' then employee_count else 0 end) as '2010',
sum(case when employment_year = '2011' then employee_count else 0 end) as '2011',
sum(case when employment_year = '2012' then employee_count else 0 end) as '2012',
sum(case when employment_year = '2013' then employee_count else 0 end) as '2013',
sum(case when employment_year = '2014' then employee_count else 0 end) as '2014',
sum(case when employment_year = '2015' then employee_count else 0 end) as '2015',
sum(case when employment_year = '2016' then employee_count else 0 end) as '2016',
sum(employee_count) as Total
from
(select * from
(select count(*) as employee_count,year(employment_date) as employment_year
from employees inner join departments on employees.employee_id=departments.employee_id AND departments.dept_id = 1
group by year(employment_date)
)T1
where employment_year = 1990
or employment_year between 2010 and 2016
)T2;
sqlfiddle
Just change departments.dept_id = 1 to whatever dep_id you're looking for.
Related
Could i calc for each row column Profit ?
SELECT
SUM(CASE WHEN m.billable = 0 THEN r.rate ELSE 0 END) AS Revenue, -- 33 + 34 + 456 + 52...etc = 5500
SUM(CASE WHEN m.billable = 1 AND m.optimized = 0 THEN r.rate ELSE 0 END) AS Costs,-- 33 + 4...etc = 339
5500 - 339 AS Profit -- I need to get this difference
FROM messages AS m
JOIN rates AS r ON (r.id = m.rate_id )
GROUP BY
m.client_account_id,
m.mcc,
m.mnc
I want to get
| Revenue | Costs | Profit
5500 500 5000
Move your query into a subquery, then subtract the results.
SELECT Revenue, Costs, Revenue - Costs AS Profit
FROM (
SELECT
SUM(CASE WHEN m.billable = 0 THEN r.rate ELSE 0 END) AS Revenue,
SUM(CASE WHEN m.billable = 1 AND m.optimized = 0 THEN r.rate ELSE 0 END) AS Costs
FROM YourTable) AS x
Joining your two tables, and showing the results grouped by account, it would be:
SELECT client_account_id, mmc, mnc, Revenue, Costs, Revenue - Costs AS Profit
FROM (
SELECT
m.client_account_id, m.mmc, m.mnc
SUM(CASE WHEN m.billable = 0 THEN r.rate ELSE 0 END) AS Revenue,
SUM(CASE WHEN m.billable = 1 AND m.optimized = 0 THEN r.rate ELSE 0 END) AS Costs
FROM messages AS m
JOIN rates AS r ON r.id = m.rate_id
GROUP BY m.client_account_id, m.mmc, m.mnc
) AS x
Simply put it in a sub query :
SELECT Revenue - Costs as Profit
FROM (
SELECT
SUM(CASE WHEN m.billable = 0 THEN r.rate ELSE 0 END) AS Revenue,
SUM(CASE WHEN m.billable = 1 AND m.optimized = 0 THEN r.rate ELSE 0 END) AS Costs
) as temp
I have two dates, say start_date is 20141215 and end_date = 20150115. I would like to use SQL DATEDIFF to only count the dates within the year 2015 which I will specify in the query. Here is the current SQL I have written:
SELECT COUNT(leave_id),
sum(case when leave_status = 1 then 1 else 0 end) pending,
sum(case when leave_status = 2 then 1 else 0 end) declined,
sum(case when leave_status = 3 then 1 else 0 end) approved,
sum(case when leave_status = 4 then 1 else 0 end) rostered,
SUM(DATEDIFF(end_date, start_date)+1) as datetotals
FROM employee_leave WHERE
((YEAR(start_date) = :year) OR (YEAR(end_date) = :year))
AND employee_id = :emp_id
Thanks
You need to fix datediff() to only consider dates during the year. I think this does what you want:
SELECT COUNT(leave_id),
sum(case when leave_status = 1 then 1 else 0 end) pending,
sum(case when leave_status = 2 then 1 else 0 end) declined,
sum(case when leave_status = 3 then 1 else 0 end) approved,
sum(case when leave_status = 4 then 1 else 0 end) rostered,
SUM(DATEDIFF(least(end_date, date(concat_ws('-', :year, 12, 31))),
greatest(start_date, date(concat_ws('-', :year, 1, 1)))
) + 1) as datetotals
FROM employee_leave
WHERE ((YEAR(start_date) = :year) OR (YEAR(end_date) = :year)) AND
employee_id = :emp_id
Make it a AND condition rather like
WHERE
((YEAR(start_date) = :year) AND (YEAR(end_date) = :year))
I have a table with payment:
worker_id, amount, payed, date
Table workers:
id, name, lname
I need to write SQL that will give me name, lname and sum for jun, july, august, september.
Name | Lname | Sum_JUN | Sum_JULY | Sum_AUG | Sum_SEP
I'm trying with subqueries but can't do it. Can you help me?
I created SQL (example). I will replace dates in PHP.
select w.name, w.lname,
sum(case when p.payed_date between '2014-06-01' and '2014-06-31' then p.amount else 0 end) `sum_june`,
sum(case when p.payed_date between '2014-07-01' and '2014-07-31' then p.amount else 0 end) `sum_july`,
sum(case when p.payed_date between '2014-08-01' and '2014-08-31' then p.amount else 0 end) `sum_august`,
sum(case when p.payed_date between '2014-09-01' and '2014-09-31' then p.amount else 0 end) `sum_september`,
sum(case when p.payed_date between '2014-10-01' and '2014-10-31' then p.amount else 0 end) `sum_november`
from worker w
left join worker_sum p on(w.id = p.worker_id)
group by w.id
You can use conditional aggregation for your desired sum,But this will give you the sum for months from all years exist in your table
select w.*,
sum(case when month(p.date) = 6 then p.amount else 0 end) `sum_june`,
sum(case when month(p.date) = 7 then p.amount else 0 end) `sum_july`,
sum(case when month(p.date) = 8 then p.amount else 0 end) `sum_august`,
sum(case when month(p.date) = 9 then p.amount else 0 end) `sum_september`
from workers w
left join payment p on(w.id = p.worker_id)
group by w.id
how can I achieve the desired result in mysql if my table looks like this.
result|year
1 |2011
2 |2011
1 |2011
0 |2011
1 |2012
2 |2012
1 = Won, 2 = lost, 0 = draw
Every year can have multiple values like this. Not sure how I can get the desired result like below.
year won lost draw totalPlayed
2011 2 1 1 3
2012 1 1 0 2
I have tried the following query but does not get the desired result
select year,
league_types.league_name,
sum(if(result = 1,1,0)) as won,
sum(if(result = 0,1,0)) as draw,
sum(if(result = 4,1,0)) as noResult,
sum(if(result = 2,1,0)) as lost,
sum(if(result = 3,1,0)) as tied,
sum(if(result > 0 and result < 4,1,0)) as played
from match_score_card
inner join fixtures on match_score_card.match_id = fixtures.match_id
inner join league_types on fixtures.league_id = league_types.league_id
where
team_id = 1 group by year order by year desc
Here is the SQL Fiddle that demonstrates the following query:
SELECT m.year,
SUM(CASE WHEN m.result = 1 THEN 1 ELSE 0 END) AS 'Won',
SUM(CASE WHEN m.result = 2 THEN 1 ELSE 0 END) AS 'Lost',
SUM(CASE WHEN m.result = 0 THEN 1 ELSE 0 END) AS 'Draw',
COUNT(*) AS 'TotalPlayed'
FROM MyTable AS m
GROUP BY m.year
I'm not familiar with that IF function in mySQL, but this standard SQL should work:
select year
, league_types.league_name
, sum(CASE WHEN result = 1 THEN 1 ELSE 0 END) as won
, sum(CASE WHEN result = 2 THEN 1 ELSE 0 END) as lost
, sum(CASE WHEN result = 3 THEN 1 ELSE 0 END) as draw
, sum(CASE WHEN result = 4 THEN 1 ELSE 0 END) as noResult
, sum(CASE WHEN result = 1
or result = 2 THEN 1 ELSE 0 END) as played
from match_score_card
inner join fixtures
on match_score_card.match_id = fixtures.match_id
inner join league_types
on fixtures.league_id = league_types.league_id
where team_id = 1
group by year, league_types.league_name
order by year desc, league_types.league_name
I'm guessing that you only want to count wins and losses as "played".
I have 3 tables; contracts, dealers, and users.
users have many dealers and dealers have many contracts but the contracts are not directly associated with the users.
I am trying to build a report that gets me a monthly count of completed contracts grouped by user for the last 12 months.
So far I have built a multiple subquery, which is very slow: SQL Fiddle
SELECT *,
( SELECT count(*) FROM contracts
WHERE
dealer_id IN
( SELECT id FROM dealers WHERE user_id = User.id )
AND status = 'Paid'
AND completion_date BETWEEN
'2012-08-01 00:00:00' AND '2012-08-31 23:59:59'
) AS Aug_2012,
( SELECT count(*) FROM contracts
WHERE
dealer_id IN
( SELECT id FROM dealers WHERE user_id = User.id )
AND status = 'Paid'
AND completion_date BETWEEN
'2012-09-01 00:00:00' AND '2012-09-30 23:59:59'
) AS Sep_2012
FROM users AS User
WHERE
id IN( SELECT user_id FROM dealers WHERE active = 1 AND user_id IS NOT NULL GROUP BY user_id )
AND id != 1
ORDER BY User.name ASC
Instead of the subquery which selects each month I'd like to use something like this:
COUNT(*) as last_12_months,
SUM(case when MONTH(completion_date) = 8 then 1 else 0 end) as Aug_2012,
SUM(case when MONTH(completion_date) = 9 then 1 else 0 end) as Sep_2012,
etc.
Since I'd be returning multiple columns I would have to restructure it, but I'm not sure how. If I use an INNER JOIN what clause do I join on?
Here's the final query based on Mikhail's answer below:
SELECT
User.*,
SUM(case when MONTH(completion_date) = 8 then 1 else 0 end) AS Aug_2012,
SUM(case when MONTH(completion_date) = 9 then 1 else 0 end) AS Sep_2012,
SUM(case when MONTH(completion_date) = 10 then 1 else 0 end) AS Oct_2012,
SUM(case when MONTH(completion_date) = 11 then 1 else 0 end) AS Nov_2012,
SUM(case when MONTH(completion_date) = 12 then 1 else 0 end) AS Dec_2012,
SUM(case when MONTH(completion_date) = 1 then 1 else 0 end) AS Jan_2013,
SUM(case when MONTH(completion_date) = 2 then 1 else 0 end) AS Feb_2013,
SUM(case when MONTH(completion_date) = 3 then 1 else 0 end) AS Mar_2013,
SUM(case when MONTH(completion_date) = 4 then 1 else 0 end) AS Apr_2013,
SUM(case when MONTH(completion_date) = 5 then 1 else 0 end) AS May_2013,
SUM(case when MONTH(completion_date) = 6 then 1 else 0 end) AS Jun_2013,
SUM(case when MONTH(completion_date) = 7 then 1 else 0 end) AS Jul_2013,
SUM(case when completion_date BETWEEN '2012-08-01 00:00:00' AND '2013-07-31 23:59:59' then 1 else 0 end) as last_12_months
FROM users AS User
LEFT OUTER JOIN
(
SELECT id, user_id FROM dealers
WHERE active = 1 AND user_id IS NOT NULL
) AS Dealer ON User.id = Dealer.user_id
LEFT OUTER JOIN
(
SELECT completion_date, status, dealer_id FROM contracts
WHERE completion_date BETWEEN '2012-08-01 00:00:00' AND '2013-07-31 23:59:59' AND status = 'Paid' AND cancelled = 0
) AS Contract on Dealer.id = Contract.dealer_id
WHERE
User.id IN
(
SELECT user_id FROM dealers
WHERE active = 1 AND user_id IS NOT NULL
GROUP BY user_id
)
GROUP BY
User.id order by User.name asc
This is about 4 times faster.
Try this:
select
User.id, User.name,
sum(case when MONTH(completion_date) = 8 and Year(completion_date)=2012 then 1 else 0 end) as Aug_2012,
sum(case when MONTH(completion_date) = 9 and Year(completion_date)=2012 then 1 else 0 end) as Sep_2012,
sum(case when MONTH(completion_date) = 10 and Year(completion_date)=2012 then 1 else 0 end) as Oct_2012,
sum(case when MONTH(completion_date) = 11 and Year(completion_date)=2012 then 1 else 0 end) as Nov_2012,
sum(case when MONTH(completion_date) = 12 and Year(completion_date)=2012 then 1 else 0 end) as Dec_2012,
sum(case when MONTH(completion_date) = 1 and Year(completion_date)=2013 then 1 else 0 end) as Jan_2012,
sum(case when MONTH(completion_date) = 2 and Year(completion_date)=2013 then 1 else 0 end) as Feb_2012,
sum(case when MONTH(completion_date) = 3 and Year(completion_date)=2013 then 1 else 0 end) as Mar_2012,
sum(case when MONTH(completion_date) = 4 and Year(completion_date)=2013 then 1 else 0 end) as Apr_2012,
sum(case when MONTH(completion_date) = 5 and Year(completion_date)=2013 then 1 else 0 end) as May_2012,
sum(case when MONTH(completion_date) = 6 and Year(completion_date)=2013 then 1 else 0 end) as Jun_2012,
sum(case when MONTH(completion_date) = 7 and Year(completion_date)=2013 then 1 else 0 end) as Jul_2012
from users AS User
left outer join dealers on
User.id=dealers.user_id
left outer join contracts on
dealers.id=contracts.dealer_id
group by
User.id,
contracts.status
having
contracts.status='Paid'
order by
User.name asc;