I'm modifying a poorly designed website for a client. The original developer placed the same header code in every page which means editing all the individual files really isn't an option.
Here is a sample of the code.
<div class="col-md-3 text-left">
<img src="img/logo.png">
</div>
So it's pretty hard to edit that logo image because it doesn't even have a class attached to it..
Is there a way for me to make a CSS rule that will only apply to the first time the col-md-3 class is called and then edit that img.
Something like this:
img.col-md-3:first{
width:171px;
padding-bottom:10px;
margin:0 auto;
display:block;
}
How would I go about doing this?
Going with what you described:
div.col-md-3:first-of-type img {
width: 171px;
padding-bottom: 10px;
margin: 0 auto;
display: block;
/* For Testing */
outline: 3px solid red;
}
<div class="col-md-3 text-left">
<a href="index.html">
<img src="https://upload.wikimedia.org/wikipedia/commons/thumb/c/c9/Intel-logo.svg/2000px-Intel-logo.svg.png">
</a>
</div>
Note to the reader: Although in #ShivamPaw 's situation this snippet resolves the problem, keep in mind of what #disinfor has stated in that if div.col-md-3 were to be found in a new containing element, the image in that container will also be affected within the same page.
In #ShivamPaw 's description I'm assuming through context:
A header on each page.
logo.png
These factors lead me to the conclusion the solution I posted will work (and it did , fortunately)
You can use jquery if that possible using :first selector to add a class or direct css values:
$( ".col-md-3:first" ).find( "img" ).css( "width", "171px" ).css( "padding-bottom","10px").....;
or if this logo is only used in this place
$( "img[src='img/logo.png']").css( "width", "171px" ).css( "padding-bottom","10px").....;
Related
I have this code
<div class="mix category-1">
<a href="img/holder-01-large.png" class="photo">
<img src="img/holder-01-small.png alt="Ram - Srbija" class="img-small-1"></a>
Primer montaze
<a class="popup-youtube" href="https://www.youtube.com/watch?v=dz1kDQEHJaU">Video primer</a>
</div>
I want to replace this holder-01-small.png when hover over it with image with same dimensions. Is that possible by not touching this HTML code, just using CSS?
Yes it's possible, but not using the approach you have presented.
Instead, create a div (using an img tag here would mean we would need a transparent image to act as a placeholder, whereas a div will just work)
<div class="image"></div>
And in css try something like the below, you will need to specify a height and a width as the div will technically be empty, otherwise it will just collapse on itself.
.image {
background-image: url("path-to-file");
height: xx;
width: yy;
}
.image:hover {
background-image: url("path-to-different-file");
}
This div will then change it's background image.
It's possibly using this HTML, yes. (As long as you insert the missing quote after the src, that is!)
a.photo:hover img {
display: none
}
a.photo:hover::after {
content: url(http://lorempixel.com/100/100);
}
<div class="mix category-1">
<a href="img/holder-01-large.png" class="photo">
<img src="http://lorempixel.com/g/100/100" alt="Ram - Srbija" class="img-small-1" />
</a>
Primer montaze
<a class="popup-youtube" href="https://www.youtube.com/watch?v=dz1kDQEHJaU">Video primer</a>
</div>
Note that I changed the HTML to point to another image on the web in order to show something here in the snippet; hope you don't consider that to be cheating!
if you can place a div instead of an imgtag, you can add the background-imgproperty in css and then a hover. Something like this:
.img-small-1{
background-img: url('..img/holder-01-small.png');
width: 'your image's width';
height: 'your image's height';
}
.img-small-1:hover {
background-img: url('..img/myOtherImage.png');
}
I want to allow mobile site users to swipe/scroll through a list of icons.
The icons are div tags containing img tags.
The user should be able to swipe the container, scrolling/sliding the elements left or right.
The images need to slide smoothly with acceleration and deceleration.
Needs to work on iOS and Android.
We needed something like this sometime back, so I made a demo for it at that time. It's pretty basic, but it'll lay up all the ground work you need. First, lets start with the markup :
Markup
Since you mentioned jQM in the tag section of your question, Im gonna go with jQM [data-role=page] markup. You'd have a structure like this :
<div data-role="page">
<div data-role="header" data-theme="b">
<h1>Slideshow</h1>
</div>
<div data-role="content">
<div class="images">
<!--your images here -->
</div>
</div>
</div>
So you'd put all your images in the div with class=images. A particular group of images were encapsulated within a tags like this :
<a href="#">
<img src="25AC.jpg" />
</a>
<a href="#">
<img src="nature.jpg" />
</a>
<!--so on-->
You'd place this inside div.images. So that's about the markup we have.
CSS
The stylesheet part is simple.
.images {
height : 280px;
overflow-x: scroll;
overflow-y: hidden;
white-space: nowrap;
background-color : #272722;
}
.images a{
padding : 14px 5px 0px 5px;
margin: 5px 3px 0px 3px;
vertical-align: middle;
display: inline-block;
}
images img {
max-width: 100%;
max-height:512px;
}
Important properties to note here :
The overflow-x, overflow-y properties : The former needs to be enabled and the latter needs to be disabled. Only then the scroll will happen when you swipe right or left.
The white-space property : This is important to make the images come in a straight horizontal layout.
The max-width property : This is for scaling the images on mobile.
That's it! You're done!
Extras
I just added a popup to show the image when its tapped so that I'd be able to demonstrate the event handling. Here's the popup :
<div data-role="popup" id="popupInfo" data-overlay-theme="a" data-theme="b" data-corners="false">
Close
<div id="stuff"></div>
</div>
I'd be putting the image inside div#stuff when the a surrounding the img is clicked. Here's the JS :
//pageinit event of page
$(document).on("pageinit", "[data-role=page]", function() {
//cache popup for future use
var $popup = $("#popupInfo");
//click event for "a" tag inside .images
$(this).on("click", ".images > a[href=#]", function(e) {
//prevent default action
e.preventDefault();
//clone the image inside "a"
var $img = $(this).find("img").clone();
//add the cloned image inside #stuff
$popup.find("#stuff").html($img);
//open popup()
$popup.popup().popup("open");
});
});
Demo & Code
Demo & Code at jsbin.com
Alternatives
You could try out swipejs, which is jQuery plugin which will provide a much more sophisticated functionality. Here's the link to the site.
I have the following setup
<div id="outerDiv" style="width:100%;">
<div id="innerDiv">
<center>
<a href="http:/..." title="..">
<img src="http://...jpg" width="800" height="xxx" alt="..">
</a>
</center>
</div>
<div>
The width of the outerDiv can change based on browser view-port. Is there a way to restrict the width on the innerDiv just by using a style attribute, such that it overrides the included image width (800 in this example). Currently the image spans beyond the viewport and I would like the div/browser to shrink the image to the inner-div-size.
Am looking for something like:
<div id="outerDiv" style="width:100%;">
<div id="innerDiv" style="attribute:xxx;" or something similar>
<center>
<a href="http:/..." title="..">
<img src="http://...jpg" width="800" height="xxx" alt="..">
</a>
</center>
</div>
<div>
Please note that : the innerDiv is rendering 'variable' data coming from a stored parameter for instance. I only have control on the style on the innerDiv to make sure that things like 'center' or 'width' on the innerHtml does not go beyond what the outerDiv is setting. I have tried to use 'max-width' on the outer-div, but that didn't seem to work (I am not an expert on html/css - so I could have done it incorrectly).
Many thanks for all your help !
max-width property can help you.
Remove width attribute from img tag and write additional css code:
<style>
#innerDiv { text-align: center; width: 800px; }
#innerDiv a > img { display: inline-block; max-width: 100%; }
</style>
ComFreak has the complete answer.
Remove the center tag and instead add some css. Also add an id to that image if you want to target only that image specifically as far as its size.
#innerDiv {
max-width:800px;
margin:0 auto;}
img {/*use 'img#idOfimage' instead of 'img' if you end up adding an id to image */
width:100%;
height:0 auto;}
This should take care of it. You can put the css in a style tag in the header or better yet in a separate css file.
Don't use center tag. It defentinatly is outdated. Instead use margin: 0 auto; That will center the content. And use the max-width property for the innerDiv id. This is a great reference source. http://www.w3schools.com/cssref/pr_dim_max-width.asp
Here is what I am trying to accomplish in HTML/CSS:
I have images in different heights and widths, but they are all under 180x235. So what I want to do is create a div with border and vertical-align: middle them all. I have successfully done that but now I am stuck on how to properly a href link the entire div.
Here is my code:
<div id="parentdivimage" style="position:relative;width:184px;height:235px;border-width:2px;border-color:black;border-style:solid;text-align:center;">
<div id="childdivimage" style="position:absolute;top:50%;height:62px;margin-top:-31px;">
<img src="myimage.jpg" height="62" width="180">
</div>
</div>
Please note that for the sake of copy pasting here easily, the style code is inline.
I read somewhere that I can simply add another parent div on top of the code and then do a href inside that. However, based on some research it won't be valid code.
So to sum it up again, I need the entire div (#parentdivimage) to be a href link.
UPDATE 06/10/2014: using div's inside a's is semantically correct in HTML5.
You'll need to choose between the following scenarios:
<a href="http://google.com">
<div>
Hello world
</div>
</a>
which is semantically incorrect, but it will work.
<div style="cursor: pointer;" onclick="window.location='http://google.com';">
Hello world
</div>
which is semantically correct but it involves using JS.
<a href="http://google.com">
<span style="display: block;">
Hello world
</span>
</a>
which is semantically correct and works as expected but is not a div any more.
Why don't you strip out the <div> element and replace it with an <a> instead? Just because the anchor tag isn't a div doesn't mean you can't style it with display:block, a height, width, background, border, etc. You can make it look like a div but still act like a link. Then you're not relying on invalid code or JavaScript that may not be enabled for some users.
Do it like this:
Parentdivimage should have specified width and height, and its position should be:
position: relative;
Just inside the parentdivimage, next to other divs that parent contains you should put:
<span class="clickable"></span>
Then in css file:
.clickable {
height: 100%;
width: 100%;
left: 0;
top: 0;
position: absolute;
z-index: 1;
}
The span tag will fill out its parent block which is parentdiv, because of height and width set to 100%. Span will be on the top of all of surrounding elements because of setting z-index higher than other elements. Finally span will be clickable, because it's inside of an 'a' tag.
Going off of what Surreal Dreams said, it's probably best to style the anchor tag in my experience, but it really does depend on what you are doing. Here's an example:
Html:
<div class="parent-div">
Test
Test
Test
</div>
Then the CSS:
.parent-div {
width: 200px;
}
a {
display:block;
background-color: #ccc;
color: #000;
text-decoration:none;
padding:10px;
margin-bottom:1px;
}
a:hover {
background-color: #ddd;
}
http://jsbin.com/zijijuduqo/1/edit?html,css,output
Two things you can do:
Change #childdivimage to a span element, and change #parentdivimage to an anchor tag. This may require you to add some more styling to get things looking perfect. This is preffered, since it uses semantic markup, and does not rely on javascript.
Use Javascript to bind a click event to #parentdivimage. You must redirect the browser window by modifying window.location inside this event. This is TheEasyWayTM, but will not degrade gracefully.
I'm surprised no one suggested this simple trick so far! (denu does something similar though.)
If you want a link to cover an entire div, an idea would be to create an empty <a> tag as the first child:
<div class="covered-div">
<a class="cover-link" href="/my-link"></a>
<!-- other content as usual -->
</div>
div.covered-div {
position: relative;
}
a.cover-link {
position: absolute;
top: 0;
bottom: 0;
left: 0;
right: 0;
}
This works especially great when using <ul> to create block sections or slideshows and you want the whole slide to be a link (instead of simply the text on the slide). In the case of an <li> it's not valid to wrap it with an <a> so you'd have to put the cover link inside the item and use CSS to expand it over the entire <li> block.
Do note that having it as the first child means it will make other links or buttons inside the text unreachable by clicks. If you want them to be clickable, then you'd have to make it the last child instead.
In the case of the original question:
<div id="parentdivimage" style="position:relative;width:184px;height:235px;border-width:2px;border-color:black;border-style:solid;text-align:center;">
<a class="cover-link" href="/my-link"></a> <!-- Insert this empty link here and use CSS to expand it over the entire div -->
<div id="childdivimage" style="position:absolute;top:50%;height:62px;margin-top:-31px;">
<img src="myimage.jpg" height="62" width="180">
</div>
<!-- OR: it can also be here if the childdivimage divs should have their own clickable links -->
</div>
Make the div of id="childdivimag" a span instead, and wrap that in an a element. As the span and img are in-line elements by default this remains valid, whereas a div is a block level element, and therefore invalid mark-up when contained within an a.
put display:block on the anchor element. and/or zoom:1;
but you should just really do this.
a#parentdivimage{position:relative; width:184px; height:235px;
border:2px solid #000; text-align:center;
background-image:url("myimage.jpg");
background-position: 50% 50%;
background-repeat:no-repeat; display:block;
text-indent:-9999px}
<a id="parentdivimage">whatever your alt attribute was</a>
This can be done in many ways.
a. Using nested inside a tag.
<a href="link1.html">
<div> Something in the div </div>
</a>
b. Using the Inline JavaScript Method
<div onclick="javascript:window.location.href='link1.html' ">
Some Text
</div>
c. Using jQuery inside tag
HTML:
<div class="demo" > Some text here </div>
jQuery:
$(".demo").click( function() {
window.location.href="link1.html";
});
I simply do
onClick="location.href='url or path here'"
What I would do is put a span inside the <a> tag, set the span to block, and add size to the span, or just apply the styling to the <a> tag. Definitely handle the positioning in the <a> tag style. Add an onclick event to the a where JavaScript will catch the event, then return false at the end of the JavaScript event to prevent default action of the href and bubbling of the click. This works in cases with or without JavaScript enabled, and any AJAX can be handled in the Javascript listener.
If you're using jQuery, you can use this as your listener and omit the onclick in the a tag.
$('#idofdiv').live("click", function(e) {
//add stuff here
e.preventDefault; //or use return false
});
this allows you to attach listeners to any changed elements as necessary.
A link with <div> tags:
<div style="cursor: pointer;" onclick="window.location='http://www.google.com';">
Something in the div
</div>
A link with <a> tags:
<a href="http://www.google.com">
<div>
Something in the div
</div>
</a>
I have 3 links that represent the content for one iFrame in my page. When you click each link, it'll reload the contents of that iFrame without reloading the page.
how do i set the image of my link to change when it's active?
here's my code:
<div id="tabs">
<div id="overview">
<a id="overviewtab" target="tabsa" href="toframe.html">Overviews</a>
</div>
<div id="gallery">
<a target="tabsa" href="tawagpinoygallery.html">Gallery</a>
</div>
<div id="reviews">
<a target="tabsa" href="trframe.html">Reviews</a>
</div>
</div>
<div id="tabs-1">
<!--<div id="scroller">-->
<iframe name= "tabsa" width="95%" height="100%" frameborder="0"></iframe>
</div>
CSS code:
#gallery a {
text-indent: -9999px;
padding-top: 40px;
background: url(../images/GalleryTab.png) no-repeat;
height: 51px; width: 123px; position: absolute; z-index: 2;
}
#gallery a:active, a:hover {
text-indent: -9999px;
padding-top: 40px;
background: url(../images/galleryoverview.png) no-repeat;
height: 51px;
width: 123px;
position: absolute;
z-index: 2;
}
it doesn't seem to work.. :o i only see the change in image when i hold the mouse down on the link, but when i click it, the image remains the same as if it wasn't the active tab. :o thanks!!
I am not seeing a style for visited? Only active and hover.
add
#gallery a:visited{}
style and see if that helps.
But I wonder if that is what you are actually asking? You may want to link to be displayed differently from the other links if its the last link that the user clicked. To do that you may have to use some javascript.
For example, if you use jQuery you can do something like this:
$("#gallery a").click(function(){
$("#gallery a").removeClass("ActiveClass");
$(this).addClass("ActiveClass");
});
where ActiveClass is a CSS class for styling the link appropriately.
EDIT based on comment below.
Let us assume that you have three links that look the same (call that lookA). You click on one and it looks different from the other two (lookB) but the other two still looks the same (lookA). You then click on a second link. The second link is not lookB and the other two links are lookA. Does this sound like what you want? At least that is how I interpret your question.
Hence, create two classes in CSS:
.lookA {/*Style for lookA*/}
.lookB {/*Style for lookB*/}
of course you can use more meaningful names.
Then you can add a class to each of the links that you need to use in this scenario like this:
<div id="tabs">
<div id="overview">
<a class="imagelink lookA" id="overviewtab" target="tabsa" href="toframe.html">Overviews</a>
</div>
<div id="gallery">
<a class="imagelink lookA" target="tabsa" href="tawagpinoygallery.html">Gallery</a>
</div>
<div id="reviews">
<a class="imagelink lookA" target="tabsa" href="trframe.html">Reviews</a>
</div>
</div>
So that each link can be refered to by its class, that is, imagelink. Also each link has a default lookA.
Now in jQuery (I know you did not specify jQuery but using it is 100 times simpler than plain Javascript).:
$(document).ready(function(){
$(".imagelink").click(function(){
$(".imagelink").removeClass("lookB");
$(this).addClass("lookB");
return true;
});
});
So on click on the link, it removes lookB from any other link and applies it only to the clicked link.
Hope this helps a bit.
I believe the selector is:
#gallery a:focus {...}
This is (inevitably) applied variably across browsers, however.
Stu Nicholls has a demo over on CSS Play, this demo being to remove the default outline of the focussed element, and otherwise style the clicked element.
Presumably this would be more reliably effected with jQuery, but it can be done with CSS.