Having some trouble figuring out the best way to do this.
Here is what I'm trying to do:
SELECT
YEAR(t.voucher_date) as period,
COUNT(t.id) as total_count,
(SELECT COUNT(t2.id) FROM booking_global as t2 where t2.booking_status = 'CONFIRMED') as confirmed,
(SELECT COUNT(t3.id) FROM booking_global as t3 where t3.booking_status = 'PENDING') as pending
FROM booking_global t
GROUP BY YEAR(t.voucher_date)
This produces the below result.
period total_count CONFIRMED PENDING
2014 4 5 3
2015 4 5 3
Expected Result
period total_count CONFIRMED PENDING
2014 4 3 1
2015 4 2 2
Here i want to get CONFIRMED / PENDING count's for respective years, rather than getting count of all statuses.
I am not sure how to use my query as a sub query and run another query on the results.
Flowing should give you right rsult
SELECT
YEAR(t.voucher_date) as period,
COUNT(t.id) as total_count,
(SELECT COUNT(t2.id) FROM booking_global as t2 where t2.booking_status = 'CONFIRMED' and YEAR(t2.voucher_date) = YEAR(t.voucher_date)) as confirmed,
(SELECT COUNT(t3.id) FROM booking_global as t3 where t3.booking_status = 'PENDING' and YEAR(t3.voucher_date) = YEAR(t.voucher_date)) as pending
FROM booking_global t
GROUP BY YEAR(t.voucher_date)
You can have a subquery that calculates each booking_status for each year. The result of which is then joined on table booking_global. Example,
SELECT YEAR(t.voucher_date) voucher_date_year,
COUNT(t.id) total_count,
IFNULL(calc.confirmed_count, 0) confirmed_count,
IFNULL(calc.pending_count, 0) pending_count
FROM booking_global t
LEFT JOIN
(
SELECT YEAR(voucher_date) voucher_date_year,
SUM(booking_status = 'CONFIRMED') confirmed_count,
SUM(booking_status = 'PENDING') pending_count
FROM booking_global
GROUP BY YEAR(voucher_date)
) calc ON calc.voucher_date_year = YEAR(t.voucher_date)
GROUP BY YEAR(t.voucher_date)
Related
Below I cannot do Group by Date the following figures.
I have tried to put Group By in different lines, but not working.
SELECT SUM(a.NetAmount) AS TotalDonation
FROM (
SELECT
(
CASE WHEN bt.BalanceTransactionCurrencyID = 17
THEN bt.BalanceTransactionNet
ELSE
bt.BalanceTransactionNet * (SELECT TOP 1 ExrateValue FROM Exrate WHERE ExrateDate < bt.BalanceTransactionCreated AND bt.BalanceTransactionCurrencyID = CurrencyID ORDER BY ExrateDate Desc)
END
) AS NetAmount
FROM Charge as ch
JOIN BalanceTransaction as bt ON (ch.BalanceTransactionID = bt.BalanceTransactionID)
WHERE ch.ChargeCreatedDate BETWEEN '3-1-2019' AND '3-31-2019'
) AS a
I wanted to see:
Days Total Amount
March 1 xxxx
March 2 xxxx
March 3 xxx
MySQL does not use TOP. Use LIMIT:
SELECT ChargeCreatedDate, SUM(netamount)
FROM (SELECT ch.ChargeCreatedDate,
(CASE WHEN bt.BalanceTransactionCurrencyID = 17
THEN bt.BalanceTransactionNet
ELSE bt.BalanceTransactionNet * (SELECT e.ExrateValue
FROM Exrate e
WHERE e.ExrateDate < bt.BalanceTransactionCreated AND
e.CurrencyID = bt.BalanceTransactionCurrencyID
ORDER BY ExrateDate Desc
LIMIT 1
)
END) AS NetAmount
FROM Charge ch JOIN
BalanceTransaction bt
ON ch.BalanceTransactionID = bt.BalanceTransactionID
WHERE ch.ChargeCreatedDate BETWEEN '2019-03-01' AND '2019-03-31'
) chtbt
GROUP BY ChargeCreatedDate;
If you happen to be using SQL Server, you can replace the LIMIT 1 with FETCH FIRST 1 ROW ONLY.
The following code will hopefully display what you are looking for
SELECT a.Days AS Days, SUM(cast(a.NetAmount as decimal(16,9))) AS TotalDonation
FROM (
SELECT
(
CASE WHEN bt.BalanceTransactionCurrencyID = 17
THEN bt.BalanceTransactionNet
ELSE
bt.BalanceTransactionNet * (SELECT TOP 1 ExrateValue FROM Exrate WHERE ExrateDate < bt.BalanceTransactionCreated AND bt.BalanceTransactionCurrencyID = CurrencyID ORDER BY ExrateDate Desc)
END
) AS NetAmount,
ch.ChargeCreatedDate as Days
FROM Charge as ch
JOIN BalanceTransaction as bt ON (ch.BalanceTransactionID = bt.BalanceTransactionID)
WHERE ch.ChargeCreatedDate BETWEEN '3-1-2019' AND '3-31-2019'
) AS a GROUP BY a.Days
This should be sufficient. You need to SELECT the desired value in the query in order to get it to show up. Also when using the SUM() function you need to specify what the group value will be.
The formula in cell G2 "ReplenQty" is:
=SUMIFS(D:D,A:A,A2,B:B,B2,C:C,">=" & E2,C:C,"<=" &F2)
The formula in cell H2 "RpInVar" is:
=IF($A2<>$A1,ROUND(VAR(IF($A:$A=$A2,$G:$G)),2),0)
I attempted this in MySQL:
SELECT DISTINCT
Part,
Customer,
OrdDt,
OrdQty,
StartDate,
ReplenDate,
SUM(CASE WHEN Part = Part AND Customer = Customer AND OrdDt >= StartDate AND OrdDt <= ReplenDate THEN OrdQty ELSE 0 END) AS ReplenQty,
VARIANCE(CASE WHEN Part = Part AND Customer = Customer AND OrdDt >= StartDate AND OrdDt <= ReplenDate THEN OrdQty ELSE 0 END) AS RpInVar,
FROM
BeforeReplenQty
GROUP BY
Part,
Customer,
OrdDt,
OrdQty,
StartDate,
ReplenDate;
Problem is OrdQty and ReplenQty are the same and RpInVar are all 0.
This query is quite long and complicated but working on this demo: http://sqlfiddle.com/#!9/3b3334/70
One task is to do a sum where order date is between start date and replenish date.
Then get the row where part is new compared to previous row.
The first part of the query is to get the variance, the second subquery is to get the sum of Ordered qty and the sub-query at the bottom is to get the row where part column has changed.
select tab.Part,tab.Customer,tab.OrdDt,tab.OrdQty,tab.StartDate,tab.ReplenDate,tab.ReplenQty,
case when sumtab.Rnk=1 then
(select variance(ReplenQty)
from (select sum(t1.OrdQty) as ReplenQty
from BeforeReplenQty t2
inner join BeforeReplenQty t1
where t2.part=t1.part and t2.customer=t1.customer
and t2.OrdDt between t1.StartDate and t1.ReplenDate
group by t1.Part,t1.Customer,t1.OrdDt,t1.OrdQty,t1.StartDate,t1.ReplenDate) t3) else 0 end as ReplenVar
from (
select t1.*,sum(t1.OrdQty) as ReplenQty
from BeforeReplenQty t2
inner join BeforeReplenQty t1
where t2.part=t1.part and t2.customer=t1.customer
and t2.OrdDt between t1.StartDate and t1.ReplenDate
group by t1.Part,t1.Customer,t1.OrdDt,t1.OrdQty,t1.StartDate,t1.ReplenDate) tab
left join (select part,customer,orddt,rnk
from (
select t.part,t.customer,t.OrdDt,
#s:=CASE WHEN #c <> t.part THEN 1 ELSE #s+1 END AS rnk,
#c:=t.part AS partSet
from (SELECT #s:= 0) s
inner join (SELECT #c:= 'A') c
inner join (SELECT * from BeforeReplenQty
order by Part, Customer, OrdDt) t
) tab
where rnk = 1
) sumtab
on tab.part=sumtab.part and tab.customer=sumtab.customer and tab.orddt=sumtab.orddt;
I need to select how many days since there is a break in my data. It's easier to show:
Table format:
id (autoincrement), user_id (int), start (datetime), end (datetime)
Example data (times left out as only need days):
1, 5, 2011-12-18, 2011-12-18
2, 5, 2011-12-17, 2011-12-17
3, 5, 2011-12-16, 2011-12-16
4, 5, 2011-12-13, 2011-12-13
As you can see there would be a break between 2011-12-13 and 2011-12-16. Now, I need to be able say:
Using the date 2011-12-18, how many days are there until a break:
2011-12-18: Lowest sequential date = 2011-12-16: Total consecutive days: 3
Probably: DATE_DIFF(2011-12-18, 2011-12-16)
So my problem is, how can I select that 2011-12-16 is the lowest sequential date? Remembering that data applies for particular user_id's.
It's kinda like the example here: http://www.artfulsoftware.com/infotree/queries.php#72 but in the reverse.
I'd like this done in SQL only, no php code
Thanks
SELECT qmin.start, qmax.end, DATE_DIFF( qmax.end, qmin.start ) FROM table AS qmin
LEFT JOIN (
SELECT end FROM table AS t1
LEFT JOIN table AS t2 ON
t2.start > t1.end AND
t2.start < DATE_ADD( t1.end, 1 DAY )
WHERE t1.end >= '2011-12-18' AND t2.start IS NULL
ORDER BY end ASC LIMIT 1
) AS qmax
LEFT JOIN table AS t2 ON
t2.end < qmin.start AND
t2.end > DATE_DIFF( qmin.start, 1 DAY )
WHERE qmin.start <= '2011-12-18' AND t2.start IS NULL
ORDER BY end DESC LIMIT 1
This should work - left joins selects one date which can be in sequence, so max can be fineded out if you take the nearest record without sequential record ( t2.anyfield is null ) , same thing we do with minimal date.
If you can calculate days between in script - do it using unions ( eg 1. row - minimal, 2. row maximal )
Check this,
SELECT DATEDIFF((SELECT MAX(`start`) FROM testtbl WHERE `user_id`=1),
(select a.`start` from testtbl as a
left outer join testtbl as b on a.user_id = b.user_id
AND a.`start` = b.`start` + INTERVAL 1 DAY
where a.user_id=1 AND b.`start` is null
ORDER BY a.`start` desc LIMIT 1))
DATEDIFF() show difference of the Two days, if you want to number of consecutive days add one for that result.
If it's not a beauty contents then you may try something like:
select t.start, t2.start, datediff(t2.start, t.start) + 1 as consecutive_days
from tab t
join tab t2 on t2.start = (select min(start) from (
select c1.*, case when c2.id is null then 1 else 0 end as gap
from tab c1
left join tab c2 on c1.start = adddate(c2.start, -1)
) t4 where t4.start <= t.start and t4.start >= (select max(start) from (
select c1.*, case when c2.id is null then 1 else 0 end as gap
from tab c1
left join tab c2 on c1.start = adddate(c2.start, -1)
) t3 where t3.start <= t.start and t3.gap = 1))
where t.start = '2011-12-18'
Result should be:
start start consecutive_days
2011-12-18 2011-12-16 3
I am running this query to get a count of the bookedby users total number of sales with insurance and total number of sales without insurance. However, all of the users are getting the same count for some reason. how can i change my query to show each users totals instead.
what i want is basically to figure out how many bookings each user had with and without insurance sales
bookedby is the agent
and T0 is the table that includes the information about bookings that do not include insurance
and t1 is the table that includes information about bookings with insurance
while both tables provide the same information how can i get a total by booked by for each agent from both tables
SELECT t0.BookedBy, count(t0.resnumber) as NonInsurance, COUNT(t1.resnumber) as Insurance
FROM (SELECT BookedBy, ResNumber, DATEPART(year, BookDate) AS Year, DATEPART(month, BookDate) AS month
FROM dbo.ResGeneral
WHERE ResNumber NOT IN (SELECT ResNumber FROM dbo.ResItinerary_insurance)
and ResStatus = 'a'
GROUP BY BookedBy, ResNumber, BookDate) t0
left JOIN (SELECT BookedBy, ResNumber, DATEPART(year, BookDate) AS Year, DATEPART(month, BookDate) AS month
FROM dbo.ResGeneral
WHERE ResNumber IN (SELECT ResNumber FROM dbo.ResItinerary_insurance)
and ResStatus = 'a') t1
ON t1.year = t0.year
group by t0.bookedby
I think this query is equivalent:
SELECT g.BookedBy,
SUM(CASE WHEN i.ResNumber IS NULL THEN 1 ELSE 0 END) AS NonInsurance,
SUM(CASE WHEN i.ResNumber IS NOT NULL THEN 1 ELSE 0 END) AS Insurance
FROM dbo.ResGeneral g
LEFT JOIN dbo.ResItinerary_insurance i
ON g.ResNumber = i.ResNumber
WHERE g.ResStatus = 'a'
GROUP BY g.BookedBy;
Your join condition looks incorrect:
ON t1.year = t0.year
This will cross join all rows with the same year. You probably want to use a more specific condition, for example t1.BookedBy = t0.BookedBy.
The query below gives me a report of items that are out for an equipment rental company. this is a super complicated query that takes almost 20 seconds to run. This is obviously not the correct way to get the data that I'm looking for. I build this query from PHP and add in the start date of 02-01-2011 and the end date of 03-01-2011, the product code (p_code = 1) and product pool (i_pool =1). Those 4 pieces of information are passed to a PHP function and injected into the following sql to return the report I need for a calendar control displaying how many items are out. My question is: Is there any way to simplify or do this better, or run more efficiently, using better joins or a better way to display the individual days.
SELECT DISTINCT reportdays.reportday, count(*)
FROM
(SELECT '2011-02-01' + INTERVAL a + b DAY reportday
FROM
(SELECT 0 a UNION SELECT 1 a UNION SELECT 2 UNION SELECT 3
UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7
UNION SELECT 8 UNION SELECT 9 ) d,
(SELECT 0 b UNION SELECT 10 UNION SELECT 20
UNION SELECT 30 UNION SELECT 40) m
WHERE '2011-02-01' + INTERVAL a + b DAY < '2011-03-01'
ORDER BY a + b) as reportdays
JOIN rental_inv as line
ON DATE(FROM_UNIXTIME(line.ri_delivery_dte)) <= reportdays.reportday
AND DATE(FROM_UNIXTIME(line.ri_pickup_dte)) >= reportdays.reportday
LEFT OUTER JOIN rental_in as rent on line.ri_num = rent.ri_num
LEFT OUTER JOIN rental_cancels cancelled on rent.ri_num = cancelled.ri_num
LEFT OUTER JOIN inv inventory on line.i_num = inventory.i_num
LEFT OUTER JOIN product ON inventory.p_code = product.p_code
WHERE rent.ri_extend = 0 -- disregard extended rentals
AND cancelled.ri_num is null -- disregard cancelled rentals
AND inventory.p_code = 1
AND inventory.i_pool = 1
GROUP BY reportdays.reportday
If there is any other information needed, let me know and I'll post it.
You can use:
SELECT DATE(ri_delivery) as day,
count(*) as itemsout,
FROM rental_inv
GROUP BY day;
I'm not sure if you need this or a different thing.
SELECT dates.day, count (*)
FROM rental_inv line
INNER JOIN (SELECT DATE(ri_delivery_dte) as day FROM rental_inv
WHERE ri_delivery_dte >= '2011/02/01'
AND ri_delivery_dte <= '2011/02/28'
GROUP BY day
UNION
SELECT DATE(ri_pickup_dte) as day FROM rental_inv
WHERE ri_pickup_dte >= '2011/02/01'
AND ri_pickup_dte <= '2011/02/28'
GROUP BY day) dates
ON line.ri_delivery_dte <= dates.day and line.ri_pickup_dte >= dates.day
LEFT JOIN rental_cancels canc on line.ri_num = canc.ri_num
LEFT JOIN rental_in rent on line.ri_num = rent.ri_num
WHERE canc.ri_num is null
AND rent.ri_extend = 0
GROUP BY dates.day
to find all days:
SELECT DATE(IFNULL(ri_delivery,ri_pickup)) AS date FROM rental_inv AS dateindex WHERE [YEAR-MONTH-1] <= ri_delivery <= LAST_DAY([YEAR-MONTH-1]) OR [YEAR-MONTH-1] <= ri_pickup <= LAST_DAY([YEAR-MONTH-1]) GROUP BY date HAVING NOT ISNULL(date)
to find items out
SELECT COUNT(id) FROM rental_inv WHERE ri_pickup = [DATE];
to find items in
SELECT COUNT(id) FROM rental_inv WHERE ri_delivery = [DATE];
to find balance
SELECT COUNT(out.id) - COUNT(in.id) FROM rental_inv AS out INNER JOIN rental_inv AS in
ON DATE(out.ri_pickup) = DATE(in.ri_delivery) WHERE out.ri_pickup = [DATE] OR in.ri_delivery = [DATE]
You probably can join up everything but since its procedure its more clear;
I am not sure if this would be the exact answer to your problem but I would do something like this I guess. (I didn't use any SQL editor so u need to check syntax I guess)
SELECT
reportdays.d3 as d,
( COALESCE(outgoing.c1,0) - COALESCE(incoming.c2,0) ) as c
FROM
-- get report dates
(
SELECT DATE(FROM_UNIXTIME(COALESCE(l3.ri_delivery_dte, l3.ri_pickup_dte)) d3
FROM rental_inv l3
WHERE
(l3.ri_delivery_dte >= UNIX_TIMESTAMP('2011-02-01')
AND l3.ri_delivery_dte < UNIX_TIMESTAMP('2011-03-01'))
OR (l3.ri_pickup_dte >= UNIX_TIMESTAMP('2011-02-01')
AND l3.ri_pickup_dte < UNIX_TIMESTAMP('2011-03-01'))
GROUP BY d3
) as reportdays
-- get outgoing
LEFT JOIN (
SELECT DATE(FROM_UNIXTIME(l1.ri_delivery_dte)) as d1, count(*) as c1
FROM rental_inv l1
LEFT JOIN rental_cancels canc1 on l.ri_num = canc1.ri_num
LEFT JOIN rental_in rent1 on l.ri_num = rent1.ri_num
WHERE
l1.ri_delivery_dte >= UNIX_TIMESTAMP('2011-02-01')
AND l1.ri_delivery_dte < UNIX_TIMESTAMP('2011-03-01')
AND canc1.ri_num is null
AND rent1.ri_extend = 0
GROUP BY d1
) as outgoing ON reportdays.d3 = outgoing.d1
-- get incoming
LEFT JOIN (
SELECT DATE(FROM_UNIXTIME(l2.ri_pickup_dte)) as d2, count(*) as c2
FROM rental_inv l2
LEFT JOIN rental_cancels canc2 on l2.ri_num = canc2.ri_num
LEFT JOIN rental_in rent2 on l2.ri_num = rent2.ri_num
WHERE
l2.ri_pickup_dte >= UNIX_TIMESTAMP('2011-02-01')
AND l2.ri_pickup_dte < UNIX_TIMESTAMP('2011-03-01')
AND canc2.ri_num is null
AND rent2.ri_extend = 0
GROUP BY d2
) as incoming ON reportdays.d3 = incoming.d2