Model method has perm looks for all the permission from Group and Permission. which is a heavy query.How can i optimized query time or any other solution to check user permission.
Example:
SELECT "auth_permission"."id", "auth_permission"."name", "auth_permission"."content_type_id", "auth_permission"."codename" FROM "auth_permission" INNER JOIN "auth_group_permissions" ON ( "auth_permission"."id" = "auth_group_permissions"."permission_id" ) INNER JOIN "auth_group" ON ( "auth_group_permissions"."group_id" = "auth_group"."id" ) INNER JOIN "auth_user_groups" ON ( "auth_group"."id" = "auth_user_groups"."group_id" ) INNER JOIN "django_content_type" ON ( "auth_permission"."content_type_id" = "django_content_type"."id" ) WHERE "auth_user_groups"."user_id" = 1235 ORDER BY "django_content_type"."app_label" ASC, "django_content_type"."model" ASC, "auth_permission"."codename" ASC
SELECT "auth_permission"."id", "auth_permission"."name", "auth_permission"."content_type_id", "auth_permission"."codename", "django_content_type"."id", "django_content_type"."name", "django_content_type"."app_label", "django_content_type"."model" FROM "auth_permission" INNER JOIN "auth_user_user_permissions" ON ( "auth_permission"."id" = "auth_user_user_permissions"."permission_id" ) INNER JOIN "django_content_type" ON ( "auth_permission"."content_type_id" = "django_content_type"."id" ) WHERE "auth_user_user_permissions"."user_id" = 1235 ORDER BY "django_content_type"."app_label" ASC, "django_content_type"."model" ASC, "auth_permission"."codename" ASC
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I have to write a query in which I need the given output.
I tried different queries but didn't work.
Actual data :
and I need Output like :
Queries like :
SELECT VCD.id,VCD.effective_date, `VCD`.`charge_id`, `C`.`head`,
`VCD`.`per`, `VCD`.`currency`, `VCD`.`amount`, `VCD`.`remarks`
FROM `vendor_charge` `VC` INNER JOIN `vendor_charge_details` `VCD`
ON `VC`.`id` = `VCD`.`vc_id` LEFT JOIN `charges` `C`
ON `C`.`id` = `VCD`.`charge_id`
WHERE `VC`.`vendor_id` = '12' AND `VCD`.`effective_date` <= '2018-05-22'
GROUP BY `VCD`.`charge_id`, `VCD`.`per`, `VCD`.`currency`
ORDER BY `C`.`head` DESC
and
SELECT VCD.id,VCD.effective_date, `VCD`.`charge_id`, `C`.`head`,
`VCD`.`per`, `VCD`.`currency`, `VCD`.`amount`, `VCD`.`remarks`
FROM `vendor_charge` `VC` INNER JOIN `vendor_charge_details` `VCD`
ON `VC`.`id` = `VCD`.`vc_id` LEFT JOIN `charges` `C`
ON `C`.`id` = `VCD`.`charge_id`
WHERE `VC`.`vendor_id` = '12' AND `VCD`.`effective_date` <= '2018-05-22'
GROUP BY `VCD`.`charge_id`, `VCD`.`per`, `VCD`.`currency`
ORDER BY `VCD`.`effective_date` DESC
I think all you need here is an additional join to a subquery which finds the latest effective_date for each charge_id:
SELECT
VCD.id,
VCD.effective_date,
VCD.charge_id,
C.head,
VC.per,
VCD.currency,
VCD.amount,
VCD.remarks
FROM vendor_charge VC
INNER JOIN vendor_charge_details VCD
ON VC.id = VCD.vc_id
INNER JOIN
(
SELECT charge_id, MAX(effective_date) AS max_effective_date
FROM vendor_charge_details
GROUP BY charge_id
) t
ON VCD.charge_id = t.charge_id AND VCD.effective_date = t.max_effective_date
LEFT JOIN charges C
ON C.id = VCD.charge_id
WHERE VC.vendor_id = '12' AND VCD.effective_date <= '2018-05-22'
ORDER BY
C.head DESC;
I want to speed up one of my slower queries.
The problem is that I can't access the outer colum value within a subquery.
What I have:
SELECT r.id AS room_id, r.room_name, coalesce(d.score,0) AS total_messages, d.latest
FROM cf_rooms_time_frames tf
INNER JOIN cf_rooms r on r.id = tf.room_id
INNER JOIN(
SELECT cf.room_id, count(*) as score, max(cf.id) as latest
FROM cf_rooms_messages cf
WHERE EXISTS(
SELECT NULL FROM cf_rooms_time_frames tf
WHERE tf.start <= cf.id AND ( tf.end IS NULL OR tf.end >= cf.id )
AND tf.room_id = cf.room_id AND tf.uid = 8
)
GROUP BY cf.room_id
ORDER BY latest
DESC ) d on d.room_id = r.id
WHERE tf.uid = 8
ORDER BY coalesce(latest, score) DESC LIMIT 0, 20
What I want:
SELECT r.id AS room_id, r.room_name, coalesce(d.score,0) AS total_messages, d.latest
FROM cf_rooms_time_frames tf
INNER JOIN cf_rooms r on r.id = tf.room_id
INNER JOIN(
SELECT cf.room_id, count(*) as score, max(cf.id) as latest
FROM cf_rooms_messages cf
/* line added here */
WHERE cf.room_id = tf.room_id
/* */
AND EXISTS(
SELECT NULL FROM cf_rooms_time_frames tf
WHERE tf.start <= cf.id AND ( tf.end IS NULL OR tf.end >= cf.id )
AND tf.room_id = cf.room_id AND tf.uid = 8
)
GROUP BY cf.room_id
ORDER BY latest
DESC ) d on d.room_id = r.id
WHERE tf.uid = 8
ORDER BY coalesce(latest, score) DESC LIMIT 0, 20
I think the markup explains what the query does.
It searches for "chatrooms" for a given user and orders them by the last message, gets the number of total message which ids are in a given range ( timeframes ), and the last message id.
I don't know why, but the first query returns all rows within the chatmessage table ( cf ) if I can trust EXPLAIN. It delivers the correct results but is kind of slow on a huge table.
I tested the second one with a "hardcoded" room_id and this one was very fast and doesn't "touched" the whole table.
I have two requests
UPDATE :
I need to do something like that :
SELECT poste_nom, ups_type_contrat,
(SELECT `entpro_date`
FROM ENT_PRO
WHERE entpro_user_id = 2
ORDER BY `entpro_id` DESC
LIMIT 1) ,
serv_nom,
serv_id_resp,
user_credit_cpf,
user_indice_salarial,
FLOOR( DATEDIFF( CURDATE( ) , user_dateentree ) /365 ) AS dateEntree
FROM USER
INNER JOIN USER_POSTE_SERVICE
ON USER.user_id= USER_POSTE_SERVICE.ups_poste_id
INNER JOIN POSTE
ON USER_POSTE_SERVICE. ups_poste_id = POSTE.poste_id
INNER JOIN SERVICE
ON USER_POSTE_SERVICE.ups_id_serv = SERVICE.serv_id
WHERE user_id = 2
ORDER BY user_nom ASC
Is it possible to gather two requests in only one ?
From what I understood you want to simple merge the result of your sub-query to your main SELECT, if so you could try it this way:
SELECT poste_nom,
ups_type_contrat,
ENT_PRO_RESULT.entpro_date,
serv_nom,
serv_id_resp,
user_credit_cpf,
user_indice_salarial,
FLOOR( DATEDIFF( CURDATE( ) , user_dateentree ) /365 ) AS dateEntree
FROM USER
LEFT JOIN (SELECT entpro_date,
entpro_user_id
FROM ENT_PRO
ORDER BY entpro_id DESC
LIMIT 1) ENT_PRO_RESULT
ON USER.user_id = ENT_PRO_RESULT.entpro_user_id
INNER JOIN USER_POSTE_SERVICE
ON USER.user_id = USER_POSTE_SERVICE.ups_poste_id
INNER JOIN POSTE
ON USER_POSTE_SERVICE.ups_poste_id = POSTE.poste_id
INNER JOIN SERVICE
ON USER_POSTE_SERVICE.ups_id_serv = SERVICE.serv_id
WHERE user_id = 2
ORDER BY user_nom ASC
I've joined it on:
ON USER.user_id = ENT_PRO_RESULT.entpro_user_id
So you only need to specify the:
WHERE user_id = 2
And the sub-query will use the current row user id for the LEFT JOIN.
I would like to use JOIN instead of IN in the following SQL query. I can't figure out how to do it.
SELECT * FROM shop_orders WHERE
id IN (SELECT orders_id FROM shop_orders_data WHERE closed='1' /*AND backorder='0'*/ AND exhibition_id='389' AND
exhibition_id IN (SELECT id FROM shop_exhibitions WHERE
country_id IN (SELECT id FROM countries WHERE id='72')) AND in_country = '72' AND
exhibition_id IN (SELECT id FROM shop_exhibitions WHERE start<=1336946400 AND end>1336600800)) AND
id IN (SELECT orders_id FROM shop_orders_products WHERE
products_id IN (SELECT id FROM shop_products WHERE artno='120000' OR name LIKE '%120000%')) AND created>=1333231200 AND created<1333663200 ORDER BY created DESC
I tried this:
SELECT
s.*
FROM
shop_orders s
INNER JOIN shop_orders_data od ON s.id=od.orders_id
INNER JOIN shop_exhibitions se ON od.exhibition_id=se.id
INNER JOIN countries co ON se.country_id=co.id
INNER JOIN shop_orders_products sop ON s.id=sop.orders_id
INNER JOIN shop_products sp
ON sop.products_id=sp.id
WHERE od.closed=1
AND ( sp.artno='120000' or sp.name LIKE '%120000%' )
AND ( od.exhibition_id='389')
AND ( od.in_country = '72')
AND ( se.start <=1336946400)
AND ( se.end >1336600800)
AND ( se.created>=1333231200)
AND ( se.created<1333663200)
ORDER BY `s`.`created` DESC
I this correct??
See if this works (and study the code to learn how it works):
SELECT *
FROM shop_orders so
JOIN shop_orders_data sod ON (
(so.id = sod.orders_id)
AND (sod.closed = '1')
/*AND (sod.backorder = '0') */
AND (sod.exhibition_id = '389')
AND (sod.in_country = '72')
)
JOIN shop_exhibitions se ON (
(sod.exhibition_id = se.id)
AND (se.start <= 1336946400)
AND (se.end > 1336600800)
)
JOIN countries c ON (
(se.country_id = c.id)
AND (c.id = '72')
)
JOIN shop_orders_products sop ON (
(so.id = sop.orders_id)
)
JOIN shop_products sp ON (
(sop.products_id = sp.id)
AND ((sp.artno='120000') OR (sp.name LIKE '%120000%'))
)
WHERE (so.created >= 1333231200) AND (so.created < 1333663200)
ORDER BY so.created DESC;
The join syntax works like this:
SELECT field1,field2,field3
FROM FirstTable
JOIN SecondTable ON (FirstTable.PrimaryKey = SecondTable.ForeignKey)
JOIN ThirdTable ON (FirstTable.PrimaryKey = ThirdTable.ForeignKey)
Try applying this approach to your query.
$query_index_neighborhood1 =
"SELECT areas_db.areas_name, areas_db.areas_id, neighborhoods_db.neighborhoods_id,
neighborhoods_db.neighborhoods_name, neighborhoods_db.neighborhoods_area_id,
areas_db.areas_state_id
FROM (
(
(
restaurants_db
INNER JOIN neighborhoods_db ON neighborhoods_db.neighborhoods_id=restaurants_db.restaurants_neighborhood
)
INNER JOIN areas_db ON areas_db.areas_id=neighborhoods_db.neighborhoods_area_id
)
INNER JOIN areas_db AS areas_db1 on areas_db1.areas_id=restaurants_db.restaurants_area
)
WHERE areas_db.areas_state_id=$mxstateid
GROUP BY neighborhoods_db.neighborhoods_id
ORDER BY areas_db.areas_id, neighborhoods_db.neighborhoods_name ASC";
As an interesting thought exercise, I came up with the following:
SELECT a.areas_name,
a.areas_id,
n.neighborhoods_id,
n.neighborhoods_name,
n.neighborhoods_area_id,
a.areas_state_id
FROM neighborhoods_db AS n
INNER JOIN areas_db AS a ON a.areas_id = n.neighborhoods_area_id
WHERE a.areas_state_id = $mxstateid
AND n.neighborhoods_id in (SELECT restaurants_neighborhood FROM restaurants_db)
ORDER BY a.areas_id, n.neighborhoods_name ASC
Also, table aliases are your friend.