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Retrieving the last record in each group - MySQL
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Closed 8 years ago.
I have a little problem with my query, here is my table:
CREATE TABLE IF NOT EXISTS `realizado` (
`cod` int(11) NOT NULL AUTO_INCREMENT,
`datedoc` date NOT NULL,
`bank` int(11) NOT NULL,
`bankValue` float NOT NULL,
PRIMARY KEY (`cod`));
INSERT INTO `realizado` (`cod`, `datedoc`, `bank`, `bankValue`) VALUES
(152, '2014-10-22', 22, 1000),
(153, '2014-10-22', 23, 2000),
(154, '2014-10-22', 24, 3000),
(200, '2014-10-23', 22, 950),
(201, '2014-10-25', 22, 100),
(202, '2014-10-25', 23, 2050),
(203, '2014-10-24', 22, 150),
(204, '2014-10-24', 24, 3800);
The problem is: I need to get the bankValue from a date and still group by bank, something like this:
SELECT bank, bankValue
FROM realizado
WHERE datedoc <= '2014/10/25'
GROUP BY bank
the closest I got is:
SELECT r.bank, (select bankValue from realizado r2 where max(r.cod) = r2.cod) as Value
FROM realizado as r
WHERE r.datedoc <= '2014/10/25'
GROUP BY r.bank
here's the SQL Fiddle if u like -> http://sqlfiddle.com/#!2/83e309/2
the result that I expect is ( 22 - 100 / 23 - 2050 / 24 - 3800 )
Here you go! (Thanks for setting up the sqlFiddle with DDL and bootstrap data :)
Working sqlFiddle: http://sqlfiddle.com/#!2/83e309/10
SELECT a.*
FROM realizado a
INNER JOIN
(
SELECT bank, MAX(datedoc) datedoc
FROM realizado
GROUP BY bank
) b ON a.bank = b.bank AND
a.datedoc = b.datedoc
You seem to want the latest value for the bank. If so, you can do:
select r.*
from realizado r
where not exists (select 1 from realizao r2 where r2.bank = r.bank and r2.datedoc > r.datedoc);
Related
Here is my table
CREATE TABLE financials (
id INT(6) UNSIGNED AUTO_INCREMENT PRIMARY KEY,
CountryID VARCHAR(30) NOT NULL,
ProductID VARCHAR(30) NOT NULL,
Revenue INT NOT NULL,
cost INT NOT NULL,
reg_date TIMESTAMP
);
INSERT INTO `financials` (`id`, `CountryID`, `ProductID`, `Revenue`, `cost`, `reg_date`) VALUES
( 1, 'Canada', 'Doe' , 20, 5, '2010-01-31 12:01:01'),
( 2, 'USA' , 'Tyson' , 40, 15, '2010-02-14 12:01:01'),
( 3, 'France', 'Keaton', 80, 25, '2010-03-25 12:01:01'),
( 4, 'France', 'Keaton',180, 45, '2010-04-24 12:01:01'),
( 5, 'France', 'Keaton', 30, 6, '2010-04-25 12:01:01'),
( 6, 'France', 'Emma' , 15, 2, '2010-01-24 12:01:01'),
( 7, 'France', 'Emma' , 60, 36, '2010-01-25 12:01:01'),
( 8, 'France', 'Lammy' ,130, 26, '2010-04-25 12:01:01'),
( 9, 'France', 'Louis' ,350, 12, '2010-04-25 12:01:01'),
(10, 'France', 'Dennis',100,200, '2010-04-25 12:01:01'),
(11, 'USA' , 'Zooey' , 70, 16, '2010-04-25 12:01:01'),
(12, 'France', 'Alex' , 2, 16, '2010-04-25 12:01:01');
For each product and date combination, I need to get the revenue for previous 5 days. For instance, for Product ‘Keaton’, the last purchase was on 2010-04-25, it will only sum up revenue between 2010-04-20 to 2010-04-25 and therefore it will be 210. While for "Emma", it would return 75, since it would sum everything between 2010-01-20 to 2010-01-25.
SELECT ProductID, sum(revenue), reg_date
FROM financials f
Where reg_date in (
SELECT reg_date
FROM financials as t2
WHERE t2.ProductID = f.productID
ORDER BY reg_date
LIMIT 5)
Unfortunately, when i use either https://sqltest.net/ or http://sqlfiddle.com/ it says that 'LIMIT & IN/ALL/ANY/SOME subquery' is not supported. Would my query work or not?
Your query is on the right track, but probably won't work in MySQL. MySQL has limitations on the use of in and limit with subqueries.
Instead:
SELECT f.ProductID, SUM(f.revenue)
FROM financials f JOIN
(SELECT ProductId, MAX(reg_date) as max_reg_date
FROM financials
GROUP BY ProductId
) ff
ON f.ProductId = ff.ProductId and
f.reg_date >= ff.max_reg_date - interval 5 day
GROUP BY f.ProductId;
EDIT:
If you want this for each product and date combination, then you can use a self join or correlated subquery:
SELECT f.*,
(SELECT SUM(f2.revenue)
FROM financials f2
WHERE f2.ProductId = f.ProductId AND
f2.reg_date <= f.reg_date AND
f2.reg_date >= f.reg_date - interval 5 day
) as sum_five_preceding_days
FROM financials f;
After some trials I ended up with some complex query, that I think it solves your problem
SELECT
financials.ProductID, sum(financials.Revenue) as Revenues
FROM
financials
INNER JOIN (
SELECT ProductId, GROUP_CONCAT(id ORDER BY reg_date DESC) groupedIds
FROM financials
group by ProductId
) group_max
ON financials.ProductId = group_max.ProductId
AND FIND_IN_SET(financials.id, groupedIds) BETWEEN 1 AND 5
group by financials.ProductID
First I used group by financials.ProductID to count revenues by products. The real problem you are facing is eliminating all rows that are not in the top 5, for each group. For that I used the solution from this question, GROUP_CONCAT and FIND_IN_SET, to get the top 5 result without LIMIT. Instead of WHERE IN I used JOIN but with this, WHERE IN might also work.
Heres the FIDDLE
I have a mysql DB with multiple that contains data like this.
http://sqlfiddle.com/#!9/f084c
CREATE TABLE `datos` (
`id` int(11) NOT NULL,
`fecha` datetime NOT NULL,
`temperatura` tinyint(4) NOT NULL
) ENGINE=MyISAM DEFAULT CHARSET=latin1;
INSERT INTO `datos` (`id`, `fecha`, `temperatura`) VALUES
(1874, '2017-05-20 01:56:40', 20),
(1875, '2017-05-20 01:56:51', 20),
(1876, '2017-06-18 23:32:49', 17),
(1877, '2017-06-18 23:34:50', 17),
(1878, '2017-06-18 23:36:51', 17),
(1879, '2017-06-18 23:38:52', 17),
(1880, '2017-06-18 23:46:02', 16),
(1881, '2017-06-18 23:47:12', 17),
(1882, '2017-06-22 01:06:27', 21);
I want to select just one value of a day during a 30 day interval, to have a result like this
2017-06-22 01:06:27 21
2017-06-18 23:47:12 17
2017-05-20 01:56:51 20
I have selected the entire interval using
SELECT * FROM `datos` WHERE fecha >= '2017-06-22 01:06:27' - INTERVAL 30 DAY
But i have not managed to just select one value per day instead of all of them.
Would appreciate the help
Based on the desired result you listed, it looks like you want maximum fecha for each day.
select date(fecha), max(fecha)
from datos
group by date(fecha)
This results in the following:
2017-06-22 2017-06-22 01:06:27
2017-06-18 2017-06-18 23:47:12
2017-05-20 2017-05-20 01:56:51
By treating the above query as a table and joining it back to the datos table you can get the complete record: id, fecha, and temperatura which had the maximum fecha each day.
select d1.*
from datos d1,
(select date(fecha), max(fecha) as max_fecha
from datos
group by date(fecha) ) d2
where d1.fecha = d2.max_fecha
and d1.fecha >= '2017-06-22 01:06:27' - INTERVAL 30 DAY
Resulting in the following:
1875 2017-05-20 2017-05-20 01:56:51 20
1881 2017-06-18 2017-06-18 23:47:12 17
1882 2017-06-22 2017-06-22 01:06:27 21
Note I initially solved in Oracle since I do not have access to a mysql database, but I believe I correctly altered the queries to work in mysql.
select a.*
from datos a
left outer join datos b
on substr(a.fecha,1,10) = substr(b.fecha,1,10) and a.id < b.id
where b.id is null
You can manipulate your conditions of matching to select whatever property of the rows you want to prioritize.
I dont need to check if business is open or close, but I need to show open hours by days.
There are some options:
1 - Business open once in day (sample - from 10:00 to 18:30) - one
rows in table
2 - Business open TWICE in day (samlpe - from 10:00 to
14:00 and from 15:00 to 18:30) - two rows in table
3 - Business may
be closed (no row inserted)
Here my MySql table of hours storing. In this sample business (affiliate_id) are open twice in days from 0 to 4, once in day 5 and closed in day 6 (no records for this day)
http://postimage.org/image/yplj4rumj/
What I need to show in website its like (according to this database example:
0,1,2,3,4 - open 10:00-14:00 and 15:00-18:30
5 - open 10:00-12:00
6 - closed
How I get results like:
http://postimage.org/image/toe53en63/
?
I tried to make queries with GROUPֹ_CONCAT and LEFT JOIN the same table ON a.day=b.day but with no luck :(
There sample of my query (that is wrong)
SELECT GROUP_CONCAT( DISTINCT CAST( a.day AS CHAR )
ORDER BY a.day ) AS days, DATE_FORMAT( a.time_from, '%H:%i' ) AS f_time_from, DATE_FORMAT( a.time_to, '%H:%i' ) AS f_time_to, DATE_FORMAT( b.time_from, '%H:%i' ) AS f_time_from_s, DATE_FORMAT( b.time_to, '%H:%i' ) AS f_time_to_s
FROM business_affiliate_hours AS a LEFT
JOIN business_affiliate_hours AS b ON a.day = b.day
WHERE a.affiliate_id =57
GROUP BY a.time_from, a.time_to, b.time_from, b.time_to
ORDER BY a.id ASC
This my table:
CREATE TABLE IF NOT EXISTS `business_affiliate_hours` (
`id` int(10) unsigned NOT NULL AUTO_INCREMENT,
`affiliate_id` int(10) unsigned NOT NULL DEFAULT '0',
`time_from` time NOT NULL,
`time_to` time NOT NULL,
`day` tinyint(1) unsigned NOT NULL DEFAULT '0',
PRIMARY KEY (`id`)
) ENGINE=MyISAM;
INSERT INTO `business_affiliate_hours` (`id`, `affiliate_id`, `time_from`, `time_to`, `day`) VALUES
(53, 57, '10:00:00', '12:00:00', 5),
(52, 57, '15:00:00', '18:30:00', 4),
(51, 57, '10:00:00', '14:00:00', 4),
(50, 57, '15:00:00', '18:30:00', 3),
(49, 57, '10:00:00', '14:00:00', 3),
(48, 57, '15:00:00', '18:30:00', 2),
(47, 57, '10:00:00', '14:00:00', 2),
(46, 57, '15:00:00', '18:30:00', 1),
(45, 57, '10:00:00', '14:00:00', 1),
(44, 57, '15:00:00', '18:30:00', 0),
(43, 57, '10:00:00', '14:00:00', 0);
Open hours may be different for every day, so I want to GROUP by the same open hours, and get list of days for all unique order of open hours.
Need your help!
Sorry for links to images, I cant upload images yes to here.
First build a materialised table of each day's combined times, then group on that:
SELECT GROUP_CONCAT(day ORDER BY day) AS days,
DATE_FORMAT(f1, '%H:%i') AS f_time_from,
DATE_FORMAT(t1, '%H:%i') AS f_time_to,
DATE_FORMAT(f2, '%H:%i') AS f_time_from_s,
DATE_FORMAT(t2, '%H:%i') AS f_time_to_s
FROM (
SELECT day,
MIN(time_from) AS f1,
MIN(time_to ) AS t1,
IF(COUNT(*) > 1, MAX(time_from), NULL) AS f2,
IF(COUNT(*) > 1, MAX(time_to ), NULL) AS t2
FROM business_affiliate_hours
WHERE affiliate_id = 57
GROUP BY day
) t
GROUP BY f1, t1, f2, t2
ORDER BY days
See it on sqlfiddle.
http://sqlfiddle.com/#!2/6a6b1
The scheme is given above.. all I want to do is get the results as the total of sales/month... the user will enter a start date and end date and I can generate (in PHP) all the month and years for those dates. For example, if I want to know the total number of "sales" for 12 months, I know I can run 12 individual queries with start and end dates, but I want to run only one query where the result will look like:
Month numofsale
January - 2
Feb-1
March - 23
Apr - 10
and so on...
or just a list of sales without the months, I can then pair it to the array of months generated in the PHP ...any ideas...
Edit/schema and data pasted from sqlfiddle.com:
CREATE TABLE IF NOT EXISTS `lead_activity2` (
`lead_activity_id` int(11) NOT NULL AUTO_INCREMENT,
`sp_id` int(11) NOT NULL,
`act_date` datetime NOT NULL,
`act_name` varchar(255) NOT NULL,
PRIMARY KEY (`lead_activity_id`),
KEY `act_date` (`act_date`),
KEY `act_name` (`act_name`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1 ;
INSERT INTO `lead_activity2` (`lead_activity_id`, `sp_id`, `act_date`, `act_name`) VALUES
(1, 5, '2012-10-16 16:05:29', 'sale'),
(2, 5, '2012-10-16 16:05:29', 'search'),
(3, 5, '2012-10-16 16:05:29', 'sale'),
(4, 5, '2012-10-17 16:05:29', 'DNC'),
(5, 5, '2012-10-17 16:05:29', 'sale'),
(6, 5, '2012-09-16 16:05:30', 'SCB'),
(7, 5, '2012-09-16 16:05:30', 'sale'),
(8, 5, '2012-08-16 16:05:30', 'sale'),
(9, 5,'2012-08-16 16:05:30', 'sale'),
(10, 5, '2012-07-16 16:05:30', 'sale');
SELECT DATE_FORMAT(date, "%m-%Y") AS Month, SUM(numofsale)
FROM <table_name>
WHERE <where-cond>
GROUP BY DATE_FORMAT(date, "%m-%Y")
Check following in your fiddle demo it works for me (remove where clause for testing)
SELECT DATE_FORMAT(act_date, "%m-%Y") AS Month, COUNT(*)
FROM lead_activity2
WHERE <where-cond-here> AND act_name='sale'
GROUP BY DATE_FORMAT(act_date, "%m-%Y")
It returns following result
MONTH COUNT(*)
07-2012 1
08-2012 2
09-2012 1
10-2012 3
You can try query as given below
select SUM(`SP_ID`) AS `Total` , DATE_FORMAT(act_date, "%M") AS Month, Month(`ACT_DATE`) AS `Month_number` from `lead_activity2` WHERE `ACT_DATE` BETWEEN '2012-05-01' AND '2012-12-17' group by Month(`ACT_DATE`)
Here 2012-05-01 and 2012-12-17 are date input from form. and It will be return you the sum of sales for particular month if exist in database.
thanks
Try this query -
SELECT
MONTH(act_date) month, COUNT(*)
FROM
lead_activity2
WHERE
YEAR(act_date) = 2012 AND act_name = 'sale'
GROUP BY
month
Check WHERE condition if it is OK for you - act_name = 'sale'.
If you want to output month names, then use MONTHNAME() function instead of MONTH().
SELECT YEAR(act_date), MONTH(act_date), COUNT(*)
FROM lead_activity2
GROUP BY YEAR(act_date), MONTH(act_date)
For getting data by month or any other data based on column you have to add GROUP BY.
You can add many columns or calculated values to GROUP BY.
I assume that "num of sales" means count of rows.
Sometimes you might want the month names as Jan, Feb, Mar .... Dec possibly for a Chart likeFusionChart
SELECT DATE_FORMAT(date, "%M") AS Month, SUM(numofsale)
FROM <Table_name>
GROUP BY DATE_FORMAT(date, "%M")
Results would look like this on table
MONTH COUNT(*)
Jul 1
Aug 2
SEP 1
OCT 3
I would like to display data re-arranged year by year and one of the possible solution is using views and select from them. The data matrix is something like (of course it's a ficticious demo dataset):
USA 2005 22 156
CAN 2005 14 101
MEX 2005 5 32
USA 2006 24 160
CAN 2006 16 103
USA 2007 26 163
MEX 2007 8 35
The SQL code to create and populate the table is:
DROP TABLE IF EXISTS `tab1`;<br>
CREATE TABLE `tab1` ( <br>
`id1` int(4) unsigned NOT NULL AUTO_INCREMENT,
`iso3` char(3) NOT NULL,
`year` int(4) unsigned NOT NULL,
`aaa` int(10) DEFAULT NULL,
`bbb` int(10) DEFAULT NULL,
PRIMARY KEY (`id1`)
)
INSERT INTO `tab1` VALUES
('1', 'USA', '2005', '22', '156'),
('2', 'CAN', '2005', '14', '101'),
('3', 'MEX', '2005', '5', '32'),
('4', 'USA', '2006', '24', '160'),
('5', 'CAN', '2006', '16', '103'),
('6', 'USA', '2007', '26', '163'),
('7', 'MEX', '2007', '8', '35');
COMMIT;
And now I would like to obtain for parameter 'aaa' a 2D table like this:
country 2005 2006 2007
USA 22 24 26
CAN 14 16
MEX 5 8
However the following SQL code is omitting all the lines with missing data, be it one single value and I only get one line
USA 22 24 26
The SQL code is:
SELECT view2005.Country, view2005.2005, view2006.2006, view2007.2007
FROM view2005, view2006, view2007
WHERE view2005.country = view2006.country
AND view2005.country = view2007.country
Any idea how to do it including lines with missing data? Thanks in advance.
Use left joins, and a view (or table, or inner select like below) which has all distinct countries:
SELECT c.country, view2005.2005, view2006.2006, view2007.2007
FROM (SELECT DISTINCT country FROM tab1) as c
LEFT JOIN view2005 ON view2005.country = c.country
LEFT JOIN view2006 ON view2006.country = c.country
LEFT JOIN view2007 ON view2007.country = c.country
GROUP BY c.country
EDIT:
In a more general context, what you are asking here is to create a pivot of this table, which is a common problem that has common solutions. Here is a nice "How To": http://www.artfulsoftware.com/infotree/queries.php?&bw=1339#78
It's better to use JOIN than implicit JOIN with WHERE. Additional advanatge is that you can convert it to a LEFT JOIN so data for 2005 that don't have a 2006 related row (and are not matched) will still be shown.
Use Galz's solution or search as correctly advised for how to create PIVOT queries.
One such logic to create a pivot query would be:
SELECT iso3 AS Country
, SUM(IF(year=2005, aaa, 0)) AS 2005
, SUM(IF(year=2006, aaa, 0)) AS 2006
, SUM(IF(year=2007, aaa, 0)) AS 2007
FROM tab1 AS t
GROUP BY iso3
If there are years without any data, you will get NULL in that column.
You can use COALESCE() function if you want 0 to be shown and not NULL:
SELECT iso3 AS Country
, COALESCE( SUM( IF(year=2004, aaa, 0) ) , 0) AS "2004"
, COALESCE( SUM( IF(year=2005, aaa, 0) ) , 0) AS "2005"
, COALESCE( SUM( IF(year=2006, aaa, 0) ) , 0) AS "2006"
, COALESCE( SUM( IF(year=2007, aaa, 0) ) , 0) AS "2007"
FROM tab1 AS t
GROUP BY iso3
Thank you Galz for the link to pivots and thank you ypercube for the SQL. It worked after enclosing the years into quotes to make them CHAR.
I was further intrigued by the question what happens if I add a row with no values at all or a row out of range of the years so I have added
INSERT INTO `tab1` VALUES
('7', 'ATA', '2004', '', '')
The result was that I got a mix of NULL and INT zero values. This is not good because zero is a valid number and legitimate data. So I have modified the query to get exactly the result I need:
SELECT iso3 AS countryб
SUM( IF(year=2004, aaa, NULL) ) AS "2004",
SUM( IF(year=2005, aaa, NULL) ) AS "2005",
SUM( IF(year=2006, aaa, NULL) ) AS "2006",
SUM( IF(year=2007, aaa, NULL) ) AS "2007"
FROM tab1
GROUP BY iso3