MySQL Query To find Trains between two stations - mysql

Question

My Train Details table,
Table Name- traindetailtb
Id Train_Number Train_Name From To
1 27658 Venad Express ABC XYZ
2 27659 Venad Express XYZ ABC
and my Train Days Table,
Table Name- traindaystb
Id Train_Number Days
1 27658 Sunday
2 27658 Wednesday
3 27659 Saturday
4 27659 Friday
and this my Train Schedule Table,
Table Name- scheduletb
Id Train_Number Station Time
1 27658 ABC 09:00am
2 27658 CDE 10:00am
3 27658 XYZ 11:00am
4 27659 XYZ 12:00pm
5 27659 CDE 01:00pm
6 27659 ABC 02:00pm
There will be two input, From and To
I need a query that gives all Trains(ie,Train_Number,Train_Name,Days) between the given stations
For eg:
For input From- CDE To-XYZ ---->
output will be-- 27658 Venad Express S W
and For input From- XYZ To-CDE ---->
output will be-- 27659 Venad Express M T
Can anyone Please help me to do this.

Answer 1

Are you looking for something like this?
SELECT q.train_number, MAX(t.train_name) train_name, GROUP_CONCAT(LEFT(d.days, 1)) days
FROM
(
SELECT s.train_number
FROM scheduletb s JOIN scheduletb e
ON s.train_number = e.train_number
WHERE s.station = 'CDE' -- from
AND e.station = 'XYZ' -- to
AND s.id < e.id
) q JOIN traindaystb d
ON q.train_number = d.train_number JOIN traindetailtb t
ON q.train_number = t.train_number
GROUP BY q.train_number
Output for CDE -> XYZ:
| TRAIN_NUMBER | TRAIN_NAME | DAYS |
|--------------|---------------|------|
| 27658 | Venad Express | S,W |
Output for XYZ -> CDE:
| TRAIN_NUMBER | TRAIN_NAME | DAYS |
|--------------|---------------|------|
| 27659 | Venad Express | S,F |
Here is SQLFiddle demo

Answer 2

You can try somthing like this:-
SELECT A.Train_number, A.Train_name, C.days
FROM traindetailtb A, traindaystb B, scheduletb C
WHERE C.Train_Number = A.Train_Number
AND A.Train_Number = B.Train_Number
AND FROM = 'ABC' AND TO = 'XYZ';
This might help you.

Answer 3

Try this
SELECT t.Train_Number,t.Train_Name,d.Days
from traindetailtb t,traindaystb d
WHERE
t.Train_Number=d.Train_Number AND From='ABC' AND To='XYZ';
and just read the input and put it into the from=' ' and to=' ';
this single query will return both the output?

Answer 4

i suggest as follow :
select
traindetailtb.Train_Number,
traindetailtb.Train_Name,
traindetailtb.From,
traindetailtb.To,
tranddaystb.Days,
scheduletb.Time
From
traindetailtb
join trandaystb on
traindetailtb.Train_Number=traindaystb.Train_Number
join scheduletb on
traindetailtb.Train_Number=scheduletb.Train_Number and
traindetailtb.From=scheduletb.From
where
traindetailtb.From=$inputFrom
and
traindetailtb.To=$inputTo

Answer 5

Using a self join you can do this, assuming that the Time is really a time field
SELECT a.Train_Number, d.Train_Name, GROUP_CONCAT(e.Days)
FROM scheduletb a
INNER JOIN scheduletb b
ON a.Train_Number = b.Train_Number
AND b.Time > a.Time
INNER JOIN traindetailtb d
ON a.Train_Number = d.Train_Number
INNER JOIN traindaystb e
ON a.Train_Number = e.Train_Number
WHERE a.Station = 'CDE'
AND b.Station = 'XYZ'
GROUP BY a.Train_Number, d.Train_Name
assuming that you have a real time field for the time
If you wanted only the trains that went directly from CDE to XYZ with no intermediate stations you could add a LEFT OUTER JOIN to the table looking for stations with a time between the other 2:-
SELECT a.Train_Number, d.Train_Name, GROUP_CONCAT(e.Days)
FROM scheduletb a
INNER JOIN scheduletb b
ON a.Train_Number = b.Train_Number
AND b.Time > a.Time
LEFT OUTER JOIN scheduletb c
ON a.Train_Number = c.Train_Number
AND c.Time > a.Time
AND c.Time < b.Time
INNER JOIN traindetailtb d
ON a.Train_Number = d.Train_Number
INNER JOIN traindaystb e
ON a.Train_Number = e.Train_Number
WHERE a.Station = 'CDE'
AND b.Station = 'XYZ'
AND c.Station IS NULL
GROUP BY a.Train_Number, d.Train_Name

Answer 6

If you want to visualize the days in one single cell instead of spread into multiple rows, use GROUP_CONCAT, which acts as a aggregator-function.
select tde.train_number, tde.train_name, GROUP_CONCAT(tda.days, ",") as days
from traindetailtb tde
join traindaystb tda on tda.train_number=tde.train_number
where tde.from = $user_input_from
and tde.to = $user_input_to
group by tde.train_number, tde.train_name