I need a query to count the duplicate records,
For Example
table name -customer
===================
customer_id-col name
222
111
222
222
111
122
output would be
customer_id count
222 3
111 2
222 3
222 3
111 2
122 1
i tried this query
SELECT customer_id,count( customer_id ) c
FROM customer
GROUP BY customer_id
HAVING c >1
output is
customer_id count
222 3
111 2
122 1
Is this possible Thanks in advance
Thanks
Raja
Try this
SELECT T.customer_id,S.duplicate_count FROM
(
SELECT customer_id,count(customer_id) AS duplicate_count
FROM yourtable group by customer_id
HAVING (duplicate_count > 0)
) AS S Join yourtable On S.customer_id = T.customer_id
FIDDLE DEMO
OP:
customer_id count
222 3
111 2
222 3
222 3
111 2
122 1
select customer_id,count(1) as count
from customer
group by customer_id
Related
I have 4 tables (1 to many):
Dont say anything about that "email" relation. It is how my developer boss built it years ago.
EMPLOYEES (+-50 results)
------------------------------------------------
id name
1 EmpName 1
2 EmpName 2
CUSTOMERS (+50k results)
------------------------------------------------
id name email employee_assigned
1 John john#doe.com 12
2 Donald donald#duck.com 6
INTERESTS_CATEGORIES (+650k results)
------------------------------------------------
id customer_email category_id
1 john#doe.com 97
2 john#doe.com 13
3 donald#duck.com 56
4 donald#duck.com 126
5 donald#duck.com 45
INTERESTS_PRODUCTS (+650k results)
------------------------------------------------
id customer_email product_id
1 john#doe.com 78
2 john#doe.com 23
3 donald#duck.com 19
4 donald#duck.com 56
5 donald#duck.com 45
So I need to filter the customers by their assigned employee and their interests.
And here is the query:
SELECT
*
FROM
(
SELECT
customers.id AS 'id',
customers.name AS 'first_name',
customers.email,
employees.id AS 'employee_id'
FROM
customers,
employees
WHERE
employees.id = 2
AND
customers.employee_assigned = employees.id
) AS myCustomers
LEFT JOIN interests_categories
ON interests_categories.customer_email = myCustomers.email
LEFT JOIN interests_products
ON interests_categories.customer_email = myCustomers.email
WHERE
(
interests_categories.category_id = 20
OR
interests_categories.category_id = 21
)
GROUP BY myCustomers.email
So, the problem:
If the employee has a low number of assigned customers (like 3) query
is successfull.
If the employee has a medium-high number of assigned customers (over 100) query stucks.
I execute SHOW PROCESSLIST and it is stucked "Generating temp table".
Anyone has idea? :(
Thank you.
Check the indexes on your tables and try this:
SELECT
c.id AS 'id',
c.name AS 'first_name',
c.email,
e.id AS 'employee_id'
ic.*,
ip.*
FROM customers c
JOIN employees e
ON c.employee_assigned = e.id
LEFT JOIN interests_categories ic
ON ic.customer_email = c.email
LEFT JOIN interests_products ip
ON ic.customer_email = c.email
WHERE
(
ic.category_id IN (20,21)
AND e.id = 2
)
GROUP BY myCustomers.email
Incidentally, a less dumb design might look like as follows. If it was me, I'd start with this, and provide properly representative CREATE and INSERT statements accordingly. Also, I'm curious about where category_id comes from - because that's potentially an area for further optimization.
EMPLOYEES
------------------------------------------------
employee_id name
6 EmpName 1
12 EmpName 2
CUSTOMERS
------------------------------------------------
customer_id name email employee_assigned
1 John john#doe.com 12
2 Donald donald#duck.com 6
INTERESTS_CATEGORIES
------------------------------------------------
customer_id category_id
1 97
1 13
2 56
2 126
2 45
INTERESTS_PRODUCTS
------------------------------------------------
customer_id product_id
1 78
1 23
2 19
2 56
2 45
Imagine you have a members with distinct member_ids and dates of service
you now need to order the dates of service in ascending order and return the order of these dates in another column (date_count). the final result will look like this:
memberid name date date_count
122 matt 2/8/12 1
122 matt 3/9/13 2
122 matt 5/2/14 3
120 luke 11/15/11 1
120 luke 12/28/14 2
100 john 1/12/10 1
100 john 3/2/12 2
100 john 5/30/12 3
150 ore 5/8/14 1
150 ore 9/9/14 2
here is the query that works but does not return the date_count in ranking (1,2,3) order. This instead returns the same number for date_count, not sure why the num
memberid name date_count
122 matt 3
122 matt 3
122 matt 3
120 luke 5
120 luke 5
120 luke 5
100 john 6
100 john 6
150 ore 2
150 ore 2
SELECT A.MEMBERID, A.NAME,A.DATE, COUNT(B.DATE) AS DATE_COUNT FROM #WCV_COUNTS A
INNER JOIN #WCV_COUNTS B
ON A.MEMBERID <= B.MEMBERID
AND A.MEMBERID= B.MEMBERID
GROUP BY A.MEMBERID, A.NAME, A.DATE
ORDER BY A.MEMBERID
Thanks for help in advance!
Use ROW_NUMBER()
SELECT memberid, name, date,
ROW_NUMBER() OVER (PARTITION BY memberid ORDER BY date) AS date_count
FROM #WCV_COUNTS
ORDER BY memberid, date
i have a table like :
id_cat id_city
1 33
1 33
1 33
2 44
2 33
2 55
and i want to obtain a result like :
id_cat id_city cat_count
1 33 3
2 44 1
2 33 1
2 55 1
how can i build my query ?
Thanks!
Use COUNT() which is an aggregate function and a GROUP BY clause.
SELECT id_cat, id_city, COUNT(*) cat_Count
FROM tableName
GROUP BY id_cat, id_city
SQLFiddle Demo
This is my table structure:
rec_id product_id quantity quantity_in quantity_out balance stock_date status
1 2 342 NULL 17 325 2009-10-23 1
2 2 325 NULL 124 201 2009-10-23 1
3 1 156 NULL 45 111 2009-10-23 1
4 2 201 NULL 200 1 2009-10-23 1
5 2 1 NULL 1 0 2009-10-23 1
6 1 111 NULL 35 76 2009-10-23 1
All I want is the last transaction done for a given product: product_id, quantity, quantity_out and balance from this table.
Example, there are 2 transaction done for product 2 (ids 1 & 2):
final balance for product_id 2 is 0 -> stored in rec_id 5
final balance for product_id 1 is 76 -> stored in rec_id 6
Final result/output should be like this:
recid productid quantity quantityin quantityout balance stock_date status
5 2 1 NULL 1 0 2009-10-23 1
6 1 111 NULL 35 76 2009-10-23 1
You can find the latest record for each product like:
select max(rec_id) as MaxRec
from YourTable
group by product_id
Using a subquery, you can retrieve the latest rows for their product:
select *
from YourTable
where rec_id in (
select max(rec_id) as MaxRec
from YourTable
group by product_id
)
Here's a single query with no subqueries:
SELECT main.*
FROM YourTable main
LEFT JOIN YourTable newer
ON newer.product_id = main.product_id AND newer.rec_id > main.rec_id
WHERE newer.rec_id IS NULL;
You can tweak the field list however you want--make sure you select fields from main, not newer, which should be all null.
I have a table that looks like this:
posid sales eid
1 20 001
1 20 002
1 30 001
2 30 001
1 30 002
2 30 001
1 30 002
2 20 002
2 10 002
I want to write a query that would give me sum of sales for each employee on particular pos. the result needs to be like this.
pos id emp id sales
1 001 50
1 002 80
2 001 60
2 002 30
How would I do this?
Use group by:
select t.posid
, t.eid
, sum(t.sales) as sales_by_posid
from mytable t
group by t.posid, t.eid
order by sales_by_posid desc
SELECT
posID, empID, sum(sales)
FROM your_table
GROUP BY posID, empID
ORDER BY posID, empID
Here's a group by tutorial: http://www.tizag.com/mysqlTutorial/mysqlgroupby.php