I need to get the week number between 2 dates, considering the week ends on Sunday ( may not be 7 days )
for clarification assume the dates are (01-Apr-2014, 31-May-2014)
so the date ( 03-Apr-2014) should be in the first week
and the date ( 06-Apr-2014) will be the first day of the second week and so on.
thanks on advance
SELECT YEARWEEK(#SoughtDate) - YEARWEEK('2014-04-01') + 1
Related
I am attempting to get a query that selects the week prior (Sun-Sat). I've fought with this query and the closest I can get is the last 7 days, using the following:
SELECT *
FROM dates
WHERE date BETWEEN CURDATE()-INTERVAL 1 WEEK AND CURDATE();
I'm really unsure how to proceed from here. It seems as if I need to create some kind of relation between CURDATE() and the Saturday before maybe?
Any help is appreciated.
You are after the Week of the year.
Look at the Week Function: WEEK(date[,mode])
http://dev.mysql.com/doc/refman/5.7/en/date-and-time-functions.html#function_week
The mode describes how you define the week (which is the start of the week)
WEEK(date,3) is for a week that starts Monday.
SELECT *
FROM dates
WHERE
-- Last Week
WEEK(date,3) = WEEK(CURDATE(),3)-1
AND YEAR(date)= YEAR(CURDATE()) ;
Don't forget the year. Week is just a number between 1 and 52. So the Year is important!
The code above is not correct. it will fail on the last week of the year!
I need stats on orders, week by week, so I have done this:
SELECT YEAR(orders.date), WEEKOFYEAR(orders.date), COUNT(*)
FROM orders
GROUP BY YEAR(orders.date), WEEKOFYEAR(orders.date)
It worked for one year, but just now (new year) it does not count the last days of 53rd week (jan 1st, 2nd, 3rd). How can I update my Query in order to have the full last week (from Monday 2015-12-28 to Sunday 2016-01-03)?
You need to switch to YEARWEEK(orders.date,3) to get the ISO weeks as a single column. Using WEEK(orders.date,3) (which is exactly the same as WEEKOFYEAR) will return the correct week number, but YEAR(orders.date) will return either 2015 or 2016, splitting the week into four days in 2015 and and three days in 2016.
As Strawberry mentioned in the comments you're looking for the WEEK function. I just checked the documentation at the MySQL website.
Week(date [,mode])
This function returns the week number for date. The two-argument form of WEEK() enables you to specify whether the week starts on Sunday or Monday and whether the return value should be in the range from 0 to 53 or from 1 to 53. If the mode argument is omitted, the value of the default_week_format system variable is used
Here's an example
SELECT WEEK('2008-12-31',1);
=> 53
It should also be noted that this is not the same as the WEEKOFYEAR function.
Returns the calendar week of the date as a number in the range from 1 to 53. WEEKOFYEAR() is a compatibility function that is equivalent to WEEK(date,3).
We can see that the value of the mode parameter here is 3. Here is the table that shows the values for the modes
Mode First day of week Range Week 1 is the first week
0 Sunday 0-53 With a Sunday in this year
1 Monday 0-53 With 4 or more days this year
2 Sunday 1-53 With a Sunday in this year
3 Monday 1-53 With 4 or more days this year
4 Sunday 0-53 With a Sunday in this year
5 Monday 0-53 With 4 or more days this year
6 Sunday 1-53 With a Sunday in this year
7 Monday 1-53 With 4 or more days this year
Source
https://dev.mysql.com/doc/refman/5.0/en/date-and-time-functions.html#function_week
As I understand you, you want calculate total orders for one week only once not twice for various years.
I've written SQL query for SQL Server, but I think you can easy rewrite it on mysql.
DECLARE #test_table TABLE(created_date DATETIME, VALUE INT)
INSERT INTO #test_table
SELECT N'20151231', 10
UNION ALL
SELECT N'20151228', 20
UNION ALL
SELECT N'20160101', 40
UNION ALL
SELECT N'20160104', 5
UNION ALL
SELECT N'20160107', 2
SELECT first_day_week_number,
SUM(value) AS total
FROM
(SELECT *,
DATEPART(ww,
DATEADD(dd, -DATEPART(dw, created_date)+2, created_date)) AS first_day_week_number
FROM #test_table ) AS T
GROUP BY first_day_week_number
To avoid problems with years you could calculate first week day of order date and then get week number from it.
I'm looking for the MySQL query to select date records that fall within the next week using Sunday - Saturday as the format for the week.
So in other words, I'm not looking to get the dates a week from today, I'm looking to get the dates that fall within Sunday - Saturday of the next week.
I found this: MySQL Query to select data from last week? and it works for the previous week from Sunday - Saturday but I'm not sure how to tweak this to get the dates for the next week.
Any ideas?
SELECT * FROM table
WHERE
date > date_add(curdate(),INTERVAL(7-dayofweek(curdate()))DAY)
AND date <= date_add(curdate(),INTERVAL(14- dayofweek(curdate()))DAY)
You can use:
SELECT *
FROM YourTable
WHERE WEEK(YourDateField, 6) = WEEK(CURRENT_DATE + INTERVAL 7 DAY, 6)
for selecting recods of next week (starting with sunday)
Weeks count is 1 to 53 with first week of the year having at least 4 days in the year
I have a select statement of which needs to base its WHERE on a timestamp but for all dates within that week beginning monday.
The MySQL
SELECT DISTINCT(unique_reference) AS unique_reference, date(datetime) AS datetime
FROM sales_tickets
WHERE Date(datetime)='$datetime'
This is based on the fact that $datetime can be any date but the select statement needs to get all records from that week, example: if its the Monday 12th May 2014, it will fetch all results from that week, instead of the one day.
Currently, its fetching only one day of results.
I have no idea how to rectify this issue. Any advise would be awesome thanks.
You can compare using the WEEK function :
WHERE WEEK(DATE(datetime)) = WEEK('$datetime')
If you have multiples years for entries, you can use instead the YEARWEEK function.
Edit for first day of week:
WEEK and YEARWEEK functions have both a second optional argument which tells when a week start. Try to consider mode 1 or 5.
Mode First day of week Range Week 1 is the first week …
0 Sunday 0-53 with a Sunday in this year
1 Monday 0-53 with 4 or more days this year
2 Sunday 1-53 with a Sunday in this year
3 Monday 1-53 with 4 or more days this year
4 Sunday 0-53 with 4 or more days this year
5 Monday 0-53 with a Monday in this year
6 Sunday 1-53 with 4 or more days this year
7 Monday 1-53 with a Monday in this year
A sargable solution would explicitly calculate the start and end points of your desired range:
WHERE datetime >= DATE('$datetime') + INTERVAL 0 - WEEKDAY('$datetime') DAY
AND datetime < DATE('$datetime') + INTERVAL 7 - WEEKDAY('$datetime') DAY
The easiest method might be to have your WHERE statement check against a range of values, which you can calculate beforehand.
I'll assume you're using php.
So your SQL statement will be:
SELECT DISTINCT(unique_reference) AS unique_reference, date(datetime) AS datetime
FROM sales_tickets
WHERE (Date(datetime) > '$startDate')
AND (Date(datetime) < '$endDate');
You'll first have to figure out what $startDate and $endDate are:
$endDate = strtotime('Monday', time()); // might need to adjust this depending on when your week starts
$startDate = $endDate - 7*24*60*60; //one week before.
Be careful with converting times between unix timestamps and datetimes used in SQL, but you get the idea.
Try WEEK():
WHERE WEEK(datetime)=WEEK('$datetime')
Read more: WEEK()
i have day, month, year, value columns in one table, here i need to get every week average value in one month.
how to get that. please help me regarding this.
select avg(value) from table group by month
gives month average.
select avg(value) from table group by day
gives day average.
but how to get week average from month field.
You can't "get weeks from a month" as one is not a subset of the other.
The number of days (and hence weeks) in 1 month varies from month to month and only in non-leap years - and in February only - are there exactly 4 weeks in a month.
You should use the original date field and use a date function to limit/group the data by week.
get the week in mySQL with
WEEK(timestamp)
or
YEARWEEK(timestamp)
or
WEEKOFYEAR(NOW())
or
DATE_FORMAT($yourDate, \'%X %V\') as week
There might be a better way, but my first thought is to write a query that calculates the week of the year for each day and groups them.
http://dev.mysql.com/doc/refman/5.5/en/date-and-time-functions.html#function_weekofyear
Something like:
SELECT avg(value) FROM table GROUP BY WEEKOFYEAR(CONCAT(year, '-', month, '-', day))