css background image repeat until specific height - html

Is there a CSS way to stop a repeating background image at a specific position?
HTML:
<div class="container bgimage">
This is the content
</div>
CSS:
.container
{
height:100%;
}
.bgimage
{
background-image:url('bg.png');
background-repeat:repeat;
}
I want to repeat the image horizontally and vertically at position 0 and stop repeating when the repeating image is reaching vertical height: 400px, like a max-height but only for the background and without shrinking the .container DIV.
I know how this can be done with gradient backgrounds, but is there also a solution for repeating image backgrounds when the .container DIV is even higher than 400px?
Example CSS Gradient:
linear-gradient(to bottom, rgba(255, 255, 255, 0) 0%, #FFFFFF 400px) repeat fixed 0 0 rgba(255, 255, 255, 0)
...
Now I want to do the same with an image, and stop it at 400px.

hope it will help you
.youclass:after{
content:"";
position:absolute;
top:0;
left:0;
right:0;
bottom:0;
background:url(path/image.png) repeat-y;
}
demo

Although I don't know if what you're asking for is possible, I have a solution that may work for what you need.
What you can do is create a div outside of your container div that will serve as your 400px high repeated background.
HTML:
<div class="tile-background"></div>
<div class="container">
Hello, Luigi.
</div>
CSS:
.container {
z-index: 0; /* MAKES the container appear on top of other elements */
position: absolute; /* REQUIRED for z-index */
}
.tile-background {
/* REQUIRED FOR Z-INDEX ... positions the div in reference to the window */
position: absolute;
top: 0px; /* positions div's top at the top edge of the window */
left: 0px; /* positions div's left side at the left edge of the window */
width: 100%;
height: 400px;
background-image: url(bg.png);
background-repeat: repeat;
}
Here is a preview of the the code does:
http://jsfiddle.net/Ember_Hawk/WP5Zu/1/
Essentially, you create a div that appears behind all other elements and does not affect their positioning.
If you need the background to start where the container div starts with respect to its position on the y-axis, you just change the "top" attribute of the "tile-background" class.
If you have an element with dynamically changing height that lies above your container, then this really wouldn't work without some help.
Hope I helped! Good luck! =)

Related

Center fixed background of container

I want to create a header with a fixed background. So I defined the following properties:
header {
margin: 0;
padding: 0;
width: 100%;
height: 300px;
display: block;
background-image: url('...');
background-repeat: no-repeat;
background-size: cover;
background-position: center;
background-attachment: fixed;
}
Now I have the following problem. Currently, the background is centered according to the Screen Width and Height. Since the header is at the top, the actual background of the header is just the top of the image. In addition, the header image section changes every time I change the screen height, which is not my goal.
I want the image to be centered within the header (center of the image is at the center of the header, but only if I have not scrolled down). In addition, the header image section should only change if I change the header width, height or screen width but not if the screen height is changed.
You can rely on vh unit combined with some calc(). The center is initally 50vh and you want it to be 150px from the top so we need a translation of 50vh - 150px. You should also get rid of cover if you want the image to not change when the screen height change but it may not render like you want.
I replaced 300px with 100px for the demo.
.header {
height:100px;
border:1px solid;
background:
url(https://picsum.photos/id/1014/1200/800) 50% calc(50% - (50vh - 50px)) fixed;
}
.not-fixed {
background-attachment:initial;
background-position:center;
margin-top:20px;
}
body {
min-height:200vh;
margin:0;
}
<div class="header">
</div>
<div class="header not-fixed">
</div>
With the use of cover
.header {
height:100px;
border:1px solid;
background:
url(https://picsum.photos/id/1014/1200/800) 50% calc(50% - (50vh - 50px))/cover fixed;
}
.not-fixed {
background-attachment:initial;
background-position:center;
margin-top:20px;
}
body {
min-height:200vh;
margin:0;
}
<div class="header">
</div>
<div class="header not-fixed">
</div>
You can clearly see how the first image is centred exactly like the second one without fixed
To get more details about the caluclation check this: Using percentage values with background-position on a linear gradient (the section Combining pixel and percentage values)
Try to wrap the img (outside the header div) and header div and play with position relative/absolute to superimpose header on top of the image.
Having done that, you can use z-index to push image backwards

Add multiple backgrounds on a angular component and keep them aligned to each other and responsive

I am working on a promo site with angular 7,
the designer gave me 2 background pictures that complete each other, 1 of them is a real footage with a highlighted part (already in the photo) that should be aligned with the other background.
1) What i should do in order to align between the two and make them responsive.
also should i use img tag or background css.
2) What is the better approach for this kind of issues (should i ask the designer to give me the full background with all elements?)
The last thing i tried is using the img tag which was fine until i added some text with z-index to be on top of the image. i used position: absolute and position:relative in order to insert the elements on top of the background but that scramble everything.
Here is the html:
<div class="main-page-container">
<div class="join-company-container">
<img src="assets/img/photo-bg.jpg" class="responsive" alt="Standing">
<app-join-company class="app-join-company"></app-join-company>
</div>
<div>
<img src="assets/img/rectangle-fill-left.svg" class="responsive-image-left" alt="Smiley face">
</div>
</div>
Here is the css:
.main-page-container {
height: auto;
}
.responsive {
width: 100%;
height: auto;
z-index: -1;
position: absolute;
}
.responsive-image-left {
width: 29.2%;
height: auto;
z-index: -1;
}
.app-join-company {
position:relative;
z-index:1;
}
** app-join-company - is the component that has the text + other elements on top of the first background.
Please note that you don't have any class app-join-company . Only a component called like that (you only have class join-company-app ). I am guessing there is the text. But the text is not actually positioned relative due to the typo.
Also you don't use the class responsive-image-right anywhere.
In adition to this z-index only works on positioned elements(position: absolute, position: relative, position: fixed, or position: sticky). So it won't work for .responsive-image-right or .responsive-image-left.
Inside the body, pass the urls of the background images separated by commas, set the size of each image in the background-size property (separated by commas). Position the background images as needed using the background-position property by setting the top/bottom and left/right for each image (the first value sets the position of the first image and so on).
body {
margin: 0;
padding: 0;
width: 100%;
height: 100%;
background-position:
top 16vh left -9vw,
top 77vh left 24vw,
top -30vh right -10vh,
top 91vh right 8vw,
bottom -126vh left 0em
;
background-size: 30%, 20%, 56%, 25%, 100%;
background-repeat: no-repeat;
background-image:
url('/assets/images/img1.svg'),
url('/assets/images/img2.svg'),
url('/assets/images/img3.svg'),
url('/assets/images/img4.svg'),
url('/assets/images/img5.svg')
;
}

Skew bottom background css

I want to reproduce my mockup : http://imgur.com/ZsR88fe
But I don't know how to skew my background image, only at the bottom. For nom I try the transform skew but all the image is skewed and The top of the page look ugly :
http://imgur.com/TkUgppW
What can I do to fix it ?
Thanks in advance
Skewed or Slanted div, hero or landing pages could be made quickly using the clip-path CSS property with polygon function.
clip-path: polygon(0 0, 100% 0, 100% 100%, 0 100%); //This makes a complete square
The skew could be made reducing the percentage in each angle.
Here's how to make skew on any components.
.skew {
height: 50vh;
width: 100%;
clip-path: polygon(0px 0px, 100% 0px, 100% 80%, 0px 100%);
background:#0a3;
}
<div class="skew">
<h1> Hey there </h1>
</div>
To make a bottom skew for your image with CSS, you're gonna need a few wrappers:
Content div for all the text
Image wrapper that will create the skew and hide the skewed area
Image div that contains nothing but the hero picture
Then you need to apply the opposite skew to the image div to make it not distorted. After that you have to mess around with positioning to ensure that as much of the image is visible and the top skew is hidden. Maybe there's a more clever solution, I just use hardcoded pixel values.
Here's the demo, and here's the important bits:
HTML
<div class="hero">
<div class="bg-img-wrapper">
<div class="bg-img"></div>
</div>
<div class="hero-content">
<h1>Cool company slogan</h1>
<p>Catchy subslogan</p>
</div>
</div>
SCSS (you can just replace the variables and it will be valid CSS, but they help with readability here)
$skewDeg: 5deg;
$offset: 70px;
.hero {
height: 100vh; // Make the hero area take 100% height
overflow: hidden; // Child's skew will cause overflow, so we hide it here
position: relative; // Children will be positioned absolutely relative to this
}
.bg-img-wrapper {
transform: skewY($skewDeg);
position: absolute;
top: -$offset; // Move the top skew offscreen
bottom: $offset; // Move the skewed area up a bit so more of it is visible
right: 0;
left: 0;
overflow: hidden; // Hide the areas that we skewed away
}
.bg-img {
background: url('https://unsplash.it/1280/720/?random') center no-repeat;
background-size: cover;
position: absolute;
top: $offset; // Move the image down by the amount of the parent that's being rendered offscreen
bottom: -$offset;
right: 0;
left: 0;
transform: skewY(-$skewDeg); // Skew the opposite amount of the parent to make the image straight again
}
.hero-content {
position: relative; // Relative positioning here makes the hero content visible
}

css percentages height and width

I understand that in order for an element to be height 100% of the viewport the parent has to have a fixed height or for html and body to be height 100%.
My problem is I have an introduction title which I want in the middle of the screen, easy I thought, I will make a div 100% width and height then the user scrolls down to reach the rest of the content... Not so easy. For the div to be 100% height I need to make html height 100% but when I do that the gradient background repeats itself as it reads the height of the viewport (html 100%) and not the content.
The site is here.
Code:
<div class="intro">
<div class="intro_text">
<h2><?php the_title(); ?></h2>
<h3><?php the_date('Y'); ?></h3>
</div>
</div>
<div id="content">
<!--The user scrolls down to see this-->
</div>
html {
width: 100%;
height: 100%;
}
body {
width: 100%;
height: 100%;
background-color: #004000;
background: -webkit-gradient(linear, 0% 0%, 0% 100%, from(#ec448c), to(#5a94bc));
background: -webkit-linear-gradient(top, #ec448c, #5a94bc);
background: -moz-linear-gradient(top, #ec448c, #5a94bc);
background: -ms-linear-gradient(top, #ec448c, #5a94bc);
background: -o-linear-gradient(top, #ec448c, #5a94bc);
}
.intro {
width: 100%;
height: 100%;
}
You can do the negative margin trick:
.intro {
height: 200px;
width: 200px;
position: absolute;
top: 50%;
left: 50%;
margin: -100px 0 0 -100px;
}
That will center the div in the viewport as long as all the ancestors don't have a position. The trick is that you position the div 50% of the viewport width and height away from the top left corner. Then you just use a negative margin equal to half the height and width of your .intro div in the top and left margins (this will center the div over the new center point).
Note: If you adjust the height and width, you should also adjust the negative margin (ex. if you change the width to 300, the negative left margin should be 150 - half the width) Also, this trick should work as far back as IE6, so no worries.
I'm a little confused by you question but if you don't want your background to repeat, you could try
body { background:url(your_image.jpg) top no-repeat; background-position:fixed; }
For fixing your background : Instead of applying your gradient to body, use another fixed element
div#mybackground {
position:fixed;
top:0;
left:0;
right:0;
bottom:0;
z-index:-1;
background: ..gradient..;
}
Now, on your site you can do
.intro_text {
height:100%;
}
And then using JavaScript, set line height of .intro_text to same value as height of .intro_text, and add this to your h3 :
.intro_text h3 {
position:relative;
top: -90%;
}
A better alternative to top -90% will be setting top to negative value of the height of .intro_text
Set the background to the html and add a overflow: hidden to it.
Then add a overflow: auto to the body.
Demo

another css 100% height question

Sorry but I can't get this to work. Should be a quick answer.
My html is laid out like so:
<html>
<header>
...
</header>
<body>
<div class = "background"></div>
<div class = "content">
...
</div>
<body>
</html>
The I want the background div to simply place a 1000px background colour down the entire length of the page. The content is then padded 40px on each side, inside this background colour.
The css is like so:
body {
width:1000px;
margin-left:auto;
margin-right:auto;
}
.background {
position:absolute;
top:0px;
width:1000px;
height:100%;
}
.content {
min-height:100%;
padding-left:40px;
padding-right:40px;
}
I thought it worked like so... The body div would expand to hold the min-height of the .content div. This means that 100% height of the .background div would fill the entire body and so the length of the page. However it does not. It only fills the window height. Where am I going wrong?
Thanks
As topek guessed, this will do it:
html, body{
height:100%
}
The reason this works is because percentage CSS heights only work if the parent element has a height defined on it. By adding the above, you're giving .background's parents a height.
Update: based on OP's comment, here's how you would get the .background div to always appear to fill the viewport:
html, body {
height: 100%;
padding: 0;
margin: 0;
}
/* Fixed element that takes up entire viewport */
.background {
position: fixed;
z-index: 1;
top: 0;
left: 0;
width: 100%;
height: 100%;
}
/* Content that stacks above .background */
.content {
position: relative;
z-index: 2;
}
As .content grows larger than the viewport and the user scrolls, the fixed position of .background will keep it always in view.
And of course, a handy example.
All you need is:
body, html {
height:100%
}
Then specify height:100%; any DIV you want to have full height.
BTW - 1000px wide is a bad unit to use. People with 1024 wide screens will get horizontal scrollbars. Better to stick to 980 or less. 960 is good because it can be divided by many factors.
I think this is what you're looking for.
http://jsfiddle.net/sg3s/GxRcp/
The key in this little example is the position: fixed; for .background so that it is kept in the screen while scrolling.
If you don't really want to do this and want the background to expand ARROUND the content just make it a normal / relatively positioned element, and wrap it arround .content...
If you give a more acurate description of the layout you're trying to create (and maybe why in such a way) we may be able to help you better.
Btw, in your example html there is an error, header should be head.
You should put bg into html or body elements as the first choices.
html { background: url("bg.jpg") no-repeat top center; }
or
body { background: url("bg.jpg") no-repeat top center; }
Fixed:
background: url("bg.jpg") no-repeat top center fixed; /* And bg will stay in fixed position */