Counting Distinct values from Sql Table - mysql

Following is a view of my table...
I am getting a hard time in getting desired result from a query.
My requirement looks like below image
It should be conditioned as follows --
1)Within start date and end date.
2)No as Pending .
3)Yes as Completed.
4)No+Yes as Total.
5)Based On only one survey Type.
This is what i have tried and got result for above mentioned 1 to 4 condition , but how to impliment 5 condition ?
SELECT DISTINCT Userid
,CASE
WHEN [YES] IS NULL
THEN 0
ELSE [YES]
END AS Completed
,CASE
WHEN [NO] IS NULL
THEN 0
ELSE [NO]
END AS Pending
,(
CASE
WHEN [YES] IS NULL
THEN 0
ELSE [YES]
END + CASE
WHEN [NO] IS NULL
THEN 0
ELSE [NO]
END
) AS Total
FROM (SELECT DISTINCT Userid
,SurveyStatus
,COUNT(ParcelId) AS cnt
FROM ParcelAllocationsurvivor
WHERE DateAllocated >= '2013-08-01'
AND DateAllocated <= '2013-08-07'
GROUP BY Userid
,SurveyStatus
) AS p
PIVOT(max(cnt) FOR surveystatus IN ([YES],[NO])) AS pvt
ORDER BY Userid
Can anybody help me out in it.
thanks in advance////

You would add a where clause into the subquery:
SELECT Userid, (case when [YES] is null then 0 else [YES] end) as Completed,
(case when [NO] is null then 0 else [NO] end) as Pending,
(case when [YES] is null then 0 else [YES] end +
case when [NO] is null then 0 else [NO] end
) as Total
FROM (SELECT Userid, SurveyStatus, COUNT(ParcelId) as cnt
FROM ParcelAllocationsurvivor
WHERE DateAllocated >= '2013-08-01' and DateAllocated <='2013-08-07' and
SurveyType = 'Survey1'
group by Userid, SurveyStatus
) AS p
PIVOT(max(cnt) FOR surveystatus IN([YES],[NO])) AS pvt order by Userid;
By the way, the select distinct are redundant. You do not need them for this query.

Related

MySQL : using sum in( case when ) statement shows 0 as result

new to MySQL..so pls help me out with this basic code..
i have a query something like this...
select weekofyear(id_time),
(id),
#Tat1:=exp1,
#Tat2:=exp2,
#check1:=exp3,
#check2:=exp4,
(case when #check2=0 then
(case when (#Tat1>(#Tat2+30) or (#check1=1 and (#Tat1>#Tat2+10))) then 1 else 0 end)
else
(case when (#Tat1>(#Tat2+30) or (#check1=1 and (#Tat1>#Tat2+20))) then 1 else 0 end)
end) as BO
from datb
where cid=18
and id_time between '2019-11-01 06:00:00' and '2019-11-25 06:00:00'
and it gives correct results as--here
however i want to use sum after case when statement so that I can get total values where BO=1 and group by week of year , so i made following changes-
select weekofyear(id_time),
count(id),
#Tat1:=exp1,
#Tat2:=exp2,
#check1:=exp3,
#check2:=exp4,
sum(case when #check2=0 then
(case when (#Tat1>(#Tat2+30) or (#check1=1 and (#Tat1>#Tat2+10))) then 1 else 0 end)
else
(case when (#Tat1>(#Tat2+30) or (#check1=1 and (#Tat1>#Tat2+20))) then 1 else 0 end)
end) as BO
from datb
where cid=18
and id_time between '2019-11-01 06:00:00' and '2019-11-25 06:00:00'
group by weekofyear(id_time)
but it always returns 0 as output.
Output --here 2
Please help , I don't know what am I doing wrong here.
Thanx !
As others have already said, session variables can be unpredictable (especially when aggregation gets mixed in). That said, it doesn't look like you're using the session variables to carry over values from one row to the next (as is often done), but to just make aliases of sorts for calculations you don't want to repeat.
A better way to handle that is just through subqueries.
SELECT woy, id, Tat1, Tat2, check1, check2
, CASE
WHEN check2=0 THEN (
CASE
WHEN (Tat1>(Tat2+30) OR (check1=1 AND (Tat1>Tat2+10))) THEN 1
ELSE 0
END
)
ELSE (
CASE WHEN (Tat1>(Tat2+30) OR (check1=1 AND (Tat1>Tat2+20))) THEN 1
ELSE 0
END
)
END AS BO
FROM (
SELECT WEEKOFYEAR(id_time) AS woy
, id
, exp1 AS Tat1
, exp2 AS Tat2
, exp3 AS check1
, exp4 AS check2
FROM datb
WHERE cid=18
AND id_time BETWEEN '2019-11-01 06:00:00' AND '2019-11-25 06:00:00'
) AS subQ
;
You can then tweak the above query for aggregation, or use it as a subquery for an aggregating outer query.

MySQL CASE , SUM, GROUP BY

I want sum of payment status from two differnt columns based on paymentstatus value - but this query returns null for sum. Why is it not working?
select payment_status,
CASE
WHEN 'PAID' THEN sum(paid_amount)
when 'Not Paid' then sum(total_amount_due )
END
from monthly_fee
group by payment_status;
select sum(CASE WHEN payment_status = 'PAID' THEN paid_amount else 0 end) as paid,
sum(CASE WHEN payment_status = 'Not Paid' THEN total_amount_due else 0 end) as due
from monthly_fee
If you want this conditionally, you need to include the column in the case:
select payment_status,
(case payment_status
when 'Paid' then sum(paid_amount)
when 'Not Paid' then sum(total_amount_due )
end)
from monthly_fee
group by payment_status;
This seems like a strange way to write the query, unless you really want two rows.
Your WHEN clauses aren't a condition.
I'd expect to see something like
select payment_status,
CASE
WHEN payment_status = 'PAID' THEN sum(paid_amount)
when payment_status = 'Not Paid' then sum(total_amount_due )
END
from monthly_fee
group by payment_status;
You can try the following query:
select sum(if(payment_status = 'PAID', paid_amount, 0)
+ if(payment_status = 'Not Paid', total_amount_due, 0))
from monthly_fee
group by payment_status;

Sum of 2 fetched columns in other column in Big query SQL

select x,
count(case when i='abc' then 1 else null end) as ele1,
count(case when i='def' then 1 else null end) as ele2,
sum(ele1+ele2) as sum1 from (INNER QUERY)
When i am using sum(ele1+ele2), it is throwing error that ele1 not found. How to fetch sum1 in the same query without using any other outer query?
You can't use alias as column name in select
select x,
count(case when i='abc' then 1 else null end) as ele1,
count(case when i='def' then 1 else null end) as ele2,
sum( ( case when i='abc' then 1 else null end ) +
( case when i='def' then 1 else null end ) ) as sum1
from (INNER QUERY)
You cannot use alias as a column name, but if your concern is in verboseness - in your particular case you can write something like below, which is easy readable and skinny enough (for BigQuery Legacy SQL)
SELECT
SUM( i ='abc' ) AS ele1,
SUM( i = 'def' ) AS ele2,
SUM( i IN ('abc', 'def') ) AS sum1
FROM (INNER QUERY)

How to do a SELECT for total from beginning until the specified date in MySQL?

I have entry table:
I need to do a SELECT to receive 'Date', 'Number of entries' (in that date), 'Total number of entries until that date'.
When I do the SELECT:
SELECT e1.*,
(select count(*) from entry where date(dateCreated) <= e1.date) as Total
from (
SELECT
DATE(e.dateCreated) as "Date",
count(e.dateCreated) as "No of Entries",
sum( case when e.premium='Y' then 1 else 0 end ) as Premium,
sum( case when e.free='Y' then 1 else 0 end ) as Free,
sum( case when e.affiliateID IS NOT NULL then 1 else 0 end) as Affiliate
FROM entry e
WHERE e.competitionID=166
GROUP BY DATE(e.dateCreated)
) as e1
ORDER BY Date DESC
I've got a result table
but the column 'Total' has a wrong data.
How the correct select should be? Is this logic of select is the best and more efficient one?
Here is a demo
If it is just the 5 vs 7 that is off I think it is because that subquery in your select list, which accesses the inline view e1 (which is filtered to competitionID = 166), is not itself filtered when also utilizing the original entry table (unfiltered). You have to filter the original table to that competitionID as well.
Notice line 3 in sql below (only change)
SELECT e1.*,
(select count(*) from entry where date(dateCreated) <= e1.date
and competitionID=166) as Total
from (
SELECT
DATE(e.dateCreated) as "Date",
count(e.dateCreated) as "No of Entries",
sum( case when e.premium='Y' then 1 else 0 end ) as Premium,
sum( case when e.free='Y' then 1 else 0 end ) as Free,
sum( case when e.affiliateID IS NOT NULL then 1 else 0 end) as Affiliate
FROM entry e
WHERE e.competitionID=166
GROUP BY DATE(e.dateCreated)
) as e1
ORDER BY Date DESC
Fiddle - http://sqlfiddle.com/#!9/e5e88/22/0

MYSQL - Showing status input as it's own column

I'm having trouble writing a SQL query to show the status of a row as it's own column as shown in the picture.
I was thinking of using an alias for Status as:
SELECT 'Table A.Date', 'Table A.Status' as ... FROM Table A;
But this doesn't resolve the issue on how to display each status type as their own column and number value.
Can someone point out how to do this?
Try this one. I used CASE statement to conditionally count the status as one depending on the status type given.
SELECT
Date,
SUM(CASE WHEN Status='Pending' THEN 1 ELSE 0 END)Pending,
SUM(CASE WHEN Status='Completed' THEN 1 ELSE 0 END)Completed,
SUM(CASE WHEN Status='Cancelled' THEN 1 ELSE 0 END)Cancelled
FROM Table A
WHERE Date='2014-01-01'
GROUP BY Date
Try this:
select A.date,
count(
case
when A.Status='Pending'
Then 1
Else NULL
End
) as Pending,
count(
case
when A.Status='Completed'
Then 1
Else NULL
End
) as Completed,
count(
case
when A.Status='Cancelled'
Then 1
Else NULL
End
) as Cancelled
From A
group by A.date