I am using the User() to populate a table which returns something like (admin#localhost).
How would I return
1) only the items to the left of the # (if possible)
and
2) only the first 10 characters (if something like AnnaMariaSmith#localhost, just return AnnaMariaS)
Thanks
Something like this perhaps?
SELECT LEFT(USER(), LOCATE('#',USER()) - 1)
See it in action
If you want only the first 10 characters of the result above, just another LEFT function:
SELECT LEFT(LEFT(USER(), LOCATE('#',USER()) - 1), 10)
Related
I have a string /path/to/project/subdirectory/ and need to find a row where path is /path/to/project/.
How can I find rows where my string starts with path?
It would be the opposite of:
SELECT * FROM projects WHERE path LIKE "/path/to/%"
Because I have too many characters, not too few.
Both of these return zero rows:
SELECT * FROM projects WHERE path LIKE "/path/to/project/subdirectory/%"
SELECT * FROM projects WHERE "/path/to/project/subdirectory/" LIKE (path+"%")
You were close with your second attempt, but MySQL uses CONCAT() to concatenate strings, not +.
SELECT *
FROM projects
WHERE "/path/to/project/subdirectory/" LIKE CONCAT(path, '%')
You can also use
WHERE LOCATE(path, "/path/to/project/subdirectory/") = 1
My table contains some columns with ;-separated numbers like this :
1;2;43;22;20;12
and so on. It's also possible there's only 1 number in this column like 110, or 2 numbers like this 110;143
I want to select the rows that contain a certain number in this column. The number is in a variable $search_var.
Let's say I need to search for the number 1 in my column. If I use a select with like statement like so :
"SELECT * FROM Table WHERE ids LIKE '%".$search_var."%'"
I get all results containing '1' and not only '1', so I also get 11, 14, 110, 1999 etc.
I think I need to use some sort of regex-statement but I'm lost here... Who can help ?
You might not need regex for this
Set #YourNUmber := 110;
SELECT *
FROM Table
WHERE ';' + ids + ';' LIKE '%;'+ #yourNumber + ';%'
This guarantees there are always ; surrounding all the numbers.
This is formatted for SQL Server. The variable syntax and wildcards might be different if you are using something else.
EDIT:
Thanks #FélixGagnon-Grenier for the suggestions. I think either of these two will work. See here for a SQL Fiddle example
SELECT *
FROM T
WHERE concat(';',ids,';') LIKE concat('%;', #YourNumber , ';%');
SELECT *
FROM T
WHERE LOCATE(concat(';', #YourNumber , ';'),concat(';',ids,';'))>0
Try this solution if you're using SQL Server. This searches for the number where adjcent characters are not numbers:
SELECT * FROM Table WHERE ids LIKE '%[^0-9]".$search_var."[^0-9]%'
I use a string for store the days of the week, something like this:
MTWTFSS. And if I search for MF (Monday and Friday) then the query must return all the strings that contain MF (for example: MWF, MTWTFS, MF, and so on).
I don't know how to do this in SQL (MySQL).
use LIKE with %-wildcard between the single characters:
SELECT * FROM table WHERE column LIKE '%M%F%';
note that this will only work if the characters are in correct order - searching for FM instead of MF won't give you any result.
you'll also need to find a way to insert the %s to your search-term, but taht shouldn't be a big problem (sadly you havn't said wich programming-language you're using).
if the characters can be in random order, you'll have to built a query like:
SELECT * FROM table WHERE
column LIKE '%M%'
AND
column LIKE '%F%'
[more ANDs per character];
SELECT * FROM yourTable WHERE columnName LIKE '%MF%'
Learn more:
http://www.sqllike.com/
Can you not just say
SELECT * FROM blah WHERE weekday LIKE "%MF%"
i have field with content like this: 1, 2, 100 first two numbers can be any size third one can be up to 100.
Now i need to sort my fields by this third number but since i have 2 other numbers i don't know how to do it.
Maybe i could use something like REGEXP or something else?
So far i've tried SUBSTRING but since my two numbers can be any lenght something like
order by SUBSTRING(my_field, 4)
would work but if i have numbers like 32, 451, 30 it takes wrong numbers
Also i use php for to build my query, but i don't think it matters.
You can use SUBSTRING_INDEX. So something like:
SUBSTRING_INDEX(my_field, ',', -1)
EDIT: if you have spaces you might want to do some trimming as well.
ORDER BY SUBSTRING_INDEX(my_field,',',-1)+0 ASC -- or DESC
Use SUBSTRING_INDEX, which grabs the substring up to the nth occurence of the delimiter (in your case, comma), or, in the case of a negative n, it will return the substring after the nth occurence from the end.
To see what I mean try:
SELECT SUBSTRING_INDEX(my_field,',',-1)
FROM my_table
The reason there is a +0 in the ORDER BY is so that mysql sorts these as numbers, not strings.
This should work:
order by CONVERT(SUBSTRING(my_field, LOCATE(",", my_field, RIGHT)), INTEGER)
SELECT *
FROM (
SELECT
SUBSTRING(my_field, 4) AS my_field,
...
FROM
...
WHERE
...
) temp_table
ORDER BY my_field
I just ran into a problem.
I know these integers, $integers: 3,5,15,20.
I only want to select the rows from this following table where all comma separated INT's from the field NUMBERS are found.
TABLE: number_table
Uid Numbers
------------------------
1 3,5,15 OK, since all of NUMBERS are in $integers
2 5,15,20 OK, since all of NUMBERS are in $integers
3 3,4,5,15 NOT OK, since 4 is not found in $integers
4 2,15,20,25 NOT OK, since 2 and 25 is not found in $integers
Is it possible to do a "for-each" on a comma separated string or another way to do this SELECT?
UPDATE: It sounds like this is not possible. I will leave it here for little while. Just a hint. When searching for something in a comma separated string then MySQL provides the WHEERE something IN (comma separated string). What I What I look for is someway to traverse a comma separated string using MySQL but that might not be possible.
Something like this would do it (pseudocode):
SELECT * FROM number_table WHERE each_commaseparated_substring(Numbers , 'IN (3,5,15,20)')
It should NOT be comma separated fields.
It must be rows in the related table.
I haven't tried this, and it's a bit ugly and quite possibly slow but you can try the following.
3,5,15,20
SELECT * FROM number_table
WHERE Numbers (LIKE '%,3,%' OR LIKE '%3,%') AND Numbers LIKE '%,5,%' AND Numbers LIKE '%,15,%' AND Numbers (LIKE '%,20,%' OR LIKE '%,20%')
You may be able to do something with REGEX. But at the very least you could use a stored procedure.
Updated for correctness
Maybe try with concate code using PHP and the implode() function.
Correct the short answer is no, but despite being non-normal data there are solutions that are ugly so not recommended. Specifically make a split string function and loop through each value with a stored procedure.
Can MySQL split a column?
Mysql string split
You could check that the number of commas is one less than the number of search terms found:
SELECT * FROM number_table
WHERE CHAR_LENGTH(Numbers) - CHAR_LENGTH(REPLACE(Numbers, ',', '')) = -1
+ (FIND_IN_SET( 3, Numbers) > 0)
+ (FIND_IN_SET( 5, Numbers) > 0)
+ (FIND_IN_SET(15, Numbers) > 0)
+ (FIND_IN_SET(20, Numbers) > 0)
To create this from $integers using PHP:
$sql = "SELECT * FROM number_table
WHERE CHAR_LENGTH(Numbers) - CHAR_LENGTH(REPLACE(Numbers, ',', '')) = -1";
foreach ($integers as $i) $sql .= " + (FIND_IN_SET($i, Numbers) > 0)";