I'm trying to refine a query that I am currently using:
SELECT `puid`,
COUNT(DISTINCT `droid_v`) AS DROID,
COUNT(DISTINCT `sig_v`) AS sig,
SUM(NoExt) AS hits
FROM temp
GROUP BY `puid`
And I need to get it to only count droid_v where droid_V is greater than 0. Is it possible to condition the count in this way? At the moment, it is counting zero values as countable, and I can't really change the zeros to null values.
I do not need to know the count value for droid_V = 0, I only need to count it if it has a number greater than 0. That number will always be either 0, 1, 2, 3, or 4.
I have tried:
SELECT `puid`,
COUNT(DISTINCT CASE WHEN `droid_v` > 0 THEN 1 END) AS DROID,
COUNT(DISTINCT `sig_v`) AS sig,
SUM(`NoExt`) AS hits
FROM temp
GROUP BY `puid`
But this gives a binary result (either 0 or 1) not the count I am expecting.
example output =
puid DROID sig hits
No PUID 1 1 252
x-fmt/92 1 5 1008
anticipated output:
puid DROID sig hits
No PUID 1 1 252
x-fmt/92 3 5 1008
Sample data:
id;puid;droid_v;sig_v;speed;Ext;NoExt;tally
1;"No PUID";"3";"v13";"SLOW";"0";"63";"63"
2;"x-fmt/92";"3";"v13";"SLOW";"63";"0";"63"
3;"x-fmt/92";"3";"v37";"SLOW";"63";"63";"126"
4;"x-fmt/92";"3";"v45";"SLOW";"63";"63";"126"
5;"x-fmt/92";"3";"v49";"SLOW";"63";"63";"126"
6;"x-fmt/92";"3";"v50";"SLOW";"63";"63";"126"
7;"x-fmt/92";"5";"v13";"SLOW";"63";"0";"63"
8;"No PUID";"5";"v13";"SLOW";"0";"63";"63"
9;"x-fmt/92";"5";"v37";"SLOW";"63";"63";"126"
10;"x-fmt/92";"5";"v45";"SLOW";"63";"63";"126"
11;"x-fmt/92";"5";"v49";"SLOW";"63";"63";"126"
12;"x-fmt/92";"5";"v50";"SLOW";"63";"63";"126"
13;"No PUID";"6";"v13";"FAST";"0";"63";"63"
14;"x-fmt/92";"6";"v13";"SLOW";"63";"0";"63"
15;"No PUID";"6";"v13";"SLOW";"0";"63";"63"
16;"x-fmt/92";"6";"v13";"FAST";"63";"0";"63"
17;"x-fmt/92";"6";"v37";"SLOW";"63";"63";"126"
18;"x-fmt/92";"6";"v37";"FAST";"63";"63";"126"
19;"x-fmt/92";"6";"v45";"FAST";"63";"63";"126"
20;"x-fmt/92";"6";"v45";"SLOW";"63";"63";"126"
21;"x-fmt/92";"6";"v49";"FAST";"63";"63";"126"
22;"x-fmt/92";"6";"v49";"SLOW";"63";"63";"126"
23;"x-fmt/92";"6";"v50";"FAST";"63";"63";"126"
24;"x-fmt/92";"6";"v50";"SLOW";"63";"63";"126"
If droid_v can only be 0, 1, 2, 3, or 4, then COUNT(DISTINCT) will never return more than 5, since there are only five possible values. Is that what you want? If so, then try this:
SELECT puid, COUNT(DISTINCT CASE WHEN droid_v > 0 THEN droid_v ELSE 0 END) - 1 AS droid /* -1 for the case where droid_v is 0 */
, COUNT(DISTINCT sig_v) AS sig
, SUM(NoExt) AS hits
Update: Oops, sorry, the above is not quite right as there might not be a zero.
It should be:
SELECT puid, COUNT(DISTINCT CASE WHEN droid_v > 0 THEN droid_v END) AS droid
If, on the other hand, you want a count of all the rows where droid_v > 0, then I think you want this:
SELECT puid, SUM(CASE WHEN droid_v > 0 THEN 1 ELSE 0 END) AS droid
, COUNT(DISTINCT sig_v) AS sig
, SUM(NoExt) AS hits
Hope this helps.
Just use a sum
so if you want to group something check this out
select city, sum( case when gender = 'male' then 1 else 0 end ) as male,
sum( case when gender = 'female' then 1 else 0 end ) as female
from person
group by city
simple as this :D
SELECT
`puid`,
COUNT(DISTINCT CASE WHEN `droid_v` > 0 THEN `droid_v` END) AS DROID,
COUNT(DISTINCT `sig_v`) AS sig,
SUM(NoExt) AS hits
This is the simplest solution I can think of:
SELECT puid,
SUM(droid_v > 0) AS DROID,
COUNT(DISTINCT sig_v) AS sig,
SUM(`NoExt`) AS hits
FROM t
GROUP BY puid
However, it is not clear if you want to count the distinct or not. If you want to count the distinct values then:
SELECT puid,
COUNT(if(droid_v > 0, droid_v, null)) AS DROID,
COUNT(DISTINCT sig_v) AS sig,
SUM(`NoExt`) AS hits
FROM t
GROUP BY puid
add this to the query
WHERE droid_v > 0
Related
This should be easy but I have not found the answer. I have a query that is running a count and I want to group this within the query into those where State = 1 and State <>1 and have the sum for each group.
SELECT count(`id_job`) as count, `state`
FROM job_table
GROUP BY `state`;
You can query a boolean expression and group by it too:
SELECT state = 1, COUNT(*)
FROM job_table
GROUP BY state = 1
SELECT count(id_job) as count,state FROM job_table
GROUP BY case when state = 1 then 1 else 0
In MySQL, you can easily put these into columns:
select sum( state = 1 ) as state_1,
sum( state <> 1 ) as state_2
from job_table;
If state can be NULL, you want to be a bit careful. The second condition is safer as:
select sum( state = 1 ) as state_1,
sum( not state <=> 1 ) as state_2
from job_table;
Try this
SELECT SUM(CASE WHEN State=1 THEN 1 END) as count1,
SUM(CASE WHEN State<>1 THEN 1 END) as count2,
State
FROM job_table
GROUP BY state
I have a query that checks a group and makes sure that it has more than 1 value under 2
SELECT `tile` FROM TFResults
GROUP BY `tile`
HAVING SUM(CASE WHEN `Place` < 2 THEN 1 ELSE 0 END)> 1 ;
I would like to return the value of sum also but can't seem to get it to work
SELECT `tile`, thesum
FROM TFResults
GROUP BY `tile`
HAVING SUM(CASE WHEN `Place` < 2 THEN 1 ELSE 0 END) as thesum > 1 ;
You define alias names in the select clause
SELECT tile,
SUM(CASE WHEN Place < 2 THEN 1 ELSE 0 END) as thesum
FROM TFResults
GROUP BY tile
HAVING thesum > 1
First you need to move sum part to select statement. And if you need only one column to check then use if instead CASE. Check Below
SELECT tile, SUM(if(Place < 2, 1, 0)) place_sum
FROM TFResults
GROUP BY tile
HAVING place_sum > 1
Just move sum statement to select:
SELECT
`tile`,
SUM(CASE WHEN `Place` < 2 THEN 1 ELSE 0 END) AS thesum
FROM TFResults
GROUP BY `tile`
HAVING thesum > 1 ;
Say I have a table called votes, and a column in that table called vote_type which can either be 0 or 1. How can I fetch the COUNT of vote_type where vote_type is 1?
Right now, I can select the count of vote_type overall, but not the count of vote_type where it is 1 or 0, via this query:
SELECT COUNT(votes.vote_id) AS vote_count
FROM votes
WHERE <some condition>
ORDER BY vote_count
How can I select the total number of vote_types, the number of vote_types = 1, the number of vote_types = 0, and the total vote_value (votetypes = 1 minus votetypes = 0), and order it by the total vote_value?
EDIT: Note that 1 & 0 are not intrinsic values of a vote, but boolean expressions for a positive vote and a negative vote.
I don't know what exactly are you trying to do, but if you want to count all the votes with Vote_Type=1
try
SELECT COUNT(votes.vote_id) AS vote_count
FROM votes
WHERE votes.vote_type=1
or if you need to sum the votes
SELECT SUM(votes.vote_type) AS vote_sum
FROM votes
WHERE votes.vote_type=1
SELECT COUNT(*) TotalVotes,
SUM(CASE WHEN vote_type = 1 THEN 1 ELSE 0 END) TotalVoteOne,
SUM(CASE WHEN vote_type = 0 THEN 1 ELSE 0 END) TotalVoteZero,
SUM(CASE WHEN vote_type = 1 THEN 1 ELSE 0 END) -
SUM(CASE WHEN vote_type = 0 THEN 1 ELSE 0 END) TotalVoteValue
FROM votes
-- WHERE ....
-- ORDER ....
When you say order it by the total vote_value -- it actually doesn't makes sense since the total number of rows in the result is only one.
You can also wrap this in a subquery,
SELECT TotalVotes,
TotalVoteOne,
TotalVoteZero,
(TotalVoteOne - TotalVoteZero) AS TotalVoteValue
FROM
(
SELECT COUNT(*) TotalVotes,
SUM(CASE WHEN vote_type = 1 THEN 1 ELSE 0 END) TotalVoteOne,
SUM(CASE WHEN vote_type = 0 THEN 1 ELSE 0 END) TotalVoteZero
FROM tableName
-- WHERE ....
-- ORDER BY TotalVoteValue DESC
) a
Try to start with something like this:
SELECT SUM(CASE WHEN votetype = 1 then 1 else 0 end) AS vote_count_1,
SUM(CASE WHEN votetype = 0 then 1 else 0 end) AS vote_count_0
FROM votes
WHERE <some condition>
ORDER BY vote_count
Edit: Added a net_vote column, which I think is the "vote1 minus vote0" number you are after.
Select
Sum(Case v.vote_type When 1 then 1 else -1 end) as net_vote
From
Votes v
Where
<some condition>
I've removed the order by, because this is only going to return one row.
$query = "SELECT *FROM votes WHERE vote_type=1 || vote_type=0";
$result = mysql_query($query);
$row = mysql_fetch_assoc($result);
$WhereVoteIsOne=$row['vote_type'];
foreach ($WhereVoteIsOne as $votesCount) { echo $votesCount."<br/>";}
Sorry that my english isn't the best.
Is it possible to do a "where" in "order by".
Example :
ORDER BY
SUM(points),
SUM(points) WHERE type = 1,
SUM(goal),
SUM(goal) WHERE type = 1
So as first we sort by points.
If anyone has the same number of SUM(points), then we sort by SUM(points) where type = 1.
If anyone has the same number of SUM(points) and the same number of SUM(points) where type = 1, then we sort after SUM(goal).
If anyone has the same in all 3, then it have to sort by SUM(goal) where type = 1.
SUM(CASE WHEN type=1 THEN points ELSE 0 END)
etc.
you should of course add DESC on all order conditions, if you want the "best" first ;)
And the sqlFiddle
ORDER BY
SUM(points),
SUM(CASE WHEN type = 1 THEN points ELSE 0 END),
SUM(goal),
SUM(CASE WHEN type = 1 THEN goal ELSE 0 END)
I have a table
id, location, status
1, london, 1
2, london, 0
3, boston, 1
4, boston, 1
I'd like my query to generate something like this: -
location, status_1, status_0
london, 1, 1
boston, 2, 0
so far I have: -
select count(id) as freq, location from my_table
group by location order by freq desc;
I'm completely lost as to where to go from here.
That sort of transformation is better done in whatever client is issuing the query, but if you have to do it in the database, then
select location,
sum(status = 1) AS status_1,
sum(status = 0) AS status_0
from my_table
group by location
it's a bit hackish, but the 'status = 1' when status really is 1 will evaluate to a boolean true, which MySQL will politely cast to an integer '1', which then gets summed up. Same goes for when status is 0 and status = 0 evaluates to true.
So you want to count the records for each status per city?
In the query below, I group by location (like your did), and then add a sum for each state. Inside the sum is a case, that either returns 1 if the record matches the desired state, or 0 otherwise. That way, you effectively count the number of records for each state per location.
select
a.location,
sum(case when a.status = 1 then 1 else 0 end) as status_1,
sum(case when a.status = 0 then 1 else 0 end) as status_0
from
YourTable a
group by
a.location
select location,
sum(case when status = 1 then 1 else 0 end) as status_1,
sum(case when status = 0 then 1 else 0 end) as status_0,
from my_table
group by location;