SQL JOIN with condition on second table with sequelizejs - mysql

Question

I have the following models:
const User = sequelize.define('user', {
name: Sequelize.TEXT,
avatar: Sequelize.TEXT,
});
const Event = sequelize.define('event', {
title: Sequelize.STRING,
description: Sequelize.TEXT,
timestamp: Sequelize.DATE,
});
const EventUser = sequelize.define('event_user', {});
Event.hasMany(EventUser);
EventUser.belongsTo(User);
So EventUser holds my list of participants for a specific event.
I'm trying to query for all events where user X is participating:
let events = await Event.findAll({
include: [
{model: EventUser, include: [{model: User, where: {id: 1}}]}
],
});
But it won't fetch the list of other participants for that event. Not sure how to achieve that, thanks!

Answer 1

Right way is to define many-to-many relation between Users and Events
User.belongsToMany(Event, {through: 'EventUser'});
Event.belongsToMany(User, {through: 'EventUser'});
Then, you can get all events of some user like this:
User.findById(userId).then(function(user){
return user.getEvents();
}).then(function(events){
//here's events
});
Or through one query:
Event.findAll({
include: [{
model: User,
where: {id: userId}
}]
}).then(function(events){
//here's events
});