I'm using MySQL and MSSql and I'm trying to join these two queries together.
Query 1
(SELECT REP.REP_NUM, REP.FIRST_NAME, REP.LAST_NAME
FROM REP, CUSTOMER)
Query 2
(SELECT CUSTOMER.REP_NUM, SUM(CUSTOMER.BALANCE) AS REP_BALANCE
FROM CUSTOMER
GROUP BY CUSTOMER.REP_NUM)
I've seen you can treat these as two Tables and join them but I'm having trouble getting it to work. The way I was trying to join them I'd get aggregate errors from trying to select the rep first and last name while using the balance sum.
Thanks in advance!
SELECT R.REP_NUM, R.FIRST_NAME, R.LAST_NAME
FROM REP r
inner join
(SELECT c.REP_NUM, SUM(c.BALANCE) AS REP_BALANCE
FROM CUSTOMER c
GROUP BY c.REP_NUM) t
on r.rep_num = t.rep_num
SELECT r.REP_NUM, r.FIRST_NAME, r.LAST_NAME, SUM (c.BALANCE) AS REP_BALANCE
FROM REP r
INNER JOIN CUSTOMER c ON r.REP_NUM = c.REP_NUM
GROUP BY r.REP_NUM, r.FIRST_NAME, r.LAST_NAME
try this:
SELECT REP.REP_NUM, REP.FIRST_NAME, REP.LAST_NAME
FROM REP join(
SELECT CUSTOMER.REP_NUM, SUM(CUSTOMER.BALANCE) AS REP_BALANCE
FROM CUSTOMER
GROUP BY CUSTOMER.REP_NUM
) as B on some_condition...
try it
select a.REP_NUM,a.FIRST_NAME,a.LAST_NAME,b.REP_NUM,Sum(b.BALANCE) as REP_BALANCE from REP a as inner join CUSTOMER b on a.REP_NUM=b.REP_NUM group by b.REP_NUM
Select New.REP_NUM,New.FIRST_NAME,New.LAST_NAME,CUSTOMER.REP_NUM,
SUM(CUSTOMER.BALANCE) AS REP_BALANCE
from (SELECT REP.REP_NUM, REP.FIRST_NAME, REP.LAST_NAME
FROM REP, CUSTOMER) New
inner join CUSTOMER ON CUSTOMER.REP_NUM=New.REP_NUM
GROUP BY CUSTOMER.REP_NUM
Related
I have 2 query:
SELECT CustomerID,count(b.BookingStatus) as 'NotComplete'
FROM Booking b, Customer c
WHERE c.CustomerID=b.BookingCustomerID
AND(b.BookingStatus='Pending'
OR b.BookingStatus='OTW')
GROUP BY c.CustomerID
SELECT c.CustomerID, r.*
FROM Customer c,Regular r
WHERE c.CustomerID=r.RegularCID
Result:
1st query
2nd query
How to combine these 2 result together?
also, display the zero(count) as well.
Thanks!
this is what I get after few hours of trying..obviously it's not what I want..
SELECT c.CustomerID,count(b.BookingStatus) as 'NotComplete',r.RegularID
FROM Booking b, Customer c
JOIN Regular r on r.RegularCID=c.CustomerID
WHERE c.CustomerID=b.BookingCustomerID
AND (b.BookingStatus='Pending'
or b.BookingStatus='OTW'
or b.BookingStatus='Started'
or b.BookingStatus='Unclaimed'
or b.BookingStatus='Confirmed')
GROUP by r.RegularID
You can JOIN to the Regular table and then LEFT JOIN to a derived table of counts in the Booking table. We do it this way to avoid having to GROUP BY all the columns in the Regular table:
SELECT c.CustomerID, r.*, b.NotComplete
FROM Customer c
JOIN Regular r ON r.RegularCID = c.CustomerID
LEFT JOIN (SELECT BookingCustomerID, COUNT(*) AS NotComplete
FROM Booking
WHERE BookingStatus IN ('Pending', 'OTW', 'Started', 'Unclaimed', 'Confirmed')
GROUP BY BookingCustomerID) b ON b.BookingCustomerID = c.CustomerID
Use join on regular table, and subquery on your first select
SELECT t1.*, r.RegularCID FROM (
SELECT CustomerID,count(b.BookingStatus) as 'NotComplete',
FROM Booking b
INNER JOIN Customer c ON c.CustomerID=b.BookingCustomerID
WHERE (b.BookingStatus='Pending' OR b.BookingStatus='OTW')
GROUP BY c.CustomerID) t1
LEFT JOIN Regular r on r.CustomerID = t1.CustomerID
I want each student's name, last payment date only. means only day.
I know i won't help you at all giving this code:
But you could try to learn something from it.
SELECT S.Id, S.Name, F.max_date, F.FeeAmt
FROM tbl_student As S
INNER JOIN (
SELECT t.Id, MAX(t.Date) As max_date, t.FeeAmt FROM tbl_fees As t GROUP BY t.Id
) As F ON F.Id=S.Id
First we selected all users from tbl_student, and then we are joining fees, selecting max date and grouping by user. The result is last (date) fee per user.
Please try this query. I hope this should give you the expected output:
SELECT S.Name, T1.LastPaymentDate
FROM
(SELECT Id, Max([Date]) AS LastPaymentDate from tbl_fees GROUP BY Id) AS T1
INNER JOIN
tbl_student AS S
ON T1.Id = S.Id
SELECT S.name,SUB.LAST_DATE
FROM tbl_student S
JOIN (SELECT f.id AS ID,MAX(f.Date) AS LAST_DATE
FROM tbl_fees f
GROUP BY f.id) SUB
ON SUB.id = S.id
I have this query
SELECT t.pname,MAX(t.name) ,MAX(t.total)
FROM
(
SELECT p.`id`,e.`name`,p.`pname`,(m.`hour`) AS total
FROM employee e INNER JOIN epmap m ON m.`employeeID`=e.`id` INNER JOIN project p ON p.`id`=m.`projectID`
)t
GROUP BY t.id
it gives the right answer, but its not the good approach beacuse Max(t.name) not appropriate
This will give you the result you need:
SELECT t.pname, t.name, t.hour as total
FROM (
SELECT p.id, e.name, p.pname, m.total,
ROW_NUMBER() OVER(partition by p.id order by m.hour desc) rn
FROM employee e
INNER JOIN epmap m ON m.employeeID=e.id
INNER JOIN project p ON p.id=m.projectID
) t
where t.rn = 1
SELECT DISTINCT would probably let you get rid of the MAX on name.
I have 3 tables:
user(id, name, id_school)
school(id, name)
result(id_user, stage1, stage2)
Now I would like to get school ranking - is sum of 2 columns: stage1 and stage2 of all users.
seems too simple:
select s.name as school, sum(stage1)+sum(stage2) as rank
from result r
join user u on u.id=r.id_user
join school s on s.id=u.id_school
group by s.id
and i really hope you have indexes.
Try this query. It is only assumption.please provide some data for testing
SELECT
s.id,
s.name AS SchoolName
(r.S1 + r.S2) AS Rank
FROM school as s
LEFT JOIN user as u ON u.id_school = s.id
LEFT JOIN (SELECT id_user , SUM(stage1) as S1 , SUM(stage2) FROM result GROUP BY id_user) as r ON r.id_user = u.id
GROUP BY s.id
ORDER BY Rank DESC
I would do something like this:
SELECT school.name, SUM(result.result1 + result.result2)
FROM school LEFT JOIN user ON (user.id_school = school.id) LEFT JOIN result ON (result.id_user = user.id) GROUP BY school.id
Hope it helps, good luck :)
I would like to get the data from one table, and count all results from other table, depending on the first table data, here is what I tried:
SELECT
cars.*, (
SELECT
COUNT(*)
FROM
uploads
WHERE
uploads.cid = cars.customer
) AS `count`,
FROM
`cars`
WHERE
customer = 11;
I dont really have an idea why its not working, as I'm not a regular MySQL user/coder...
Could anyone direct me in the right direction with this one?
SELECT
c.*, COUNT(u.cid) AS count
FROM
cars c
LEFT JOIN
uploads u
ON
u.cid=c.customer
WHERE
u.customer = 11;
GROUP BY c.cid
Try it by joining both tables using LEFT JOIN
SELECT a.customer, COUNT(b.cid) totalCount
FROM cars a
LEFT JOIN uploads b
ON a.customer = b.cid
WHERE a.customer = 11
GROUP BY a.customer
using COUNT(*) in LEFT JOIN will have records to have a minimum count of 1.
SELECT cars.*,COUNT(uploads.*) as uplloaded
from cars
left outer join uploads on uploads.cid = cars.customer
where cars.customer = 11
group by uploads.cid;
Try this :
SELECT customer, COUNT(cid) totalCount
FROM cars
INNER JOIN uploads
ON (customer = cid)
WHERE customer = 11
GROUP BY customer